ÌâÄ¿ÄÚÈÝ
2£®ÓÃÈçͼ1ËùʾµÄʵÑé×°ÖÃÑéÖ¤»úеÄÜÊغ㶨ÂÉ£®ÊµÑéËùÓõĵçԴΪѧÉúµçÔ´£¬Êä³öµçѹΪ6VµÄ½»Á÷µçºÍÖ±Á÷µçÁ½ÖÖ£®ÖØ´¸´Ó¸ß´¦Óɾ²Ö¹¿ªÊ¼ÂäÏ£¬ÖØ´¸ÉÏÍÏ×ŵÄÖ½´øͨ¹ý´òµã¼ÆʱÆ÷´ò³öһϵÁеĵ㣬¶ÔÖ½´øÉϵĵ㼣½øÐвâÁ¿£¬ÒÑÖªÖØÁ¦¼ÓËÙ¶ÈΪg£¬¼´¿ÉÑéÖ¤»úеÄÜÊغ㶨ÂÉ£®¢ÙÏÂÃæÁоÙÁ˸ÃʵÑéµÄ¼¸¸ö²Ù×÷²½Ö裺
A£®°´ÕÕͼʾµÄ×°Öð²×°Æ÷¼þ£»
B£®½«´òµã¼ÆʱÆ÷½Óµ½µçÔ´µÄÖ±Á÷Êä³ö¶ËÉÏ£»
C£®ÓÃÌìƽ²âÁ¿³öÖØ´¸µÄÖÊÁ¿£»
D£®ÏÈÊÍ·ÅÐü¹ÒÖ½´øµÄ¼Ð×Ó£¬È»ºó½ÓͨµçÔ´¿ª¹Ø´ò³öÒ»ÌõÖ½´ø£»
E£®²âÁ¿´ò³öµÄÖ½´øÉÏijЩµãÖ®¼äµÄ¾àÀ룻
F£®¸ù¾Ý²âÁ¿µÄ½á¹û¼ÆËãÖØ´¸ÏÂÂä¹ý³ÌÖмõÉÙ
µÄÖØÁ¦ÊÆÄÜÔÚÎó²î·¶Î§ÄÚÊÇ·ñµÈÓÚÔö¼ÓµÄ¶¯ÄÜ£®
ÆäÖÐûÓбØÒª»ò²Ù×÷²»Ç¡µ±µÄ²½ÖèÊÇBCD£¨ÌîдѡÏî¶ÔÓ¦µÄ×Öĸ£©
¢ÚÈçͼ2ËùʾÊÇʵÑéÖеõ½Ò»ÌõÖ½´ø£¬½«Æðʼµã¼ÇΪO£¬²¢ÔÚÀëOµã½ÏÔ¶µÄÈÎÒâµãÒÀ´ÎÑ¡È¡6¸öÁ¬ÐøµÄµã£¬·Ö±ð¼ÇΪA¡¢B¡¢C¡¢D¡¢E¡¢F£¬Á¿³öÓëOµãµÄ¾àÀë·Ö±ðΪh1¡¢h2¡¢h3¡¢h4¡¢h5¡¢h6£¬Ê¹Óý»Á÷µçµÄÖÜÆÚΪT£¬ÉèÖØ´¸ÖÊÁ¿Îªm£¬ÔòÔÚ´òEµãʱÖØ´¸µÄ¶¯ÄÜΪ$\frac{{m{{£¨{h_6}-{h_4}£©}^2}}}{{8{T^2}}}$£¬ÔÚ´òOµãºÍEµãÕâ¶Îʱ¼äÄÚµÄÖØÁ¦ÊÆÄܵļõÉÙÁ¿Îªmgh5£®
¢ÛÔÚ±¾ÊµÑéÖз¢ÏÖ£¬ÖØ´¸¼õÉÙµÄÖØÁ¦ÊÆÄÜ×ÜÊÇ´óÓÚ£¨Ìî¡°´óÓÚ¡±»ò¡°Ð¡ÓÚ¡±£©ÖØ´¸Ôö¼ÓµÄ¶¯ÄÜ£¬Ö÷ÒªÊÇÒòΪÔÚÖØ´¸ÏÂÂä¹ý³ÌÖдæÔÚ×Å×èÁ¦µÄ×÷Óã¬ÎªÁ˲ⶨ×èÁ¦´óС£¬¿ÉËã³ö¢ÚÎÊÖÐÖ½´ø¸÷µã¶ÔÓ¦µÄËٶȣ¬·Ö±ð¼ÇΪv1ÖÁv6£¬²¢×÷vn2-hnͼÏó£¬Èçͼ3Ëùʾ£¬Ö±ÏßбÂÊΪk£¬Ôò¿É²â³ö×èÁ¦´óСΪ$m£¨g-\frac{k}{2}£©$£®
·ÖÎö ¢Ù¸ù¾ÝʵÑéµÄÔÀíÒÔ¼°²Ù×÷ÖеÄ×¢ÒâÊÂÏîÈ·¶¨´íÎóµÄ²Ù×÷²½ÖèÒÔ¼°²»±ØÒªµÄ²½Ö裮
¢Ú¸ù¾Ýij¶Îʱ¼äÄÚµÄƽ¾ùËٶȵÈÓÚÖмäʱ¿ÌµÄ˲ʱËÙ¶ÈÇó³öEµãµÄËٶȣ¬´Ó¶øµÃ³ö¶¯ÄܵÄÔö¼ÓÁ¿£¬¸ù¾ÝϽµµÄ¸ß¶ÈÇó³öÖØÁ¦ÊÆÄܵļõСÁ¿£®
