ÌâÄ¿ÄÚÈÝ

ÓÃÖÊÁ¿·ÖÊýΪ98£¥£¬ÃܶÈΪ1.84 g¡¤cm£­3µÄŨÁòËáÅäÖÆ1 mol/LÏ¡ÁòËá100 mL£¬Æä²Ù×÷ÓÐÒÔϸ÷²½£º

¢ÙÓÃÁ¿Í²Á¿È¡________mLŨÁòËá

¢ÚÏ´µÓÉÕ±­ºÍ²£Á§°ô2£­3´Î£¬½«Ï´µÓҺתÈëÈÝÁ¿Æ¿ÖÐ

¢Û½«Ï¡ÊÍ¡¢ÀäÈ´ºóµÄÁòËáתÈë100 mLÈÝÁ¿Æ¿ÖÐ

¢Ü½«Å¨ÁòËáµ¹ÈëÊ¢ÓÐË®µÄÉÕ±­ÖÐÏ¡ÊÍ¡¢ÀäÈ´

¢Ý¼ÓË®ÖÁÒºÃæ½Ó½ü¿Ì¶ÈÏß1¡«2 cm´¦£¬¶¨ÈÝ£¬Ò¡ÔÈ

Íê³ÉÏÂÁÐÌî¿Õ£º

(1)µÚ¢Ù²½²Ù×÷ÖÐÓ¦ÓÃÁ¿Í²Á¿È¡________mLŨÁòË᣻ӦѡÔñ________mLÁ¿Í²(Ìî5¡¢10»ò50)£®

(2)±¾ÊµÑéÓõ½µÄ»ù±¾ÒÇÆ÷ÒÑÓÐÉÕ±­¡¢Á¿Í²¡¢²£Á§°ô£¬»¹È±ÉÙµÄÒÇÆ÷ÊÇ________£®

(3)ÕýÈ·µÄ²Ù×÷˳ÐòÊÇ(ÓÃÐòºÅÌîд)________£®

(4)ÏÂÁвÙ×÷»áʹʵ¼ÊŨ¶ÈÆ«¸ß£¬Æ«µÍ»¹ÊDz»±ä£¬ÇëÌîд£º

1)Ò¡ÔȺó£¬ÒºÃæµÍÓڿ̶ÈÏߣ¬Ã»ÓÐÔÙ¼ÓË®£»________£®

2)ÒÆÒº¹ý³ÌÖУ¬²»Ð¡ÐĽ¦³öÉÙÁ¿ÈÜÒº£»________£®

3)¶¨ÈÝʱ£¬Èç¹û¸©Êӿ̶ÈÏߣ¬ÅäÖƵÄÁòËáŨ¶È½«________£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø