ÌâÄ¿ÄÚÈÝ

¡¾ÌâÄ¿¡¿Ò»ÖÖRuÅäºÏÎïÓëg¡ªC3N4¸´ºÏ¹â´ß»¯¼Á½«CO2»¹Ô­ÎªHCOOHµÄÔ­ÀíʾÒâͼÈçͼ¡£

£¨1£©Ru»ù̬ԭ×Ó¼Ûµç×ÓÅŲ¼Ê½Îª4d75s1£¬Ð´³ö¸ÃÔªËØÔÚÔªËØÖÜÆÚ±íÖеÄλÖÃ___£¬ÊôÓÚ___Çø¡£

£¨2£©HCOOHÖЦҼüÓë¦Ð¼üµÄÊýÄ¿Ö®±ÈÊÇ___£¬HCOOHµÄ·Ðµã±ÈCO2¸ßµÄÔ­Òò___¡£

£¨3£©×ÏÍâ¹âµÄ¹â×ÓËù¾ßÓеÄÄÜÁ¿Ô¼Îª399kJ¡¤mol1¡£¸ù¾ÝϱíÓйص°°×ÖÊ·Ö×ÓÖÐÖØÒª»¯Ñ§¼üµÄÐÅÏ¢£¬ËµÃ÷ÈËÌ峤ʱ¼äÕÕÉä×ÏÍâ¹âºóƤ·ôÒ×ÊÜÉ˺¦µÄÔ­Òò__¡£

£¨4£©ÒÑÖªºÍÖÐËùÓÐÔ­×Ó¾ù¹²Ã棬ÆäÖеªÔ­×Ó½ÏÒ×ÐγÉÅäλ¼üµÄÊÇ___£¨Ìî¡°Ç°Õß¡±»ò¡°ºóÕß¡±£©¡£

£¨5£©ÏÂÁÐ״̬µÄµª¡¢ÑõÔ­×ÓÖУ¬µçÀë×îÍâ²ãÒ»¸öµç×ÓËùÐèÄÜÁ¿×î´óµÄÊÇ___£¨ÌîÐòºÅ£¬ÏÂͬ£©£¬×îСµÄÊÇ___(ÌîÐòºÅ)¡£

A.µª

B.Ñõ

C.Ñõ

D.Ñõ

£¨6£©Ò»ÖÖÀàʯīµÄ¾ÛºÏÎï°ëµ¼Ìåg¡ªC3N4£¬Æäµ¥²ãƽÃæ½á¹¹Èçͼ1£¬¾§°û½á¹¹Èçͼ2¡£

¢Ùg¡ªC3N4ÖеªÔ­×ÓµÄÔÓ»¯ÀàÐÍÊÇ__£»

¢Ú¸ù¾Ýͼ2£¬ÔÚͼ1ÖÐÓÃƽÐÐËıßÐλ­³öÒ»¸ö×îСÖظ´µ¥Ôª___£»

¢ÛÒÑÖª¸Ã¾§°ûµÄÌå»ýΪVcm3£¬Öмä²ãÔ­×Ó¾ùÔÚ¾§°ûÄÚ²¿£¬Éè°¢·ü¼ÓµÂÂÞ³£ÊýµÄֵΪNA£¬Ôòg¡ªC3N4µÄÃܶÈΪ__g¡¤cm-3¡£

¡¾´ð°¸¡¿µÚÎåÖÜÆÚ¢ø×å d 4£º1 HCOOH·Ö×Ó¼äÒ×ÐγÉÇâ¼ü ×ÏÍâ¹âµÄ¹â×ÓËù¾ßÓеÄÄÜÁ¿±Èµ°°×ÖÊ·Ö×ÓÖеĻ¯Ñ§¼ü¼üÄܴ󣬳¤Ê±¼äÕÕÉäʹ»¯Ñ§¼ü¶ÏÁÑ£¬´Ó¶øÆÆ»µµ°°×ÖÊ·Ö×Ó ºóÕß C D sp2ÔÓ»¯ »ò

