ÌâÄ¿ÄÚÈÝ

¡¾ÌâÄ¿¡¿ÏÂÁÐ˵·¨ÖÐÕýÈ·µÄÊÇ

¢Ù¾§ÌåÖзÖ×Ó¼ä×÷ÓÃÁ¦Ô½´ó£¬ ·Ö×ÓÔ½Îȶ¨

¢ÚÔ­×Ó¾§ÌåÖй²¼Û¼üԽǿ£¬ ÈÛµãÔ½¸ß

¢Û¸É±ùÊÇ CO2 ·Ö×Óͨ¹ýÇâ¼üºÍ·Ö×Ó¼ä×÷ÓÃÁ¦ÓйæÔòÅÅÁгɵķÖ×Ó¾§Ìå

¢ÜÔÚNa2OºÍNa2O2¾§ÌåÖУ¬Òõ¡¢ÑôÀë×ÓÊýÖ®±ÈÏàµÈ

¢ÝÕýËÄÃæÌå¹¹Ð͵ķÖ×Ó£¬¼ü½Ç¶¼ÊÇ109¡ã28'£¬Æ侧ÌåÀàÐÍ¿ÉÄÜÊÇÔ­×Ó¾§Ìå»ò·Ö×Ó¾§Ìå

¢Þ·Ö×Ó¾§ÌåÖж¼º¬Óл¯Ñ§¼ü

¢ßº¬4.8 g̼ԪËصĽð¸Õʯ¾§ÌåÖеÄ̼̼¼üµÄÎïÖʵÄÁ¿Îª0.8 mol

A.¢Ù¢Ú¢Û¢Ü¢ÝB.¢Ú¢Ü¢ßC.¢Ý¢Þ¢ßD.¢Û¢Ü

¡¾´ð°¸¡¿B

¡¾½âÎö¡¿

¢Ù·Ö×ÓµÄÎȶ¨ÐÔÈ¡¾öÓÚ·Ö×ÓÄÚ¹²¼Û¼üÄܵĴóС£¬Óë·Ö×Ó¼ä×÷ÓÃÁ¦Î޹أ¬·Ö×Ó¼ä×÷ÓÃÁ¦Ö»Ó°ÏìÎïÖʵÄÎïÀíÐÔÖÊ£¬¢Ù²»ÕýÈ·£»

¢ÚÔ­×Ó¾§ÌåÖй²¼Û¼üԽǿ£¬ÆÆ»µËüËùÐèµÄÄÜÁ¿Ô½´ó£¬ÔòÈÛµãÔ½¸ß£¬¢ÚÕýÈ·£»

¢ÛCO2·Ö×Ӽ䲻ÄÜÐγÉÇâ¼ü£¬¢Û²»ÕýÈ·£»

¢ÜÔÚNa2OºÍNa2O2¾§ÌåÖУ¬ÒõÀë×Ó·Ö±ðΪO2-¡¢O22-£¬ÑôÀë×Ó¶¼ÎªNa+£¬Òõ¡¢ÑôÀë×ÓÊýÖ®±È¶¼Îª1£º2£¬¢ÜÕýÈ·£»

¢ÝÕýËÄÃæÌå¹¹Ð͵ķÖ×Ó£¬AB4ÐÍ£¨ÈçCH4£©£¬¼ü½Ç¶¼ÊÇ109¡ã28¡ä£»A4ÐÍ£¨ÈçP4£©£¬¼ü½ÇΪ60¡ã£¬¢Ý²»ÕýÈ·£»

¢ÞÏ¡ÓÐÆøÌåÊǵ¥Ô­×Ó·Ö×Ó£¬ÔòÏ¡ÓÐÆøÌåÐγɵķÖ×Ó¾§ÌåÖв»º¬Óл¯Ñ§¼ü£¬¢Þ²»ÕýÈ·£»

¢ß4.8 g̼ԭ×ÓΪ=0.4mol£¬½ð¸ÕʯÖУ¬Ã¿¸öCÓëÆäËü4¸öCÐγÉÁË4¸öC-C¹²¼Û¼ü£¬Ôòƽ¾ùÿ¸ö̼ԭ×ÓÐγÉ4¡Á=2¸ö¹²¼Û¼ü£¬ËùÒÔ¹²¼Û¼üµÄÎïÖʵÄÁ¿Îª0.4mol ¡Á2=0.8 mol£¬¢ßÕýÈ·¡£

×ÛºÏÒÔÉÏ·ÖÎö£¬¢Ú¢Ü¢ßÕýÈ·¡£

´ð°¸Ñ¡B¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø