题目内容
(2014·孝感模拟)已知函数f(x)=
sinωxcosωx-cos2ωx,其中ω为使f(x)能在x=
时取得最大值的最小正整数.
(1)求ω的值.
(2)设△ABC的三边长a,b,c满足b2=ac,且边b所对的角θ的取值集合为M,当x∈M时,求f(x)的值域.
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824050816167368.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824050816167353.png)
(1)求ω的值.
(2)设△ABC的三边长a,b,c满足b2=ac,且边b所对的角θ的取值集合为M,当x∈M时,求f(x)的值域.
(1)2 (2)
.
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824050816183395.png)
(1)f(x)=sin
-
,依题意有
-
=2kπ+
(k∈Z),
即ω=
(k∈Z),ω的最小正整数值为2,所以ω=2.
(2)b2=ac,又b2=a2+c2-2accosB,
所以a2+c2-2accosB=ac,即1+2cosB=
≥
=2,
所以1+2cosB≥2,所以cosB≥
,所以0<B≤
,
即M=
,
f(x)=sin
-
,0<x≤
,
所以-
<4x-
≤
,
所以sin
∈
,
所以f(x)∈
,
故函数f(x)的值域是
.
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824050816198613.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824050816214274.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824050816229381.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824050816229308.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824050816245287.png)
即ω=
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824050816261403.png)
(2)b2=ac,又b2=a2+c2-2accosB,
所以a2+c2-2accosB=ac,即1+2cosB=
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824050816276402.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824050816292360.png)
所以1+2cosB≥2,所以cosB≥
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824050816214274.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824050816323298.png)
即M=
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824050816339448.png)
f(x)=sin
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824050816354564.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824050816214274.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824050816323298.png)
所以-
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824050816229308.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824050816229308.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824050816417344.png)
所以sin
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824050816354564.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824050816448406.png)
所以f(x)∈
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824050816183395.png)
故函数f(x)的值域是
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824050816183395.png)
![](http://thumb.zyjl.cn/images/loading.gif)
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