ÌâÄ¿ÄÚÈÝ
17£®áéÖݽÀÉɽ×÷ΪÕã½Ê¡µÚÒ»¸öÊÀ½çÒŲúÌáÃûµØ£¬Óë¹úÄÚÆäËü5¸öµ¤Ï¼µØÃ²Ò»Æð£¬ÔÚ2010Äê8Ô±»ÕýʽÁÐÈë¡¶ÊÀ½çÒŲúÃû¼¡·£®¡°Öйúµ¤Ï¼¡±ÆäºìɫɰÀùÑÒÓÉʯ»ÒÑÒ¡¢Ê¯¸à£¨CaSO4•2H2O£©¡¢ÇâÑõ»¯ÌúµÈ³É·Ö×é³É£®£¨1£©Ê¯»ÒÑÒÊÇÒ»ÖֱȽϼáÓ²µÄÑÒʯ£¬Ö÷Òª³É·ÖÊÇ̼Ëá¸Æ£®Ì¼Ëá¸ÆÖк¬ÓеÄÑôÀë×ÓÊÇCa2+£¨Óû¯Ñ§·ûºÅ±íʾ£©£®
£¨2£©Ïñʯ¸à£¨CaSO4•2H2O£©ÕâÑùº¬ÓнᾧˮµÄÎïÖʽÐ×ö½á¾§Ë®ºÏÎ×ÔÈ»½çÖÐÐíÎïÖʺ¬½á¾§Ë®£¬ËüÃǵĻ¯Ñ§Ê½ºÍ¶Á·¨ÈçÏ£ºCuSO4•5H2O¶Á×÷¡°ÎåË®ºÏÁòËáÍ¡±¡¢Na2SO4•10H2O¶Á×÷¡°Ê®Ë®ºÏÁòËáÄÆ¡±¡¢MgSO4•7H2O¶Á×÷¡°ÆßË®ºÏÁòËáþ¡±£¬ÒÀ´ËÃüÃû¹æÔò£¬KAl£¨SO4£©2•12H2OÓ¦¶Á×÷Ê®¶þË®ºÏÁòËáÂÁ¼Ø£®
£¨3£©ÑÒʯ³ÊºìÉ«ÊǺ¬ÇâÑõ»¯ÌúËùÖ£®ÇâÑõ»¯ÌúÊÇÒ»ÖÖ²»ÈÜÓÚË®µÄ¼î£¬Ï¡ÁòËá¿ÉÈܽâÇâÑõ»¯Ìú£¬Ï¡ÁòËáÖк¬ÓеÄÁ£×ÓÓÐH+¡¢SO42-¡¢H2O£¨Óû¯Ñ§·ûºÅ±íʾ£©£®
·ÖÎö £¨1£©Ì¼Ëá¸ÆÖк¬ÓеÄÑôÀë×ÓÊǸÆÀë×Ó£¬Ð´³öÆäÀë×Ó·ûºÅ¼´¿É£®
£¨2£©ÓÉÌâÒ⣬½á¾§Ë®ºÏÎïµÄ¶Á·¨ÊÇ£ºCuSO4•5H2O¶Á×÷¡°ÎåË®ºÏÁòËáÍ¡±¡¢Na2SO4•10H2O¶Á×÷¡°Ê®Ë®ºÏÁòËáÄÆ¡±¡¢MgSO4•7H2O¶Á×÷¡°ÆßË®ºÏÁòËáþ¡±£¬¾Ý´Ë½øÐзÖÎö½â´ð£®
£¨3£©Ï¡ÁòËáÊÇÁòËáµÄË®ÈÜÒº£¬ÈÜÖÊÊÇÁòËᣬÈܼÁÊÇË®£¬ÁòËáÊÇÓÉÇâÀë×ÓºÍÁòËá¸ùÀë×Ó¹¹³ÉµÄ£¬Ë®ÊÇÓÉË®·Ö×Ó¹¹³ÉµÄ£¬¾Ý´Ë½øÐзÖÎö½â´ð£®
½â´ð ½â£º£¨1£©Ì¼Ëá¸ÆÖк¬ÓеÄÑôÀë×ÓÊǸÆÀë×Ó£¬ÆäÀë×Ó·ûºÅΪ£ºCa2+£®
