题目内容
【题目】(本小题满分12分)已知数列的首项
(1)求的通项公式;
(2)证明:对任意的.
【答案】解:(1)
∴ ∴
又 ∵
∴ 是以
为首项,
为公比的等比数列·········································4分
∴
∴ ································································6分
(2) 由 (1) 知···························································7分
∴ 原不等式成立··························································12分
【解析】略
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