¡¾½âÎö¡¿

£¨1£©ÓÉRu»ù̬ԭ×Ó¼Ûµç×ÓÅŲ¼Ê½Îª4d75s1¿ÉÖª£¬RuÔªËØλÓÚÖÜÆÚ±íµÚÎåÖÜÆÚ¢ø×壬ÊôÓÚdÇø£»

£¨2£©Ì¼Ô­×ÓÐγɵĵ¥¼üÈ«ÊǦҼü£¬ÐγɵÄË«¼üÓÐÒ»¸öÊǦҼü¡¢Ò»¸öÊǦмü£¬HCOOH·Ö×ÓÖк¬ÓÐ4¸ö¦Ò¼üºÍ1¸ö¦Ð¼ü£¬HCOOHºÍCO2¾ùΪ·Ö×Ó¾§Ì壬HCOOH·Ö×ÓÖк¬ÓÐôÈ»ù£¬·Ö×Ó¼äÄÜÐγÉÇâ¼ü£¬¶ø¶þÑõ»¯Ì¼·Ö×Ӽ䲻ÄÜÐγÉÇâ¼ü£»

£¨3£©×ÏÍâ¹âµÄ¹â×ÓËù¾ßÓеÄÄÜÁ¿Ô¼Îª399kJ/mol£¬±Èµ°°×ÖÊ·Ö×ÓÖÐC-C¡¢C-NºÍC-SµÄ¼üÄܶ¼´ó£»

£¨4£©ÖÐNÔ­×Ó²ÎÓëÐγɴó¦Ð¼ü£¬²»Ò׸ø³öµç×Ó¶ÔÐγÉÅäλ¼ü£¬ÖÐNÔ­×ÓÓÐÒ»¶Ô¹Âµç×Ó£¬ÈÝÒ׸ø³öµç×Ó¶ÔÐγÉÅäλ¼ü£»

(5)ͬһԪËصÄÔ­×Ó£¬µçÀë×îÍâ²ãÒ»¸öµç×ÓËùÐèÄÜÁ¿£º¼¤·¢Ì¬Ô­×Ó<»ù̬µÄµÚÒ»µçÀëÄÜ<µÚ¶þµçÀëÄÜ£»µ±Äܼ¶´¦ÓÚÈ«Âú¡¢°ëÂú¡¢È«¿Õʱ£¬½ÏÎȶ¨£¬µçÀë×îÍâ²ãÒ»¸öµç×ÓÐèÒªµÄÄÜÁ¿¸ß£»

(6)¢Ù¸ÃÎïÖÊÖÐNÔ­×Ó¼Û²ãµç×Ó¶ÔÊýΪ3£»

¢ÚÓÉͼ2¿ÉÖª£¬Öظ´µÄ½á¹¹µ¥ÔªÎªÁùÔª»·ºÍÍâ¼ÓÈý¸öNÔ­×ÓÐγɵĽṹ£»

¢ÛÓɾù̯·¨¼ÆËã¿ÉµÃ¡£

£¨1£©ÓÉRu»ù̬ԭ×Ó¼Ûµç×ÓÅŲ¼Ê½Îª4d75s1¿ÉÖª£¬RuÔªËØλÓÚÖÜÆÚ±íµÚÎåÖÜÆÚ¢ø×壬ÊôÓÚdÇø£¬¹Ê´ð°¸Îª£ºµÚÎåÖÜÆÚ¢ø×壬d£»

£¨2£©Ì¼Ô­×ÓÐγɵĵ¥¼üÈ«ÊǦҼü£¬ÐγɵÄË«¼üÓÐÒ»¸öÊǦҼü£¬Ò»¸öÊǦмü£¬HCOOH·Ö×ÓÖк¬ÓÐ4¸ö¦Ò¼üºÍ1¸ö¦Ð¼ü£¬ÔòHCOOH·Ö×ÓÖЦҼüÓë¦Ð¼üµÄÊýÄ¿Ö®±ÈÊÇ4:1£»HCOOHºÍCO2¾ùΪ·Ö×Ó¾§Ì壬HCOOH·Ö×ÓÖк¬ÓÐôÈ»ù£¬·Ö×Ó¼äÄÜÐγÉÇâ¼ü£¬¶ø¶þÑõ»¯Ì¼·Ö×Ӽ䲻ÄÜÐγÉÇâ¼ü£¬¹ÊHCOOHµÄ·Ðµã±ÈCO2¸ß£¬¹Ê´ð°¸Îª£º4:1£»HCOOH·Ö×Ó¼äÒ×ÐγÉÇâ¼ü£»

