题目内容

【答案】分析:先利用指数函数的图象和性质:y=ax (0<a<1)为R上的减函数,得对数不等式,再利用对数函数的单调性解不等式即可
解答:解:∵
在R上为减函数,
∴
即
∴
故答案为
点评:本题考查了指数函数的图象和性质,对数函数的单调性,解简单的对数不等式
解答:解:∵

∴

即

∴

故答案为

点评:本题考查了指数函数的图象和性质,对数函数的单调性,解简单的对数不等式

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