9. 乙题:

解:(1)因为反比例函数的图象经过点

,················································································································ 2分

.····················································································································· 3分

所以反比例函数的解析式为,············································································· 4分

(2)当为一、三象限角平分线与反比例函数图像的交点时,

线段最短.············································································································ 5分

代入,解得,即.····················· 6分

,··········································································································· 7分

,··········································································································· 8分

为反比例函数图像上的任意两点,

由图象特点知,线段无最大值,即.·················································· 9分

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