£¨2£©ÓÉʾÀýCuSO4•5H2O¶Á×÷¡°ÎåË®ºÏÁòËáÍ¡±¡¢Na2SO4•10H2O¶Á×÷¡°Ê®Ë®ºÏÁòËáÄÆ¡±¡¢MgSO4•7H2O¶Á×÷¡°ÆßË®ºÏÁòËáþ¡±£¬ÔòKAl£¨SO4£©2•12H2OÓ¦¶Á×÷Ê®¶þË®ºÏÁòËáÂÁ¼Ø£®
£¨3£©Ï¡ÁòËáÊÇÁòËáµÄË®ÈÜÒº£¬ÈÜÖÊÊÇÁòËᣬÈܼÁÊÇË®£¬ÁòËáÊÇÓÉÇâÀë×ÓºÍÁòËá¸ùÀë×Ó¹¹³ÉµÄ£¬Ë®ÊÇÓÉË®·Ö×Ó¹¹³ÉµÄ£¬ÔòÏ¡ÁòËáÖк¬ÓеÄÁ£×ÓÓÐH+¡¢SO42-¡¢H2O£®
¹Ê´ð°¸Îª£º£¨1£©Ca2+£»£¨2£©Ê®¶þË®ºÏÁòËáÂÁ¼Ø£»£¨3£©H+¡¢SO42-¡¢H2O£®
µãÆÀ ±¾ÌâÄѶȲ»´ó£¬ÕÆÎÕ³£¼û»¯Ñ§ÓÃÓ·Ö×Ó·ûºÅ¡¢»¯Ñ§Ê½¡¢Àë×Ó·ûºÅµÈ£©µÄÊéд·½·¨ÊÇÕýÈ·½â´ð´ËÀàÌâµÄ¹Ø¼ü£®
| A£® | ½ð¸Õʯ | B£® | ÑõÆø | C£® | ÂÈ»¯ÄÆ | D£® | Í |
£¨1£©Ð´³öͼÖбêºÅÒÇÆ÷µÄÃû³Æ£ºa×¶ÐÎÆ¿£»
£¨2£©ÓÃB×°ÖÃÖÆÈ¡ÆøÌåÓ¦¾ß±¸µÄ·´Ó¦ÎïµÄ״̬ºÍ·´Ó¦Ìõ¼þÊÇ·´Ó¦Îï¾ùΪ¹ÌÌåÇÒ·´Ó¦ÐèÒª¼ÓÈÈ£®
£¨3£©ÊµÑéÊÒÖÆÈ¡²¢ÊÕ¼¯¶þÑõ»¯Ì¼ÆøÌåÑ¡ÔñµÄ×°ÖÃ×éºÏÊÇAD£¬·¢Éú×°ÖÃÖз¢ÉúµÄ»¯Ñ§·´Ó¦·½³ÌʽÊÇCaCO3+2HCl¨TCaCl2+CO2¡ü+H2O£®
£¨4£©¼ìÑé¶þÑõ»¯Ì¼ÊÇ·ñÊÕ¼¯ÂúµÄ·½·¨Êǽ«È¼ÉÕµÄľÌõ·ÅÔÚ¼¯ÆøÆ¿¿Ú£¬ÈôϨÃðÔòÊÕ¼¯Âú£¬ÈôÒªÊÕ¼¯µ½¸ÉÔïµÄ¶þÑõ»¯Ì¼ÆøÌ壬ÔÚF×°ÖÃÖÐÓ¦¼ÓÈëµÄÊÔ¼ÁΪŨÁòËᣨÌîÃû³Æ£©£®
£¨5£©Ä³Í¬Ñ§ÓûÊÕ¼¯Ò»ÖÖÄÑÈÜÐÔÆøÌ壬ÈÏΪF ×°ÖÿÉÒÔ´úÌæC×°Öã®Çë¼òÊö¸ÃͬѧӦÈçºÎʹÓÃF×°Öã¿F×°ÖóäÂúË®ºóÕý·Å£¬ÆøÌåÓÉc¶Ë½øÈ루»òE×°ÖóäÂúË®ºóµ¹·Å£¬ÆøÌåÓÉb¶Ë½øÈ룩£®
