题目内容
如图,在长方体ABCD-A1B1C1D1中,AB=BC=2,AA1=1,则异面直线AC1与BB1所成的角为( )
A.arctan
| B.arccos
| C.arcsin
| D.arctan2
|
因为长方体ABCD-A1B1C1D1中,AA1∥BB1,
∴∠A1AC1为异面直线异面AC1与BB1所成的角,
∵AA1⊥A1C1,
∴△A1AC1为直角三角形,
∵AB=BC=2,
∴A1C1=2
,
∴tan∠A1AC1=
=2
,
∴∴∠A1AC1=arctan2
,
故选D.
∴∠A1AC1为异面直线异面AC1与BB1所成的角,
∵AA1⊥A1C1,
∴△A1AC1为直角三角形,
∵AB=BC=2,
∴A1C1=2
2 |
∴tan∠A1AC1=
A1C1 |
AA1 |
2 |
∴∴∠A1AC1=arctan2
2 |
故选D.
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