题目内容
(1)已知lg2=a,lg3=b,试用a,b表示 log215;
(2)求值:(2
)
+(lg5)0+(
)-
.
(2)求值:(2
7 |
9 |
1 |
2 |
27 |
64 |
1 |
3 |
(1)log215=
=
=
.
(2)原式=[(
)2]
+1+[(
)-3]-
=
+1+
=4.
lg3+lg5 |
lg2 |
lg3+1-lg2 |
lg2 |
b+1-a |
a |
(2)原式=[(
5 |
3 |
1 |
2 |
4 |
3 |
1 |
3 |
5 |
3 |
4 |
3 |
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