ÌâÄ¿ÄÚÈÝ

¡¾ÌâÄ¿¡¿×Ô20ÊÀ¼Í60Äê´úÒÔºó£¬ÈËÃÇ·¢ÏÖÁË120¶àÖÖº¬ÌúÁò´ØÈç¡¢¡¢µÈµÄøºÍµ°°×ÖÊ¡£ËüÊÇ´æÔÚÓÚÉúÎïÌåµÄ×î¹ÅÀϵÄÉúÃüÎïÖÊÖ®Ò»¡£Ä³»¯Ñ§ÐËȤС×éÔÚÑо¿Ä³ÌúÁò´Ø½á¹¹µÄ×é³Éʱ£¬Éè¼ÆÁËÏÂÁÐʵÑ飺

ʵÑéÒ»£º²â¶¨ÁòµÄÖÊÁ¿£º

(1)Á¬½Ó×°Öã¬ÇëÌîд½Ó¿Ú˳Ðò£ºb½Ó____________________

(2)¼ì²é×°ÖõÄÆøÃÜÐÔ£¬ÔÚAÖзÅÈë0.4gÌúÁò´ØµÄÑùÆ·º¬Óв»ÈÜÓÚË®ºÍÑÎËáµÄÔÓÖÊ,ÔÚBÖмÓÈëÆ·ºìÈÜÒº£¬ÔÚCÖмÓÈë30mL 0.1mol/LµÄËáÐÔÈÜÒº£®

(3)ͨÈë¿ÕÆø²¢¼ÓÈÈ£¬·¢ÏÖ¹ÌÌåÖð½¥×ª±äΪºì×ØÉ«£®

(4)´ý¹ÌÌåÍêȫת»¯ºó£¬È¡CÖеÄÈÜÒº£¬ÓÃ0.1mol/LµÄµâ»¯¼ØÈÜÒº½øÐеζ¨¡£¼Ç¼Êý¾ÝÈçÏ£º

µÎ¶¨´ÎÊý

´ý²âÈÜÒºÌå»ý

ÏûºÄµâ»¯¼ØÈÜÒºÌå»ý

µÎ¶¨Ç°¿Ì¶È

µÎ¶¨ºó¿Ì¶È

1

2

3

ʵÑé¶þ£º²â¶¨ÌúµÄÖÊÁ¿£º

ȡʵÑé¢ñÖÐAµÄÓ²Öʲ£Á§¹ÜÖеIJÐÁô¹ÌÌå¼ÓÈëÏ¡ÑÎËáÖУ¬³ä·Ö½Á°èºó¹ýÂË£¬ÔÚÂËÒºÖмÓÈë×ãÁ¿µÄNaOHÈÜÒº£¬¹ýÂ˺óÈ¡ÂËÔü£¬¾­×ÆÉÕµÃ0.32g¹ÌÌ壮ÊԻشðÏÂÁÐÎÊÌ⣺

(1)¼ì²é¡°ÊµÑéÒ»¡±ÖÐ×°ÖÃAµÄÆøÃÜÐԵķ½·¨ÊÇ_________

(2)µÎ¶¨ÖÕµãµÄÅжϷ½·¨ÊÇ_________

(3)×°ÖÃBÖÐÆ·ºìÈÜÒºµÄ×÷ÓÃÊÇ_______ÓÐͬѧÌá³ö£¬³·È¥B×°Ö㬶ÔʵÑéûÓÐÓ°Ï죬ÄãµÄ¿´·¨ÊÇ______Ñ¡Ìî¡°ºÏÀí¡±»ò¡°²»ºÏÀí¡±£¬ÀíÓÉÊÇ_________

(4)ÓÃKIÈÜÒºµÎ¶¨ÈÜҺʱ·¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽΪ_________

