题目内容
三个人造地球卫星A、B、C在地球的大气层外沿如图4所示的方向做匀速圆周运动,已知mA=mB<mC,则三个卫星( )
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241240143972244.png)
A.线速度大小的关系是vA>vB=vC
B.周期关系是TA<TB=TC
C.向心力大小的关系是FA=FB<FC
D.轨道半径和周期的关系是
=
=![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824124014662582.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241240143972244.png)
A.线速度大小的关系是vA>vB=vC
B.周期关系是TA<TB=TC
C.向心力大小的关系是FA=FB<FC
D.轨道半径和周期的关系是
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824124014428584.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824124014646594.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824124014662582.png)
ABD
本题考查人造卫星、万有引力定律
根据卫星受到的万有引力提供向心力得:
得:
A、线速度
线速度跟半径的平方根成反比,因为RA<RB=RC所以A正确;
B、周期
, 知周期跟半径的3次方的平方根成正比,已知半径RA<RB=RC所以B正确;
C、向心力F向=
和RA<RB=RC以及mA=mB<mC,可得C错误;
D、轨道半径的关系
,故有
=
=
,即D正确.故选ABD.
根据卫星受到的万有引力提供向心力得:
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241240146931566.png)
A、线速度
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824124014818744.png)
B、周期
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824124014865949.png)
C、向心力F向=
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824124014912650.png)
D、轨道半径的关系
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824124014943926.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824124014428584.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824124014646594.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824124014662582.png)
![](http://thumb2018.1010pic.com/images/loading.gif)
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