题目内容
计算下列各题,要写出主要计算过程,能用简便方法的要用简便方法计算.
①3000-45×36
②3.9+3.9×99
③20.5÷(8.5-0.3)
④
-
+
⑤
-
+
-
⑥1005÷[42×(
-
)].
①3000-45×36
②3.9+3.9×99
③20.5÷(8.5-0.3)
④
4 |
5 |
2 |
3 |
1 |
6 |
⑤
5 |
9 |
3 |
11 |
4 |
9 |
7 |
11 |
⑥1005÷[42×(
5 |
6 |
5 |
7 |
分析:①可将36拆分为4×9计算;
②⑥可根据乘法分配律计算;
③先算括号中的减法,再算除法;
④按从左到右的顺序计算即可;
⑤可根据加法交换律及一个数减两个数,等于减去这两个数的和的减法性质计算.
②⑥可根据乘法分配律计算;
③先算括号中的减法,再算除法;
④按从左到右的顺序计算即可;
⑤可根据加法交换律及一个数减两个数,等于减去这两个数的和的减法性质计算.
解答:解:①3000-45×36
=3000-45×4×9,
=3000-180×9,
=3000-1620,
=1380;
②3.9+3.9×99
=(1+99)×3.9,
=100×3.9,
=390;
③20.5÷(8.5-0.3)
=20.5÷8.2,
=2.5;
④
-
+
=
+
,
=
;
⑤
-
+
-
=
+
-(
+
),
=1-1,
=0;
⑥1005÷[42×(
-
)]
=1005÷[42×
-42×
],
=1005÷[35-30],
=1005÷5,
=201.
=3000-45×4×9,
=3000-180×9,
=3000-1620,
=1380;
②3.9+3.9×99
=(1+99)×3.9,
=100×3.9,
=390;
③20.5÷(8.5-0.3)
=20.5÷8.2,
=2.5;
④
4 |
5 |
2 |
3 |
1 |
6 |
=
2 |
15 |
1 |
6 |
=
3 |
10 |
⑤
5 |
9 |
3 |
11 |
4 |
9 |
7 |
11 |
=
5 |
9 |
4 |
9 |
3 |
11 |
7 |
11 |
=1-1,
=0;
⑥1005÷[42×(
5 |
6 |
5 |
7 |
=1005÷[42×
5 |
6 |
5 |
7 |
=1005÷[35-30],
=1005÷5,
=201.
点评:完成此类题目要注意分析式中数据的特点及内在联系,然后运用合适的方法计算.
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