题目内容
如图,四棱锥P-ABCD的底面为正方形,侧面PAD是正三角形,且侧面PAD⊥底面ABCD,
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(I) 求证:平面PAD⊥平面PCD
(II)求二面角A-PC-D的余弦值.
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(I) 求证:平面PAD⊥平面PCD
(II)求二面角A-PC-D的余弦值.
(1)对于面面垂直的证明,要通过线面垂直的证明来分析得到,关键是证明
(2)
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(2)
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试题分析:解:(I) 证:
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(II)解:取PD的中点E,过E作EG⊥PC,垂足为G,连AG, AE
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由△PAD为正三角形得 AE⊥PD
又平面PAD⊥平面 PCD
∴ AE⊥平面PCD
∴ AG⊥PC
∴ ∠AGE是二面角A-PC-D的平面角.
设底面正方形边长为2a,
∴ AD = 2a,ED = a,∴ AE =
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由
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tan∠AGE
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∴ cos∠AGE =
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点评:主要是考查了面面垂直的证明以及二面角的平面角的求解运算,属于基础题。
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