(5)Çë¼ÆËãÕâÖÖÌúÁò´Ø½á¹¹µÄ»¯Ñ§Ê½_________

(6)ÏÂÁвÙ×÷£¬¿ÉÄÜÒýÆðÆ«´óµÄÊÇ_________

µÎ¶¨Ê£ÓàÈÜҺʱ£¬KIÈÜÒºµÎµ½×¶ÐÎÆ¿Íâ±ßÒ»µÎ

ÅäÖÆKIÈÜҺʱ£¬¶¨ÈÝʱ¸©Êӿ̶ÈÏß

Óõ⻯¼ØÈÜÒºµÎ¶¨Ê£ÓàÈÜҺʱ£¬µÎ¶¨Ç°ÓÐÆøÅÝ£¬µÎ¶¨ºóÎÞÆøÅÝ

ʵÑé¶þÖУ¬¶ÔÂËÔü×ÆÉÕ²»³ä·Ö

¡¾´ð°¸¡¿b½Óд²»Ð´¶¼¶Ô ÔÚµ¼¹Üb½ÓÉϳ¤µ¼¹Ü£¬°ÑÄ©¶Ë²åÈëË®²ÛÖУ¬¹Ø±Õ»îÈû£¬Óþƾ«µÆ΢ÈÈÓ²ÖÊÊÔ¹ÜA£¬µ¼¹Ü³¤µ¼¹Ü¿ÚÓÐÆøÅݲúÉú£¬³·È¥¾Æ¾«µÆ£¬µ¼¹ÜÐγÉÒ»¶ÎË®Öù£¬ËµÃ÷×°ÖÃÆøÃÜÐÔÁ¼ºÃ ¼ÓÈë×îºóÒ»µÎKIÈÜÒº£¬ÈÜÒº×ÏÉ«ÍÊÈ¥£¬ÇÒ°ë·ÖÖÓ²»»Ö¸´Îª×ÏÉ« ¼ìÑé¶þÑõ»¯ÁòÊÇ·ñ±»ËáÐÔ¸ßÃÌËá¼ØÍêÈ«ÎüÊÕ ºÏÀí ÈôBÖиßÃÌËá¼ØÈÜÒºµÄ×ÏÉ«²»ÍÊÈ¥£¬ËµÃ÷¶þÑõ»¯Áò±»ÎüÊÕÍêÈ«

¡¾½âÎö¡¿

ÌúÁò´ØµÄÑùÆ·ÔÚ×°ÖÃÖÐÓëO2·´Ó¦£¬µÃµ½SO2£¬²âµãSO2µÄº¬Á¿£¬ÓÃËáÐÔ¸ßÃÌËá¼ØÎüÊÕ£¬ÔÙÓÃÆ·ºìÈÜÒº¼ì²éSO2ÊÇ·ñÎüÊÕÍêÈ«£¬ÔÙ½ÓβÆøÎüÊÕ¡£

ʵÑéÒ»£º(1)ÓøßÃÌËá¼ØÎüÊÕ¶þÑõ»¯Áò£¬ÓÃÆ·ºìÖ¤Ã÷¶þÑõ»¯ÁòÎüÊÕÍêÈ«£¬×îºóÓÃÇâÑõ»¯ÄÆÎüÊÕβÆø£¬½Ó¿Ú˳Ðò£ºb½Óд²»Ð´¶¼¶Ô£¬¹Ê´ð°¸Îª£ºb½Óд²»Ð´¶¼¶Ô£»

ʵÑé¶þ£º(1)ÏÈÐγÉÒ»ÃܱÕÌåϵ£¬ÀûÓüÓÈÈÅòÕÍ·¨¼ì²é×°ÖÃÆøÃÜÐÔ£¬¹Ê´ð°¸Îª£ºÔÚµ¼¹Üb½ÓÉϳ¤µ¼¹Ü£¬°ÑÄ©¶Ë²åÈëË®²ÛÖУ¬¹Ø±Õ»îÈû£¬Óþƾ«µÆ΢ÈÈÓ²ÖÊÊÔ¹ÜA£¬µ¼¹Ü³¤µ¼¹Ü¿ÚÓÐÆøÅݲúÉú£¬³·È¥¾Æ¾«µÆ£¬µ¼¹ÜÐγÉÒ»¶ÎË®Öù£¬ËµÃ÷×°ÖÃÆøÃÜÐÔÁ¼ºÃ£»