¢ÛÓÉÓÚ×èÁ¦µÄ´æÔÚ£¬ÖØÁ¦ÊÆÄܵļõСÁ¿´óÓÚ¶¯ÄܵÄÔö¼ÓÁ¿£¬¸ù¾ÝͼÏßµÄбÂÊÇó³ö¼ÓËٶȣ¬½áºÏÅ£¶ÙµÚ¶þ¶¨ÂÉÇó³ö×èÁ¦µÄ´óС£®
½â´ð ½â£º¢Ù´òµã¼ÆʱÆ÷Ó¦½ÓÔÚµçÔ´µÄ½»Á÷Êä³öÉÏ£¬¹ÊB´íÎó£®
ʵÑéÖÐÑéÖ¤¶¯ÄܵÄÔö¼ÓÁ¿ºÍÖØÁ¦ÊÆÄܵļõСÁ¿ÊÇ·ñÏàµÈ£¬ÖÊÁ¿¿ÉÒÔԼȥ£¬²»ÐèÒªÓÃÌìƽ²âÁ¿ÖØ´¸µÄÖÊÁ¿£¬¹ÊC²»±ØÒª£®
ʵÑéʱӦÏȽÓͨµçÔ´£¬ÔÙÊÍ·ÅÖØÎ¹ÊD´íÎó£®
±¾ÌâѡûÓбØÒª»ò²Ù×÷²»Ç¡µ±µÄ£¬¹ÊÑ¡£ºBCD£®
¢ÚEµãµÄ˲ʱËÙ¶ÈΪ£º${v}_{E}=\frac{{h}_{6}-{h}_{4}}{2T}$£¬ÔòEµãÖØ´¸µÄ¶¯ÄÜΪ£º${E}_{k}=\frac{1}{2}m{{v}_{E}}^{2}$=$\frac{{m{{£¨{h_6}-{h_4}£©}^2}}}{{8{T^2}}}$£¬ÔÚ´òOµãºÍEµãÕâ¶Îʱ¼äÄÚµÄÖØÁ¦ÊÆÄܵļõÉÙÁ¿Îª£º¡÷Ep=mgh5£®
¢ÛÓÉÓÚ×èÁ¦µÄ´æÔÚ£¬ÖØ´¸¼õÉÙµÄÖØÁ¦ÊÆÄÜ´óÓÚ¶¯ÄܵÄÔö¼ÓÁ¿£®
¸ù¾Ýv2=2ahµÃ£¬Í¼ÏßµÄбÂÊk=2a£¬Ôòa=$\frac{k}{2}$£¬¸ù¾ÝÅ£¶ÙµÚ¶þ¶¨Âɵãºmg-f=ma£¬½âµÃ×èÁ¦Îª£ºf=mg-ma=$m£¨g-\frac{k}{2}£©$£®
¹Ê´ð°¸Îª£º¢ÙBCD£»¢Ú$\frac{{m{{£¨{h_6}-{h_4}£©}^2}}}{{8{T^2}}}$£¬mgh5 £»¢Û´óÓÚ£¬$m£¨g-\frac{k}{2}£©$£®
µãÆÀ ÒªÖªµÀÖØÎï´ø¶¯Ö½´øÏÂÂä¹ý³ÌÖÐÄÜÁ¿×ª»¯µÄ¹ý³ÌºÍÄÜÁ¿Êغ㣬ÊìÁ·Ó¦ÓÃÔȱäËÙÖ±ÏßÔ˶¯¹æÂɽâ¾öʵÑéÎÊÌ⣻ÖØÎï´ø¶¯Ö½´øÏÂÂä¹ý³ÌÖУ¬³ýÁËÖØÁ¦»¹Êܵ½×èÁ¦£¬´ÓÄÜÁ¿×ª»¯µÄ½Ç¶È£¬ÓÉÓÚ×èÁ¦×ö¹¦£¬ÖØÁ¦ÊÆÄܼõС³ýÁËת»¯¸øÁ˶¯ÄÜ»¹ÓÐÒ»²¿·Öת»¯¸øĦ²Á²úÉúµÄÄÚÄÜ£®
A£® | Óÿɲð±äѹÆ÷£¬ÄÜ·½±ãµØ´Ó²»Í¬½ÓÏßÖùÉÏÑ¡È¡²»Í¬ÔÑÊýµÄÏßȦ | |
B£® | ²âÁ¿Ô¡¢¸±ÏßȦµÄµçѹ£¬¿ÉÓᰲⶨµç³ØµÄµç¶¯ÊƺÍÄÚ×衱ʵÑéÖеÄÖ±Á÷µçѹ±í | |
C£® | ÔÏßȦ½Ó0¡¢8½ÓÏßÖù£¬¸±ÏßȦ½Ó0¡¢4½ÓÏßÖù£¬¸±ÏßȦµçѹ´óÓÚÔÏßȦµçѹ | |
D£® | Ϊ±ãÓÚ̽¾¿£¬Ïȱ£³ÖÔÏßȦÔÑÊýºÍµçѹ²»±ä£¬¸Ä±ä¸±ÏßȦµÄÔÑÊý£¬Ñо¿Æä¶Ô¸±ÏßȦµçѹµÄÓ°Ïì |