题目内容
已知奇函数f(x)在区间(-∞,+∞)上是单调递减函数,
,
,
∈R且
+
>0,
+
>0,
+
>0.试说明f(
)+f(
)+f(
)的值与0的关系.












f(
)+f(
)+f(
)<0



由
+
>0,得
>-
.
∵f(x)在R上是单调减函数,∴f(
)<f(-
).
又∵f(x)为奇函数,∴f(
)<-f(
),∴f(
)+f(
)<0,
同理f(
)+f(
)<0,f(
)+f(
)<0,
∴f(
)+f(
)+f(
)<0.




∵f(x)在R上是单调减函数,∴f(


又∵f(x)为奇函数,∴f(




同理f(




∴f(




练习册系列答案
相关题目