(2)µâ»¯¼Øʹ¸ßÃÌËá¼ØÈÜÒºÍÊÉ«£¬¹Ê´ð°¸Îª£º¼ÓÈë×îºóÒ»µÎKIÈÜÒº£¬ÈÜÒº×ÏÉ«ÍÊÈ¥£¬ÇÒ°ë·ÖÖÓ²»»Ö¸´Îª×ÏÉ«£»

(3)Æ·ºìÊǼìÑé¶þÑõ»¯ÁòÊÇ·ñ±»ËáÐÔ¸ßÃÌËá¼ØÍêÈ«ÎüÊÕ£»Ò²¿ÉʡȥƷºì×°Öã¬Òò¿ÉÒÔ¸ù¾Ý¸ßÃÌËá¼ØÑÕÉ«±ä»¯À´È·¶¨ÊÇ·ñÍêÈ«ÎüÊÕ£¬ÈôBÖиßÃÌËá¼ØÈÜÒºµÄ×ÏÉ«²»ÍÊÈ¥£¬ËµÃ÷¶þÑõ»¯Áò±»ÎüÊÕÍêÈ«£¬¹Ê´ð°¸Îª£º¼ìÑé¶þÑõ»¯ÁòÊÇ·ñ±»ËáÐÔ¸ßÃÌËá¼ØÍêÈ«ÎüÊÕ£»ºÏÀí£»ÈôBÖиßÃÌËá¼ØÈÜÒºµÄ×ÏÉ«²»ÍÊÈ¥£¬ËµÃ÷¶þÑõ»¯Áò±»ÎüÊÕÍêÈ«£»

(4)¸ßÃÌËáËá¸ù±»»¹Ô­ÎªÃÌÀë×Ó£¬µâÀë×Ó±»Ñõ»¯Îªµâµ¥ÖÊ£¬¹Ê´ð°¸Îª£º£»

(5)µÚÒ»´ÎµÎ¶¨£¬²ÝËáÈÜÒºµÄÌå»ýÓëµÚ2¡¢3´ÎÏà²îÌ«´ó£¬Ó¦ÉáÈ¥£¬È¡µÚ2¡¢3´ÎµÄƽ¾ùÖµ¼ÆËã±ê×¼ÈÜÒºµÄÌå»ýΪ£¬¸ù¾Ý»¯Ñ§·½³Ìʽ£ºÖªÊ£ÓàµÄ¸ßÃÌËá¼ØÊÇ£¬¼ÓÈëÁË30mL£¬Ö»È¡ÁË3mL£¬ËùÒÔ¹²Ê£Óà¸ßÃÌËá¼Ø£»ËùÒԲμӷ´Ó¦µÄ¸ßÃÌËá¼ØÊÇ£»ÔÙ¸ù¾Ý¹Øϵʽ¼ÆËãÉú³É¶þÑõ»¯Áò£¬È¡ÊµÑé¢ñÖÐAµÄÓ²Öʲ£Á§¹ÜÖеIJÐÁô¹ÌÌå¼ÓÈëÏ¡ÑÎËáÖУ¬³ä·Ö½Á°èºó¹ýÂË£¬ÔÚÂËÒºÖмÓÈë×ãÁ¿µÄNaOHÈÜÒº£¬¹ýÂ˺óÈ¡ÂËÔü£¬¾­×ÆÉյùÌÌ壬¹ÌÌåÊÇ£¬¼ÆË㣬ÀûÓÃÌúÔªËغÍÁòÔªËØÊغãÖª£º£º5£¬È·¶¨µÄ»¯Ñ§Ê½Îª£º£¬¹Ê´ð°¸Îª£º£»

(6)a.µÎ¶¨Ê£ÓàÈÜҺʱ£¬KIÈÜÒºµÎµ½×¶ÐÎÆ¿Íâ±ßÒ»µÎÔò±ê׼Һƫ¶à£¬¼ÆËãʱµ¼ÖÂÁòÔªËØÆ«ÉÙ£¬±Èֵƫ´ó£»

b.ÅäÖÆKIÈÜҺʱ£¬¶¨ÈÝʱ¸©Êӿ̶ÈÏߣ¬»áʹŨ¶ÈÆ«´ó£¬µ¼ÖÂÊ£Óà¸ßÃÌËá¼ØƫС£¬ÁòÆ«¶à£¬±ÈֵƫС£»

c.Óõ⻯¼ØÈÜÒºµÎ¶¨Ê£ÓàÈÜҺʱ£¬µÎ¶¨Ç°ÓÐÆøÅÝ£¬µÎ¶¨ºóÎÞÆøÅݵ¼Ö±ê×¼ÒºÌåÓÃÁ¿Æ«´ó£¬Ê£ÓàµÄ¸ßÃÌËá¼ØÆ«¶à£¬¼ÆËãµÄÁòÔªËØÆ«ÉÙ£¬±Èֵƫ´ó£»

d.ʵÑé¶þÖУ¬¶ÔÂËÔü×ÆÉÕ²»³ä·Ö»á¼ÆËãµÄÌúÔªËØÆ«¶à£¬±Èֵƫ´ó£»

acdÕýÈ·£¬¹Ê´ð°¸Îª£ºacd¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

¡¾ÌâÄ¿¡¿°´ÒªÇó»Ø´ðÏÂÁÐÎÊÌâ

(1)ÒÑÖª25¡æ£¬NH3¡¤H2OµÄKb=1.8¡Á105£¬H2SO3µÄKa1=1.3¡Á102£¬Ka2=6.2¡Á108¡£½«SO2ͨÈë2.0 mol¡¤L-1°±Ë®ÖÐ(ÈÜÒºµÄÌå»ý±£³Ö²»±ä)£¬µ±c(OH)½µÖÁ1.0¡Á107 mol¡¤L1ʱ£¬ÈÜÒºÖÐµÄ =______£»(NH4)2SO3ÈÜÒºÖеÄÖÊ×ÓÊغã_______¡£

(2)ÍÁÈÀµÄpHÒ»°ãÔÚ4~9Ö®¼ä¡£ÍÁÈÀÖÐNa2CO3º¬Á¿½Ï¸ßʱ£¬pH¿É¸ß´ï10.5,ÊÔÓÃÀë×Ó·½³Ìʽ½âÊÍÍÁÈÀ³Ê¼îÐÔµÄÔ­ÒòΪ________________(ÓÃÀë×Ó·´Ó¦·½³Ìʽ)¡£¼ÓÈëʯ¸à(CaSO4¡¤2H2O)¿ÉÒÔʹÍÁÈÀ¼îÐÔ½µµÍ£¬Óйط´Ó¦µÄ»¯Ñ§·½³ÌʽΪ________¡£

(3)SOCl2ÊÇÒ»ÖÖҺ̬»¯ºÏÎ·ÐµãΪ77¡æ»¯ºÏÎÔÚÊ¢ÓÐ10mLË®µÄ׶ÐÎÆ¿ÖÐСÐĵμÓ8¡«10µÎSOCl2£¬¿É¹Û²ìµ½¾çÁÒË®½â·´Ó¦£¬ÒºÃæÓа×ÎíÐγɣ¬²¢Óд̼¤ÐÔÆøζµÄÆøÌåÒݳö£¬¸ÃÆøÌå¿ÉʹµÎÓÐÆ·ºìÊÔÒºµÄÂËÖ½ÍÊÉ«£¬ÇáÇáÕñµ´×¶ÐÎÆ¿£¬µÈ°×ÎíÏûʧºó£¬ÍùÈÜÒºÖеμÓAgNO3ÈÜÒº£¬Óв»ÈÜÓÚHNO3µÄ°×É«³ÁµíÎö³ö¡£