ѧÔÚʳƷ°ü×°´üÄÚ£¬·¢ÏÖÓÐÒ»¸öСֽ´ü£¬ÉÏÃæÐ´×Å¡°Éúʯ»Ò¸ÉÔï¼Á£¬ÇëÎðʳÓá±£®ËûËæÊÖ½«Ð¡Ö½´üÄóöÀ´·ÅÔÚ×ÀÃæÉÏ£¬¾¹ýÒ»¶Î½Ï³¤Ê±¼äºó·¢ÏÖÖ½´üÄڵİ×É«¿ÅÁ£Õ³ÔÚÒ»Æð³ÉΪ¿é×´¹ÌÌåM£®ÇëÄãÓëËûÒ»Æð¶Ô¿é×´¹ÌÌåM½øÐÐ̽¾¿£®
¡¾Ì½¾¿ÈÎÎñ¡¿I̽¾¿¹ÌÌåMÊÇ·ñʧЧ£» II̽¾¿¹ÌÌåMÖÐÊÇ·ñº¬ÓÐÇâÑõ»¯¸Æ£®
¡¾Ì½¾¿·½°¸¡¿
| ÎÊÌâÓë²ÂÏë | ʵÑé²½Öè | ʵÑéÏÖÏó | ʵÑé½áÂÛ |
| ̽¾¿Ò»£º¹ÌÌåMÊÇ·ñʧЧ | È¡ÊÊÁ¿¹ÌÌåM£¬¼ÓÈëÊ¢ÓÐË®µÄÉÕ±ÖУ¬ÓÃζȼƲâÁ¿¼ÓÈëǰºóµÄÎÂ¶È | ζÈûÓÐÃ÷ÏÔ ±ä»¯ | ˵Ã÷ûÓÐÑõ»¯¸Æ |
| ̽¾¿¶þ£º¹ÌÌåMÖÐÊÇ·ñº¬ÓÐÇâÑõ»¯¸Æ | ½«ÉÏÊöÉÕ±ÄÚµÄÒºÌå³ä·Ö½Á°è¡¢¾²Öã¬È¡ÉϲãÇåÒº£¬¼ÓÈëÎÞÉ«·Ó̪ÊÔÒº | ·Ó̪ÊÔÒº±äºì | ÓÐÇâÑõ»¯¸Æ |
£¨1£©ÄãÈÏΪ¹ÌÌåMÖгýº¬ÓÐÇâÑõ»¯¸ÆÍ⣬»¹¿ÉÄܺ¬ÓеÄÎïÖÊÊÇ̼Ëá¸Æ£¬Çëд³öÕâÖÖÎïÖÊÓëÑÎËá·´Ó¦µÄ»¯Ñ§·½³ÌʽCaCO3+2HCl=CaCl2+H2O+CO2¡ü£®
£¨2£©Ð´³öÉúʯ»ÒÔÚ¿ÕÆøÖбäÖʵĻ¯Ñ§·½³Ìʽ£ºCaO+H2O=Ca£¨OH£©2¡¢CO2+Ca£¨OH£©2=CaCO3¡ý+H2O£®
¢ÙʹÓÃÎÞÁ×Ï´ÒÂ·Û ¢Ú½ûֹʩÓÃũԼºÍ»¯·Ê ¢ÛÒÖÖÆË®ÖÐËùÓж¯¡¢Ö²ÎïµÄÉú³¤ ¢ÜÉú»îÎÛË®´¦Àí´ï±êºóÔÙÅÅ·Å ¢Ý¹¤Òµ¡°Èý·Ï¡±´¦Àí´ï±êºóÅÅ·Å£®
| A£® | ¢Ù¢Û¢Ý | B£® | ¢Ù¢Ú¢Ü | C£® | ¢Ú¢Ü¢Ý | D£® | ¢Ù¢Ü¢Ý |
| A£® | ¸ÉÔïµÄ¿ÕÆøÖÐ | B£® | ³±ÊªµÄ¿ÕÆøÖÐ | C£® | ½þûÔÚ×ÔÀ´Ë®ÖÐ | D£® | ½þûÔÚÖ²ÎïÓÍÖÐ |