题目内容
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241147192303461.gif)
求:①卫星在绕地球轨道运行时离地面600km时的加速度.
②卫星从离开地球轨道进入地月转移轨道最终稳定在离月球表面200km的工作轨道上外力对它做了多少功?(忽略地球自转及月球绕地球公转的影响)
(1)8 m/s2(2)-1×1011J
①卫星在离地600km处对卫星加速度为a,由牛顿第二定律
又由
可得a="8" m/s2
(2)
卫星离月面200km速度为v,由牛顿第二定律得:
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824114719292876.gif)
由
及M月/M="1/81"
得:V2=2.53×106km2/s2
由动能定理,对卫星 W=
mv2—
mv02
=
× 2350×(253×104—110002)=-1×1011J
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824114719245708.gif)
又由
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824114719261590.gif)
可得a="8" m/s2
(2)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/2014082411471927673.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824114719292876.gif)
由
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824114719261590.gif)
得:V2=2.53×106km2/s2
由动能定理,对卫星 W=
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824114719323225.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824114719323225.gif)
=
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824114719323225.gif)
![](http://thumb2018.1010pic.com/images/loading.gif)
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