题目内容
已知电子运动的轨道半径大于
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824115456607204.gif)
(1)电子从
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824115456622209.gif)
(2)若圆形磁场区域的圆心
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824115456638219.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824115456622209.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241154566694374.jpg)
(1)
(2)![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241154567001094.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824115456685573.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241154567001094.gif)
(1)由
得
(3分)
由
(
为电子圆轨道半径) (3分)
得
(3分)
(3分)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241154567946659.jpg)
(2)由图可知:
(3分)
圆轨道对应的弦越长,圆心角越大,即偏转角越大。当弦长为圆形磁场的直径时.电子射出磁场区域时的偏转角最大为
(3分)
由图可知:
(2分)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824115456716535.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824115456685573.gif)
由
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824115456747556.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824115456747123.gif)
得
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824115456778795.gif)
(3分)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241154567946659.jpg)
(2)由图可知:
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824115456810509.gif)
圆轨道对应的弦越长,圆心角越大,即偏转角越大。当弦长为圆形磁场的直径时.电子射出磁场区域时的偏转角最大为
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824115456825357.gif)
由图可知:
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241154567001094.gif)
![](http://thumb2018.1010pic.com/images/loading.gif)
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