题目内容
一长直杆长1.5 m,垂直立于底部平坦、水面平静无波的游泳池中,露出水面部分高0.3 m,当阳光以与水面成37°的夹角入射时,杆在游泳池底部所成的影长为多少?(已知水的折射率n=
.)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003640569373.png)
1.3 m
依题意作图如图所示,依据折射定律n=
,得sin r=
=
=
,r=37°,
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/201408250036406623482.jpg)
影长s=0.3×tan 53° m+1.2×tan 37° m=0.3×
m+1.2×
m=1.3 m.
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003640584541.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003640615485.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003640631722.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003640647369.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/201408250036406623482.jpg)
影长s=0.3×tan 53° m+1.2×tan 37° m=0.3×
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003640569373.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003640709385.png)
![](http://thumb2018.1010pic.com/images/loading.gif)
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