ÌâÄ¿ÄÚÈÝ
11£®Ð¡¾êÏë²â¶¨Cu-ZnºÏ½ðºÍCu-AgºÏ½ðÖÐ͵ÄÖÊÁ¿·ÖÊý£¬ÊµÑéÊÒÖ»ÌṩÁËһƿδ±êÃ÷ÈÜÖÊÖÊÁ¿·ÖÊýµÄÏ¡ÑÎËáºÍ±ØÒªµÄÒÇÆ÷£®£¨1£©ÄãÈÏΪËýÄܲâ³ö͵ÄÖÊÁ¿·ÖÊýµÄºÏ½ðÊÇCu-ZnºÏ½ð£®
£¨2£©ÈôÏë²â³ö¸ÃÑÎËáµÄÈÜÖÊÖÊÁ¿·ÖÊý£¬ÄãÈÏΪʵÑéʱ±ØÐëÌṩºÍ²â³öµÄÊý¾ÝÊÇBC
A¡¢²Î¼Ó·´Ó¦µÄºÏ½ðÖÊÁ¿¡¡¡¡¡¡¡¡¡¡B¡¢²Î¼Ó·´Ó¦µÄÏ¡ÑÎËáÖÊÁ¿
C¡¢Éú³ÉµÄÆøÌåÖÊÁ¿¡¡¡¡¡¡¡¡¡¡¡¡¡¡D¡¢²Î¼Ó·´Ó¦µÄÏ¡ÑÎËáµÄÌå»ýºÍÃܶÈ
£¨3£©Ð¡¾êÈ¡¸ÃºÏ½ðµÄ·ÛÄ©32.5g£¬Óë×ãÁ¿¸ÃÑÎËá³ä·Ö·´Ó¦ºó£¬¾²â¶¨²úÉúÁË0.4gÆøÌ壬ÇëÄã°ïÖúËý¼ÆËã³ö¸ÃºÏ½ðÖÐ͵ÄÖÊÁ¿·ÖÊý£®
·ÖÎö £¨1£©¸ù¾ÝÌṩµÄÒ©Æ·¿ÉÖª±¾ÌâÖÐÒª²â³öµÄºÏ½ðÖеÄÁ½ÖÖ½ðÊô±ØÐëÒ»ÖÖÔÚÇâ֮ǰ£¬Ò»ÖÖÔÚÇâÖ®ºó½øÐзÖÎö£»
£¨2£©ÒªÇó³öÑÎËáÖÐÈÜÖʵÄÖÊÁ¿·ÖÊý±ØÐë²â³ö»òÇó³öÈÜÖʺÍÈÜÒºµÄÖÊÁ¿£¬¶øÈÜÒºµÄÖÊÁ¿ÐèÒª²â³ö£¬ÈÜÖʵÄÖÊÁ¿ÐèÒª¸ù¾ÝÉú³ÉÇâÆøµÄÖÊÁ¿¼ÆËã³öÀ´£»
£¨3£©¸ù¾ÝÇâǰ½ðÊôÓëÑÎËáµÄ·´Ó¦Çó³ö½ðÊôпºÍ½ðÊô͵ÄÖÊÁ¿½ø¶ø¿ÉÇó³öºÏ½ðÖÐ͵ÄÖÊÁ¿·ÖÊý£®
½â´ð ½â£º£¨1£©ÍµÄ»î¶¯ÐÔ±ÈÇâÈõ£¬²»ÓëÏ¡Ëá·¢Éú·´Ó¦£¬Ð¿µÄ»î¶¯ÐÔ±ÈÇâÇ¿£¬ÄÜÓëÏ¡Ëá·¢Éú·´Ó¦£¬Òò¶øÍпºÏ½ðÄܲⶨ³ö͵ÄÖÊÁ¿·ÖÊý£»¶øÒøµÄ»î¶¯ÐÔ±ÈÇâÈõ£¬Ò²²»ÓëÏ¡Ëá·¢Éú·´Ó¦£¬Òò¶øÍÒøºÏ½ð²»Äܲⶨ³ö͵ÄÖÊÁ¿·ÖÊý£»
£¨2£©ÒªÏë²â³ö¸ÃÑÎËáµÄÖÊÁ¿·ÖÊý£¬±ØÐëÖªµÀÑÎËáÖÐÈÜÖʵÄÖÊÁ¿ºÍÈÜÒºµÄÖÊÁ¿£®²Î¼Ó·´Ó¦µÄÑÎËáÖÐÈÜÖʵÄÖÊÁ¿¿ÉÓÉÉú³ÉÇâÆøµÄÖÊÁ¿Í¨¹ý»¯Ñ§·½³Ìʽ¼ÆËã³ö£¬È»ºó£¨ÈÜÖʵÄÖÊÁ¿¡ÂÏ¡ÑÎËáµÄÖÊÁ¿£©¡Á100%¼´Îª¸ÃÑÎËáµÄÖÊÁ¿·ÖÊý£»¶ø²Î¼Ó·´Ó¦µÄºÏ½ðµÄÖÊÁ¿ÊÇ»ìºÏÎïµÄÖÊÁ¿£¬½øÐмÆËãʱ²»ÄÜÖ±½ÓʹÓã¬ÊµÑéʱ±ØÐë²â³ö²Î¼Ó·´Ó¦µÄÏ¡ÑÎËáµÄÖÊÁ¿ºÍÉú³ÉÇâÆøµÄÖÊÁ¿£¬¹ÊÑ¡£ºBC»òCD£»
£¨3£©É裺ºÏ½ðÖÐпµÄÖÊÁ¿Îªx
Zn+2HCl=ZnCl2+H2¡ü
65 2
x 0.4g
$\frac{65}{x}$$\frac{2}{0.4g}$
x=13g
ºÏ½ðÖÐ͵ÄÖÊÁ¿Îª£º32.5g-13g=19.5g
ºÏ½ðÖÐ͵ÄÖÊÁ¿·ÖÊýΪ£º$\frac{19.5g}{32.5g}$¡Á100%=60%£®
´ð£ººÏ½ðÖÐ͵ÄÖÊÁ¿·ÖÊýΪ60%£®
¹Ê´ð°¸Îª£º£¨1£©Cu-Zn£»
£¨2£©BC£»
£¨3£©60%£®
µãÆÀ ±¾Ì⿼²é½ðÊô»î¶¯ÐÔ˳Ðò¼°ÆäÓ¦Óã¬Í¬Ê±¿¼²é¸ù¾Ý»¯Ñ§·½³ÌʽµÄ¼ÆË㣬»¹´Ó²»Í¬½Ç¶È¿¼²éѧÉú·ÖÎöÎÊÌâµÄÄÜÁ¦£®
| A£® | NaNO3+KCl=NaCl+KNO3 | B£® | Na2CO3+2HCl=2NaCl+H2O+CO2¡ü | ||
| C£® | BaCl2+H2SO4=BaSO4¡ý+2HCl | D£® | 2HNO3+Ca£¨OH£©2=Ca£¨NO3£©2+2H2O |
| A£® | ÓÃÕôÁóˮϴ | B£® | ÓÃÏ¡ÑÎËáÏ´ | ||
| C£® | ÓÃÏ¡ÑÎËáÏ´£¬ÔÙÓÃË®³åÏ´ | D£® | ÓÃNaOHÈÜҺϴ |
| A£® | ¸ÃÎïÖÊÊÇÈÝÒ×»Ó·¢µÄÓлúÈܼÁ | |
| B£® | ¸ÃÎïÖʾßÓÐÄ͸ßεÄÐÔÄÜ | |
| C£® | ¸ÃÎïÖÊÖк¬·úµÄÖÊÁ¿·ÖÊýÊÇ76% | |
| D£® | ¸ÃÎïÖÊÊÇÒ»ÖÖ»¯Ñ§Îȶ¨ÐÔºÜÇ¿µÄÓлú»¯ºÏÎï |