题目内容
(本小题满分10分)(选修4-4:坐标系与参数方程)
在直角坐标系中,直线
的参数方程为![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/201408240001381501087.png)
为参数).若以坐标原点
为极点,
轴正半轴为极轴建立极坐标系,则曲线
的极坐标方程为
.
(I)求曲线
的直角坐标方程;
(II)求直线
被曲线
所截得的弦长.
在直角坐标系中,直线
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824000138134280.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/201408240001381501087.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824000138166267.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824000138181292.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824000138197266.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824000138212313.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824000138228932.png)
(I)求曲线
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824000138212313.png)
(II)求直线
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824000138134280.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824000138212313.png)
(I)
(II)![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824000138306450.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824000138290947.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824000138306450.png)
试题分析:(I) 由
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824000138228932.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824000138353668.png)
两边同乘以
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824000138368311.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824000138384796.png)
∴
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824000138400651.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824000138290947.png)
(2)将直线参数方程代入圆
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824000138212313.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824000138446674.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824000138462846.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/201408240001384931559.png)
点评:抓住极坐标与平面直角坐标互化公式并准确应用是解决此类问题的关键,高考中对该部分重点考查极坐标与直角坐标的互化以及圆的极坐标问题.
![](http://thumb.zyjl.cn/images/loading.gif)
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