¢Ù¸ù¾ÝÉÏÊöʵÑ飬д³ö SOCl2ºÍË®·´Ó¦µÄ»¯Ñ§·½³Ìʽ________________¡£

¢ÚSOCl2ÓëAlCl3¡¤6H2O »ìºÏ¹²ÈÈ£¬¿ÉµÃµ½ÎÞË®AlCl3£¬ÆäÔ­ÒòÊÇ__________¡£

(4)µ±ÒâÍâʧ»ðʱ£¬½«ÅÝÄ­Ãð»ðÆ÷µ¹¹ýÀ´¼´¿ÉʹҩҺ»ìºÏ£¬Åç³öÅÝÄ­×´ÎïÆ·£¬×èÖ¹»ðÊÆÂûÑÓ£¬ÆäÏà¹ØµÄÀë×Ó·´Ó¦·½³ÌʽΪ___________________________¡£

¡¾ÌâÄ¿¡¿Áò´úÁòËáÄÆÊÇÒ»ÖÖÖØÒªµÄ»¯¹¤²úÆ·¡£Ä³ÐËȤС×éÄâÖƱ¸Áò´úÁòËáÄƾ§Ìå(Na2S2O3¡¤5H2O)¡£

¢ñ. [²éÔÄ×ÊÁÏ]

£¨1£©Na2S2O3¡¤5H2OÊÇÎÞɫ͸Ã÷¾§Ì壬Ò×ÈÜÓÚË®¡£ÆäÏ¡ÈÜÒºÓëBaCl2ÈÜÒº»ìºÏÎÞ³ÁµíÉú³É¡£

£¨2£©ÏòNa2CO3ºÍNa2S»ìºÏÒºÖÐͨÈëSO2¿ÉÖƵÃNa2S2O3£¬ËùµÃ²úÆ·Öг£º¬ÓÐÉÙÁ¿Na2SO3ºÍNa2SO4¡£

£¨3£©Na2SO3Ò×±»Ñõ»¯£»BaSO3ÄÑÈÜÓÚË®£¬¿ÉÈÜÓÚÏ¡HCl¡£

£¨4£©Áò´úÁòËáÄÆÓëµâ·´Ó¦µÄÀë×Ó·½³ÌʽΪ£º2+I2=+2I

¢ò. [ÖƱ¸²úÆ·]ʵÑé×°ÖÃÈçͼËùʾ(Ê¡ÂԼгÖ×°ÖÃ)

ʵÑé²½Ö裺

£¨1£©°´ÈçͼËùʾ×é×°ºÃ×°Öúó£¬Ó¦ÏÈ_________________________________________(Ìî²Ù×÷Ãû³Æ)£¬ÔÙ°´Í¼Ê¾¼ÓÈëÊÔ¼Á¡£ÒÇÆ÷BºÍDµÄ×÷ÓÃÊÇ__________________________________________£»

£¨2£©ÏÈÏòÉÕÆ¿CÖмÓÈëNa2SºÍNa2CO3»ìºÏÈÜÒº£¬ÔÙÏòÉÕÆ¿AÖеμÓŨH2SO4¡£CÖз´Ó¦Éú³ÉNa2S2O3ºÍCO2£¬»¯Ñ§·½³ÌʽΪ____________________________________________________________________¡£

£¨3£©´ýNa2SºÍNa2CO3ÍêÈ«ÏûºÄºó£¬½áÊø·´Ó¦¡£¹ýÂËCÖлìºÏÒº£¬ÂËÒº¾­Õô·¢¡¢½á¾§¡¢¹ýÂË¡¢Ï´µÓ¡¢¸ÉÔï¡¢µÃµ½²úÆ·¡£

¢ó. [̽¾¿Ó뷴˼]

£¨4£©ÓÃI2µÄ±ê×¼ÈÜÒº²â¶¨²úÆ·µÄ´¿¶È¡£È¡10.0g²úÆ·£¬ÅäÖƳÉ100mLÈÜÒº£¬ÅäÖÆÈÜÒºµÄÕôÁóË®±ØÐë¾­¹ýÖó·Ð¡¢ÀäÈ´ºó²ÅÄÜʹÓã¬ÆäÄ¿µÄÊÇɱ¾ú¡¢³ý_______________________________¼°¶þÑõ»¯Ì¼¡£È¡10.00mLÈÜÒº¡£ÒÔ________________________________ÈÜҺΪָʾ¼Á£¬ÓÃŨ¶ÈΪ0.10 mol/L I2µÄ±ê×¼ÈÜÒº½øÐе樣¬Ïà¹ØÊý¾Ý¼Ç¼ÈçϱíËùʾ¡£

