题目内容
【题目】化简sin2α+sin2β﹣sin2αsin2β+cos2αcos2β= .
【答案】1
【解析】解:sin2α+sin2β﹣sin2αsin2β+cos2αcos2β
=sin2α(1﹣sin2β)+sin2β+cos2αcos2β
=sin2αcos2β+sin2β+cos2αcos2β
=cos2β(sin2α+cos2α)+sin2β
=cos2β+sin2β=1
所以答案是:1
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题目内容
【题目】化简sin2α+sin2β﹣sin2αsin2β+cos2αcos2β= .
【答案】1
【解析】解:sin2α+sin2β﹣sin2αsin2β+cos2αcos2β
=sin2α(1﹣sin2β)+sin2β+cos2αcos2β
=sin2αcos2β+sin2β+cos2αcos2β
=cos2β(sin2α+cos2α)+sin2β
=cos2β+sin2β=1
所以答案是:1