£¨3£©×ÏÍâ¹âµÄ¹â×ÓËù¾ßÓеÄÄÜÁ¿Ô¼Îª399kJ/mol£¬±Èµ°°×ÖÊ·Ö×ÓÖÐC-C¡¢C-NºÍC-SµÄ¼üÄܶ¼´ó£¬³¤Ê±¼äÕÕÉä×ÏÍâ¹âÄÜʹµ°°×ÖÊ·Ö×ÓÖеĻ¯Ñ§¼ü¶ÏÁÑ£¬´Ó¶øÆÆ»µµ°°×ÖÊ·Ö×Ó£¬¹Ê´ð°¸Îª£º×ÏÍâ¹âµÄ¹â×ÓËù¾ßÓеÄÄÜÁ¿±Èµ°°×ÖÊ·Ö×ÓÖеĻ¯Ñ§¼ü¼üÄܴ󣬳¤Ê±¼äÕÕÉäʹ»¯Ñ§¼ü¶ÏÁÑ£¬´Ó¶øÆÆ»µµ°°×ÖÊ·Ö×Ó£»

£¨4£©ÖÐNÔ­×Ó²ÎÓëÐγɴó¦Ð¼ü£¬²»Ò׸ø³öµç×Ó¶ÔÐγÉÅäλ¼ü£¬¶øÖÐNÔ­×ÓÓÐÒ»¶Ô¹Âµç×Ó£¬ÈÝÒ׸ø³öµç×Ó¶ÔÐγÉÅäλ¼ü£¬ÔòºóÕß·Ö×ÓÖеªÔ­×Ó½ÏÒ×ÐγÉÅäλ¼ü£¬¹Ê´ð°¸Îª£ººóÕߣ»

£¨5£©Î¢Á£µÄ½á¹¹Ô½Îȶ¨£¬µçÀë×îÍâ²ãÒ»¸öµç×ÓËùÐèÄÜÁ¿Ô½¸ß£¬

A. Ϊ»ù̬NÔ­×ӵĹìµÀ±íʾʽ£¬2pÄܼ¶°ë³äÂú¡¢½ÏÎȶ¨£»

B. Ϊ»ù̬OÔ­×ӵĹìµÀ±íʾʽ£¬Ê§È¥1¸öµç×ÓΪOµÄµÚÒ»µçÀëÄÜ£»

C. ʧȥ×îÍâ²ãÒ»¸öµç×ÓΪOµÄµÚ¶þµçÀëÄÜ£»

D. Ϊ¼¤·¢Ì¬OÔ­×Ó£»

ͬһԪËصÄÔ­×Ó£¬µçÀë×îÍâ²ãÒ»¸öµç×ÓËùÐèÄÜÁ¿£º¼¤·¢Ì¬Ô­×Ó<»ù̬µÄµÚÒ»µçÀëÄÜ<µÚ¶þµçÀëÄÜ£»µ±Äܼ¶´¦ÓÚÈ«Âú¡¢°ëÂú¡¢È«¿Õʱ£¬½ÏÎȶ¨£¬µçÀë×îÍâ²ãÒ»¸öµç×ÓÐèÒªµÄÄÜÁ¿¸ß£¬ÔòµçÀë×îÍâ²ãÒ»¸öµç×ÓËùÐèÄÜÁ¿×î´óµÄÊÇC£¬×îСµÄÊÇD£¬¹Ê´ð°¸Îª£ºC£»D£»

£¨6£©¢Ù¸ÃÎïÖÊÖÐNÔ­×Ó¼Û²ãµç×Ó¶ÔÊýΪ3£¬¸ù¾Ý¼Û²ãµç×Ó¶Ô»¥³âÀíÂÛÅжÏNÔ­×ÓÔÓ»¯ÀàÐÍΪsp2ÔÓ»¯£¬¹Ê´ð°¸Îª£ºsp2ÔÓ»¯£»