񅧏

1

2

3

ÈÜÒºµÄÌå»ý/mL

10.00

10.00

10.00

ÏûºÄI2±ê×¼ÈÜÒºµÄÌå»ý/mL

19.95

17.10

20.05

µÎ¶¨Ê±£¬´ïµ½µÎ¶¨ÖÕµãµÄÏÖÏóÊÇ___________________________¡£Na2S2O3¡¤5H2OÔÚ²úÆ·ÖеÄÖÊÁ¿·ÖÊýÊÇ____________________________________(ÓðٷÖÊý±íʾ£¬ÇÒ±£Áô1λСÊý)¡£

¡¾ÌâÄ¿¡¿ÓÃÈçͼװÖÃÖƱ¸FeCO3£¬ÌáÈ¡³öµÄFeCO3ÓëÆÏÌÑÌÇËá·´Ó¦¿ÉµÃÆÏÌÑÌÇËáÑÇÌú¡£ÒÑÖª£ºÆÏÌÑÌÇËáÑÇÌú(C6H11O7)2FeÊdz£ÓõIJ¹Ìú¼Á£¬Ò×ÈÜÓÚË®¡£»Ø´ðÏÂÁÐÎÊÌ⣺

¢ñ(1)BÖмÓÈëÒ©Æ·Na2CO3£¬ÒªÊ¹AÖÐÖƵõÄFeSO4ÈÜÒº½øÈëBÖз¢Éú·´Ó¦£¬ÊµÑ鿪ʼʱ£¬Ó¦´ò¿ª·ÖҺ©¶·µÄ»îÈû¡¢______£¬¹Ø±Õ______£¬Ò»¶Îʱ¼äºó£¬¹Ø±Õ_______£¬´ò¿ª________ (ÌîÐýÈûµÄ±àºÅ)¡£

(2)½«ÆÏÌÑÌÇËáÓë̼ËáÑÇÌú»ìºÏ£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ(ÓлúÎïÓ÷Ö×Óʽ±íʾ)________________¡£

(3)´Ó»·¾³±£»¤µÄ½Ç¶È·ÖÎö£¬¸Ã×°ÖôæÔÚ²»×ãÖ®´¦ÊÇ£º_____________¡£

¢ò.ij²¹Ìú¼ÁµÄÖ÷Òª³É·ÖÊÇÁòËáÑÇÌú£¬ÓÃÑõ»¯»¹Ô­µÎ¶¨·¨¿É²â¶¨¸Ã²¹Ìú¼ÁÖÐÌúÔªËصĺ¬Á¿£¬ÊµÑéµÄÖ÷Òª²½ÖèÈçÏ£º

¢ÙÈ¡10Ƭ²¹Ìú¼ÁÑùÆ·£¬Èܽâ³ýÈ¥²»ÈÜÎï(²»ËðºÄÌúÔªËØ)£¬²¢Åä³É100mL´ý²âÈÜÒº¡£

¢ÚÁ¿È¡25.00mL´ý²âÒºÓÚ׶ÐÎÆ¿ÖС£

¢ÛÓÃc mol¡¤L1µÄËáÐÔKMnO4ÈÜÒºµÎ¶¨ÖÁÖյ㣬¼Ç¼ÏûºÄKMnO4ÈÜÒºµÄÌå»ý£¬Öظ´Á½´ÎʵÑ飬ƽ¾ùÏûºÄKMnO4ÈÜÒºÌå»ýΪV mL¡£

