ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿µªÔªËØÊÇÔì³ÉË®Ì帻ӪÑø»¯µÄÖ÷ÒªÔÒò£¬ÔÚË®Öг£ÒÔ°±µª»òNO3ÐÎʽ´æÔÚ¡£
£¨1£©ÔÚpHΪ4¡«6ʱ£¬ÓÃH2ÔÚPd-Cu´ß»¯Ï½«NO3-»¹ÔΪN2¿ÉÏû³ýË®ÖÐNO3¡£¸Ã·´Ó¦µÄÀë×Ó·½³ÌʽΪ____¡£ÈôÓÃH2ºÍCO2µÄ»ìºÏÆøÌå´úÌæH2£¬NO3-È¥³ýЧ¹û¸üºÃ£¬ÆäÔÒòÊÇ____¡£
£¨2£©NaClOÑõ»¯¿É³ýÈ¥°±µª£¬·´Ó¦»úÀíÈçͼ1Ëùʾ£¨ÆäÖÐH2OºÍNaClÂÔÈ¥£©£¬ÊµÑé²âµÃÏàͬÌõ¼þÏ£¬Ïàͬ·´Ó¦Ê±¼ä£¬pHÓë°±µªµÄÈ¥³ýÂʹØϵÈçͼ2Ëùʾ£¬Î¶ÈÓë°±µªÈ¥³ýÂʹØϵÈçͼ3Ëùʾ¡£
ͼ1 ͼ2 ͼ3
¢ÙNaClOÑõ»¯NH3µÄ×Ü·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ____¡£
¢ÚÈçͼ2Ëùʾ£¬ÔÚpH£¾9ʱ£¬pHÔ½´óÈ¥³ýÂÊԽС£¬ÆäÔÒòÊÇ____¡£
¢ÛÈçͼ3Ëùʾ£¬Î¶ȵÍÓÚ15¡æʱ£¬Î¶ÈÔ½µÍÈ¥³ýÂÊÔ½µÍÆäÔÒòÊÇ____¡£µ±Î¶ȸßÓÚ25¡æʱ£¬Î¶ÈÔ½¸ßÈ¥³ýÂÊÒ²Ô½µÍ£¬ÆäÔÒòÊÇ____¡£
£¨3£©Óõ绯ѧ·¨¿ÉÈ¥³ý·ÏË®Öеݱµª¡£ÔÚº¬NH4+µÄ·ÏË®ÖмÓÈëÂÈ»¯ÄÆ£¬ÓöèÐԵ缫µç½â¡£·´Ó¦×°ÖÃÈçͼ4Ëùʾ£¬Ôòµç½âʱ£¬a¼«µÄµç¼«·´Ó¦Ê½Îª____¡£
¡¾´ð°¸¡¿ 2NO3¨C + 5H2 + 2H+ £½N2¡ü+ 6H2O CO2ÈÜÓÚÈÜÒºÖУ¬¿Éά³ÖpHÔÚ4¡«6Ö®¼ä 2NH3 + 3NaClO£½N2¡ü+ 3H2O + 3NaCl ClOµÄŨ¶È¼õС£¬Ñõ»¯·´Ó¦ËÙÂʼõÂý ζȵÍʱ·´Ó¦ËÙÂÊÂý ζȸßʱ£¬¼Ó¿ìÁËHClOµÄ·Ö½â£¨»òNaClO·Ö½â£©£¬ÀûÓÃÂʽµµÍ 2H2O + 2NH4+ + 2e¨C£½2NH3¡¤H2O + H2¡ü»ò2H+ + 2e¨C£½H2¡ü
¡¾½âÎö¡¿·ÖÎö£º£¨1£©ÇâÆøÄܽ«ÏõËá¸ù»¹ÔΪµªÆø£¬ÈÜÒº³ÊËáÐÔ£¬ËµÃ÷ÓÐH+²ÎÓë·´Ó¦£¬ÇâÆø±»Ñõ»¯Éú³ÉË®£»£¨2£©¸ù¾ÝͼʾÕÒ³ö·´Ó¦ÎïºÍÉú³ÉÎ£¨3£©¸ù¾ÝͼÖеç½âÔÀí½â´ð¡£
Ïê½â£º£¨1£©ÇâÆøÄܽ«ÏõËá¸ù»¹ÔΪµªÆø£¬ÈÜÒº³ÊËáÐÔ£¬ËµÃ÷ÓÐH+²ÎÓë·´Ó¦£¬ÇâÆø±»Ñõ»¯Éú³ÉË®£¬ÊéдʱעÒâ·´Ó¦µÄÌõ¼þ£¬¹Ê´ð°¸Îª£º2NO3¨C + 5H2 + 2H+ £½N2¡ü+ 6H2O£¨´ß»¯¼ÁÌõ¼þ£©£»ÒòΪÐè¿ØÖÆpHΪ4¡«6£¬ÈôÓÃH2ºÍCO2µÄ»ìºÏÆøÌå´úÌæH2£¬CO2ÈÜÓÚÈÜÒºÖУ¬¿Éά³ÖpHÔÚ4¡«6Ö®¼ä£¬Ê¹NO3-È¥³ýЧ¹û¸üºÃ£¬Òò´Ë£¬±¾Ìâ´ð°¸Îª£º2NO3¨C + 5H2 + 2H+ £½N2¡ü+ 6H2O £»CO2ÈÜÓÚÈÜÒºÖУ¬¿Éά³ÖpHÔÚ4¡«6Ö®¼ä¡£
£¨2£©¢ÙÓÉͼ֪£¬NaClOÑõ»¯NH3Éú³ÉN2¡¢H2OºÍNaCl,¸ù¾ÝµÃʧµç×ÓÊغ㡢Ô×ÓÊغãд³ö·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ2NH3 + 3NaClO£½N2¡ü+ 3H2O + 3NaCl¡£
¢ÚÔÚpH£¾9ʱ£¬ClO-µÄŨ¶È¼õС£¬Ñõ»¯·´Ó¦ËÙÂʼõÂý£¬È¥³ýÂʽµµÍ¡£
¢ÛÓÉͼ֪ζȵÍÓÚ15¡æʱ£¬·´Ó¦ËÙÂÊÂý£¬È¥³ýÂʽµµÍ¡£µ±Î¶ȸßÓÚ25¡æʱ£¬¼Ó¿ìÁËHClOµÄ·Ö½â£¨»òNaClO·Ö½â£©£¬ÀûÓÃÂʽµµÍ¡£
Òò´Ë£¬±¾ÌâÕýÈ·´ð°¸Îª£ºNH3 + 3NaClO£½N2¡ü+ 3H2O + 3NaCl £»ClO-µÄŨ¶È¼õС£¬Ñõ»¯·´Ó¦ËÙÂʼõÂý £»Î¶ȵÍʱ·´Ó¦ËÙÂÊÂý £» ζȸßʱ£¬¼Ó¿ìÁËHClOµÄ·Ö½â£¨»òNaClO·Ö½â£©£¬ÀûÓÃÂʽµµÍ¡£
£¨3£©¾Ýͼ¿ÉÖª£¬¸Ã³ØΪµç½â³Ø£¬aΪÒõ¼«£¬bΪÑô¼«£¬a¼«·¢Éú»¹Ô·´Ó¦£¬µç¼«·´Ó¦Ê½Îª£º2H2O + 2NH4+ + 2e¨C£½2NH3¡¤H2O + H2¡ü»ò2H+ + 2e¨C£½H2¡ü¡£Òò´Ë£¬±¾Ìâ´ð°¸Îª£º2H2O + 2NH4+ + 2e¨C£½2NH3¡¤H2O + H2¡ü»ò2H+ + 2e¨C£½H2¡ü¡£