¢ÚÓÉͼ2¿ÉÖª£¬Öظ´µÄ½á¹¹µ¥ÔªÎªÁùÔª»·ºÍÍâ¼ÓÈý¸öNÔ­×ÓÐγɵĽṹ£¬×îСÖظ´µ¥ÔªÈçͼËùʾ£º»ò£¬¹Ê´ð°¸Îª£º»ò£»

¢ÛÓɾù̯·¨¿ÉÖª£¬¸Ã¾§°ûÖÐNÔ­×Ó¸öÊý=8¡Á+8¡Á+2¡Á+4=8£¬CÔ­×Ó¸öÊý=3+6¡Á=6£¬1¸ö¾§°ûµÄÖÊÁ¿=£¬ÃܶȦÑ=g.cm-3£¬¹Ê´ð°¸Îª£º¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

¡¾ÌâÄ¿¡¿¸ßµâËá¼Ø(KIO4)ÈÜÓÚÈÈË®£¬Î¢ÈÜÓÚÀäË®ºÍÇâÑõ»¯¼ØÈÜÒº£¬¿ÉÓÃ×÷ÓлúÎïµÄÑõ»¯¼Á¡£ÖƱ¸¸ßµâËá¼ØµÄ×°ÖÃͼÈçÏÂ(¼Ð³ÖºÍ¼ÓÈÈ×°ÖÃÊ¡ÂÔ)¡£»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©×°ÖÃIÖÐÊ¢·ÅŨÑÎËáµÄÒÇÆ÷Ãû³ÆÊÇ___________¡£

£¨2£©×°ÖÃIÖÐŨÑÎËáÓëKMnO4»ìºÏºó·¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ___________¡£

£¨3£©×°ÖâòÖеÄÊÔ¼ÁXµÄ×÷ÓÃ___________¡£

£¨4£©ÉÏÊöÌ¿Öð´ÆøÁ÷ÓÉ×óÖÁÓÒ¸÷½Ó¿Ú˳ÐòΪ___________(ÓÃ×Öĸ±íʾ)¡£

£¨5£©×°ÖÃÁ¬½ÓºÃºó£¬½«×°Öâóˮԡ¼ÓÈÈ£¬Í¨ÈëÂÈÆøÒ»¶Îʱ¼ä£¬ÀäÈ´ÎöŒç¸ßµâËá¼Ø¾§Ì壬¾­¹ýÂË£¬Ï´µÓ£¬¸ÉÔïµÈ²½ÖèµÃµ½²úÆ·¡£

¢Ùд³ö×°ÖâóÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º___________¡£

¢ÚÏ´µÓʱ£¬ÓëÑ¡ÓÃÈÈË®Ïà±È£¬Ñ¡ÓÃÀäˮϴµÓ¾§ÌåµÄÓŵãÊÇ___________¡£

¢ÛÉÏÊöÖƱ¸µÄ²úÆ·Öк¬ÉÙÁ¿µÄKIO3£¬ÆäËûÔÓÖʺöÂÔ£¬ÏÖ³ÆÈ¡a g¸Ã²úÆ·ÅäÖƳÉÈÜÒº£¬È»ºó¼ÓÈëÉÔ¹ýÁ¿µÄÓô×ËáËữµÄKIÈÜÒº£¬³ä·Ö·´Ó¦ºó£¬¼ÓÈ뼸µÎµí·ÛÈÜÒº£¬È»ºóÓÃ1.0mol¡¤L£­1Na2S2O3±ê×¼ÈÜÒºµÎ¶¨ÖÁÖյ㣬ÏûºÄ±ê×¼ÈÜÒºµÄƽ¾ùÌå»ýΪb L¡£

ÒÑÖª£ºKIO3+5KI+6CH3COOH===3I2+6CH3COOK+3H2O£»KIO4+7KI+8CH3 COOH===4I2+8CH3COOK+4H2O£»I2+2Na2S2O3===2NaI+N2S4O6Ôò¸Ã²úÆ·ÖÐKIO4µÄ°Ù·Öº¬Á¿ÊÇ___________(Mr(KIO3)=214£¬Mr(KIO4)=230£¬Áгö¼ÆËãʽ)¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø