题目内容
等边三角形ABC与正方形ABDE有一公共边AB,二面角C-AB-D的余弦值为
,M,N分别是AC,BC的中点,则EM,AN所成角的余弦值等于________.
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设AB=2,作CO⊥平面ABDE,OH⊥AB,则CH⊥AB,∠CHO为二面角C-AB-D的平面角,
CH=
,OH=CH·cos∠CHO=1,结合等边三角形ABC与正方形ABDE可知此四棱锥为正四棱锥,则AN=EM=CH=
.
=
(
+
),
=
-
,
·
=
(
+
)·
=
.
故EM,AN所成角的余弦值为
=
.
CH=
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故EM,AN所成角的余弦值为
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