ÌâÄ¿ÄÚÈÝ

15£®Èçͼ¼×Ëùʾ£¬ÓÃˮƽºãÁ¦FÀ­¶¯Ë®Æ½ÃæÉϵÄľ°å£¬¿ÉÒÔʹÆä×öÔȼÓËÙÖ±ÏßÔ˶¯£¬µ±¸Ä±äÀ­Á¦µÄ´óСʱ£¬Ïà¶ÔÓ¦µÄÔȼÓËÙÔ˶¯µÄ¼ÓËÙ¶ÈÒ²»á±ä»¯£¬aºÍFµÄ¹ØϵÈçͼÒÒËùʾ£¬gÈ¡10m/s2£¬Éè×î´ó¾²Ä¦²ÁÁ¦µÈÓÚ»¬¶¯Ä¦²ÁÁ¦£®

£¨1£©¸Ãľ°åµÄÖÊÁ¿ÊǶà´ó£¿
£¨2£©¸Ãľ°åºÍˮƽÃæ¼äµÄ¶¯Ä¦²ÁÒòÊý¶à´ó£¿
£¨3£©Èç¹ûÓÃF=5NµÄÀ­Á¦À­Ä¾°å£¬×÷ÓÃ2sºó³·È¥£¬Ä¾°å×îºóÍ£ÔÚˮƽÃæÉÏ£¬Çóľ°åÔ˶¯µÄ×ÜλÒÆ£®

·ÖÎö £¨1£©¸ù¾ÝÅ£¶ÙµÚ¶þ¶¨ÂÉÁÐʽ£¬µÃµ½aÓëFµÄ¹Øϵʽ£¬½áºÏͼÏóµÄÐÅÏ¢£¬Çó½âÎïÌåµÄÖÊÁ¿£®
£¨2£©ÓÉͼÏóµÃµ½Ä¦²ÁÁ¦fµÄ´óС£¬ÓÉf=¦ÌmgÇó¶¯Ä¦²ÁÒòÊý

½â´ð ½â£º£¨1£©¸ù¾ÝÅ£¶ÙµÚ¶þ¶¨ÂɵãºF-f=ma£¬
ÔòµÃ£ºa=$\frac{F-f}{m}$
ÓÉÊýѧ֪ʶµÃ£ºÍ¼ÏóµÄбÂÊΪ£ºk=$\frac{1}{m}$£¬
ÓÉͼ֪k=2
¹ÊµÃ£ºm=0.5kg£®
£¨2£©ÓÉf=¦Ìmg£¬ÓÉͼ2Öª£¬f=1N
´úÈëµÃµ½£º¦Ì=$\frac{f}{mg}$=$\frac{1}{5}$=0.2
£¨3£©Èç¹ûF=5N£¬¼ÓËÙ¶ÈΪ£ºa=8m/s2
2sÄÚλÒÆΪ£ºx1=$\frac{1}{2}a{t}^{2}$=$\frac{1}{2}¡Á8¡Á{2}^{2}$m=16m
ËÙ¶ÈΪ£ºv1=at=8¡Á2=16m/s
³·È¥F£¬¼ÓËÙ¶ÈΪ£ºa¡ä=$\frac{f}{m}$=$\frac{1}{0.5}$=2m/s2
ֹͣʱĩËÙ¶ÈΪÁ㣬ÓУºv2$-{v}_{0}^{2}$=2ax2
µØ£ºx2=$\frac{1{6}^{2}}{2¡Á2}$m=64m
¹Ê×ÜλÒÆΪ£ºx=x1+x2=80m
´ð£º£¨1£©¸ÃÎïÌåµÄÖÊÁ¿ÊÇ0.5kg£®
£¨2£©Îï¿éÓëˮƽÃæ¼äµÄ¶¯Ä¦²ÁÒòÊýÊÇ0.2£»
£¨3£©Èç¹ûÓÃF=5NµÄÀ­Á¦À­Ä¾°å£¬×÷ÓÃ2sºó³·È¥£¬Ä¾°å×îºóÍ£ÔÚˮƽÃæÉÏ£¬Ä¾°åÔ˶¯µÄ×ÜλÒÆΪ80m£®

µãÆÀ ±¾ÌâÊÇÓ¦ÓÃÅ£¶ÙÔ˶¯¶¨ÂÉÇó½âµÄͼÏóÀàÎÊÌ⣬´ËÀàÎÊÌâÇó½âµÄ¹Ø¼üÊÇ£¬Òª¸ù¾ÝͼÏóµÄÌص㣬°ÑÊýѧͼÏóÓëÎïÀí½áºÏÆðÀ´½øÐÐÑо¿£¬Ö÷ÒªµÄÊÇÑо¿Ö±ÏßµÄбÂʺͽؾ࣮

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø