ÌâÄ¿ÄÚÈÝ
Èçͼ£¬Ò»Õý·½ÐÎÇøÓòabcdÄÚÓд¹Ö±ÓÚÖ½ÃæÏòÀïµÄÔÈÇ¿´Å³¡£¬Õý·½Ðα߳¤0.20m£¬ÓÐÒ»´øµçÁ£×Ó´Óab±ßµÄÖеãe´¦ÑØÖ½Ãæ´¹Ö±ÓÚab¡¢ÒÔv0=1.0¡Ám/sµÄËÙ¶ÈÉäÈë´Å³¡£¬´øµçÁ£×ÓÖÊÁ¿m=2.0¡Ákg£¬Ëù´øµçÁ¿q=-8.0¡ÁC£¬Á£×ÓÇ¡´Óc´¦Éä³ö´Å³¡£¬Çó¸Ã´Å³¡µÄ´Å¸ÐÇ¿¶È£®ÈôÔÚ¸ÃÇøÓòÔÙƽÐÐÓÚab¼ÓÒ»Ïò×óµÄÔÈÇ¿µç³¡£¬µç³¡Ç¿¶ÈE=5.0¡ÁV/m£¬ÉÏÊö´Óe´¦ÉäÈëµÄÁ£×Óµ±À뿪¸ÃÇøÓòʱ£¬ËÙ¶ÈÓжà´ó?(Á£×ÓÖØÁ¦ºöÂÔ²»¼Æ)
£¨1£© £¨2£©
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