(4)¸ÃµÎ¶¨Ô­ÀíµÄÀë×Ó·½³ÌʽΪ______________________

(5)ÉÏÊöʵÑéÖÐÓ¦¸ÃÓÃÏ¡ÁòËáËữKMnO4ÈÜÒº£¬Èç¹ûÓÃÏõËá¶ÔKMnO4ÈÜÒº½øÐÐËữ£¬¶Ô²â¶¨½á¹ûµÄÓ°ÏìÊÇ________(Ìî¡°Æ«´ó¡±¡°Æ«Ð¡¡±»ò¡°ÎÞÓ°Ï족)¡£µÎ¶¨ÖÕµãµÄʵÑéÏÖÏóΪ______¡£

(6)ÿƬ²¹Ìú¼Áº¬ÌúÔªËصÄÖÊÁ¿Îª__________g(ÓôúÊýʽ±íʾ)¡£

¡¾ÌâÄ¿¡¿LiBH4Ϊ½üÄêÀ´´¢Çâ²ÄÁÏÁìÓòµÄÑо¿Èȵ㡣

£¨1£©·´Ó¦2LiBH4=2LiH£«2B£«3H2¡ü£¬Éú³É22.4 L H2(±ê×¼×´¿ö)ʱ£¬×ªÒƵç×ÓµÄÎïÖʵÄÁ¿Îª____mol¡£

£¨2£©ÏÂͼÊÇ2LiBH4/MgH2Ìåϵ·ÅÇâìʱäʾÒâͼ£¬Ôò£º

Mg(s)£«2B(s)=MgB2(s) ¡÷H£½________¡£

£¨3£©²ÉÓÃÇòÄ¥·¨ÖƱ¸AlÓëLiBH4µÄ¸´ºÏ²ÄÁÏ£¬²¢¶ÔAl£­LiBH4ÌåϵÓëË®·´Ó¦²úÇâµÄÌØÐÔ½øÐÐÏÂÁÐÑо¿£º

¢ÙÈçͼΪ25¡æˮԡʱÿ¿Ë²»Í¬Åä±ÈµÄAl£­LiBH4¸´ºÏ²ÄÁÏÓëË®·´Ó¦²úÉúH2Ìå»ýËæʱ¼ä±ä»¯¹Øϵͼ¡£ÓÉͼ¿ÉÖª£¬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ____(Ìî×Öĸ)¡£

a£®25¡æʱ£¬´¿ÂÁÓëË®²»·´Ó¦

b£®25¡æʱ£¬´¿LiBH4ÓëË®·´Ó¦²úÉúÇâÆø

c£®25¡æʱ£¬Al£­LiBH4¸´ºÏ²ÄÁÏÖÐLiBH4º¬Á¿Ô½¸ß£¬1000sÄÚ²úÉúÇâÆøµÄÌå»ýÔ½´ó

¢ÚÈçͼΪ25¡æºÍ75¡æʱ£¬Al£­LiBH4¸´ºÏ²ÄÁÏ[¦Ø(LiBH4)£½25%]ÓëË®·´Ó¦Ò»¶¨Ê±¼äºó²úÎïµÄX£­ÉäÏßÑÜÉäͼÆ×(X£­ÉäÏßÑÜÉä¿ÉÓÃÓÚÅжÏij¾§Ì¬ÎïÖÊÊÇ·ñ´æÔÚ£¬²»Í¬¾§Ì¬ÎïÖʳöÏÖÑÜÉä·åµÄÑÜÉä½Ç²»Í¬)¡£

´ÓͼÖзÖÎö£¬25¡æʱAl£­LiBH4¸´ºÏ²ÄÁÏÖÐÓëË®ÍêÈ«·´Ó¦µÄÎïÖÊÊÇ___________(Ìѧʽ)£¬²úÉúAl(OH)3µÄ»¯Ñ§·½³ÌʽΪ_________________¡£

£¨4£©ÈçͼÊÇÖ±½ÓÅðÇ⻯ÄÆ£­¹ýÑõ»¯ÇâȼÁϵç³ØʾÒâͼ¡£¸Ãµç³Ø¹¤×÷ʱ£¬Õý¼«¸½½üÈÜÒºµÄpH________(Ìî¡°Ôö´ó¡±¡¢¡°¼õС¡±»ò¡°²»±ä¡±)£¬¸º¼«µÄµç¼«·´Ó¦Ê½Îª________________________¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø