题目内容
如图,在平面直角坐标系
中,点
为椭圆
的右顶点, 点
,点
在椭圆上,
.
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005348124345.jpg)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/201408240053481394055.jpg)
(1)求直线
的方程;
(2)求直线
被过
三点的圆
截得的弦长;
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005348030413.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005348046300.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005348061767.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005348077503.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005348093395.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005348108554.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005348124345.jpg)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/201408240053481394055.jpg)
(1)求直线
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005348155374.png)
(2)求直线
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005348155374.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005348186493.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005348202313.png)
(1)
(2) ![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005348233753.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005348217519.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005348233753.png)
试题分析:解: (1)因为
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005348108554.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005348264524.png)
从而得
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005348280694.png)
所以直线BD的方程为
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005348217519.png)
(2)线段BP的垂直平分线方程为x=0,线段AP的垂直平分线方程为
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005348405443.png)
所以圆C的圆心为(0,-1),且圆C的半径为
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005348420453.png)
又圆心(0,-1)到直线BD的距离为
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005348420473.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005348155374.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005348202313.png)
为
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005348233753.png)
点评:解决的关键是利用直线与圆的位置关系的判定法则,圆心到直线的距离与圆的半径的关系来得到求解,属于基础题。
![](http://thumb.zyjl.cn/images/loading.gif)
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