题目内容
已知F是双曲线
-
=1的左焦点,A(1,4),P是双曲线右支上的动点,则|PF|+|PA|的最小值为 .
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9
由
-
=1知c2=4+12=16,
c=4.
∴左焦点F(-4,0),设双曲线右焦点为F′(4,0),
∵点P在双曲线右支上,
∴|PF|-|PF′|=2a=4,
∴|PF|=4+|PF′|,
∴|PF|+|PA|=4+|PF′|+|PA|.
由图可知,当A、P、F′三点共线时,|PF′|+|PA|最小,此时,
(|PF|+|PA|)min=4+(|PF′|+|PA|)min
=4+|AF′|
=4+
=4+5
=9.
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c=4.
∴左焦点F(-4,0),设双曲线右焦点为F′(4,0),
∵点P在双曲线右支上,
∴|PF|-|PF′|=2a=4,
∴|PF|=4+|PF′|,
∴|PF|+|PA|=4+|PF′|+|PA|.
由图可知,当A、P、F′三点共线时,|PF′|+|PA|最小,此时,
(|PF|+|PA|)min=4+(|PF′|+|PA|)min
=4+|AF′|
=4+

=4+5
=9.
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