摘要:14.设F为抛物线A.B.C为该抛物线上三点.若.则= .
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设F为抛物线y2=2px(p>0)的焦点,A、B、C为该抛物线上三点,当
+
+
=
且|FA|+|FB|+|FC|=3时,此抛物线的方程为( )
FA |
FB |
FC |
0 |
A、y2=2x |
B、y2=4x |
C、y2=6x |
D、y2=8x |
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FA |
FB |
FC |
0 |
A、y2=2x |
B、y2=4x |
C、y2=6x |
D、y2=8x |