ÌâÄ¿ÄÚÈÝ

¡¾ÌâÄ¿¡¿µçÀëƽºâÊÇÈÜÒº»¯Ñ§ÖеÄÖØÒªÄÚÈÝ£¬Ä³»¯Ñ§ÐËȤС×éÄâÒÔÒÒËáΪÀý̽¾¿ÈõËáµÄÐÔÖÊ¡£

£¨1£©ÊµÑéÒ»£ºÇâÑõ»¯ÄƱê×¼ÈÜÒºµÄÅäÖÆ¡£

ÏÖÒªÅäÖÆ0.1000mol/LNaOH±ê×¼ÈÜÒº250mL£¬ÐèÒªÓõ½µÄ²£Á§ÒÇÆ÷Óв£Á§°ô¡¢ÉÕ±­¡¢½ºÍ·µÎ¹ÜºÍ______£¬²Ù×÷¹ý³ÌÖÐÈç¹ûûÓн«ÉÕ±­µÈµÄÏ´µÓÒºÒ»²¢×ªÈëÈÝÁ¿Æ¿£¬ÔÚÆäËü²Ù×÷¶¼ÕýÈ·µÄÇé¿öÏ£¬½«¸Ã±ê×¼ÈÜÒºÓÃÀ´µÎ¶¨ÏÂÁУ¨2£©ÖеÄδ֪Ũ¶ÈµÄÒÒËáÈÜÒº£¬½«»áʹ²à¶¨µÄ½á¹ûÆ«£ß£¨Ìî¡°¸ß¡±¡¢¡°µÍ¡±¡¢¡°²»Ó°Ï족£©

£¨2£©ÊµÑé¶þ£ºÏÖÓÐһƿÒÒËáÈÜÒº£¬³£ÎÂϲⶨÆäÖÐÒÒËáµÄµçÀëƽºâ³£Êý¡£Éè¼ÆʵÑé·½°¸£¬½«´ý²âÎïÀíÁ¿ºÍ¶ÔÓ¦µÄ²â¶¨·½·¨ÌîдÔÚϱíÖС£

´ý²âÎïÀíÁ¿

²â¶¨·½·¨

¢Ù_______

Á¿È¡25.00mLÒÒËáÈÜÒºÓÚ׶ÐÎÆ¿ÖУ¬µÎ¼Óָʾ¼Á£¬½«0.1000mol/LNaOH±ê×¼ÈÜҺװÈë¼îʽµÎ¶¨¹Ü£¬µÎ¶¨ÖÁÖյ㣬¼Ç¼Êý¾Ý¡£Öظ´µÎ¶¨2´Î¡£

¢ÚH+µÄÎïÖʵÄÁ¿Å¨¶È

È¡ÊÊ×îÒÒËáÈÜÒºÓÚÉÕ±­ÖУ¬ÓÃ______²â¶¨ÈÜÒºpH¡£

¢Û ÉÏÊöʵÑéÖУ¬Èç¹ûÔÚijζÈʱ²âµÃÒÒËáÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶ÈΪ0.1000mol/L£¬pH=3£¬ÔòÔÚ¸ÃζÈʱÒÒËáµÄµçÀëƽºâ³£ÊýΪ____________¡£

£¨3£©ÊµÑéÈý£ºÌ½¾¿ËáµÄÇ¿Èõ¶ÔËáÓëþÌõ·´Ó¦ËÙÂʵÄÓ°Ïì¡£

¢Ù Éè¼ÆʵÑé·½°¸ÈçÏÂ±í£¬±íÖÐc=_______g¡£

񅧏

ËáµÄÖÖÀà

ËáµÄŨ¶È£¨mol/L£©

ËáµÄÌå»ý£¯mL

þÌõÖÊÁ¿/g

l

ÒÒËá

0.5

17.0

2.0

2

ÑÎËá

0.5

17.0

c

¢Ú ʵÑé²½Ö裺

a£©ÏÂͼµÄ×°ÖÃÖУ¬ÔÚÌí¼ÓҩƷ֮ǰ±ØÐë________£»

b£©·´Ó¦¿ªÊ¼ºó£¬__________£»

c£©½«Ëù¼Ç¼µÄÓû¾Ý»æÖƳÉÇúÏßͼ£¨ÏÂͼ£©¡£

¢Û д³öþÓëÒÒËáÈÜÒº·´Ó¦µÄÀë×Ó·½³Ìʽ£º_______________¡£

¢Ü ÃèÊöO¡«5minÑÎËáÓëþÌõ·´Ó¦µÄ·´Ó¦ËÙÂʱ仯¹æÂÉ£º_____________¡£

¡¾´ð°¸¡¿ 250ºÁÉýÈÝÁ¿Æ¿ ¸ß ÒÒËáÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶È pH¼Æ»ò¾«ÃÜpHÊÔÖ½ 1¡Á10-5 2.0 ¼ì²é×°ÖõÄÆøÃÜÐÔ¡£Ã¿¸ô1min¼Ç¼һ´ÎÉú³ÉH2µÄÌå»ý Mg+2CH3COOH=Mg2++2CH3COO- +H2¡ü ÑÎËáÓëþÌõ·´Ó¦¿ªÊ¼½×¶Î·´Ó¦ËÙÂʺܿ죬һ¶Îʱ¼äºó·´Ó¦ËÙÂÊÃ÷ÏÔ¼õС

¡¾½âÎö¡¿£¨1£©ÏÖÒªÅäÖÆ0.1000mol/LNaOH±ê×¼ÈÜÒº250mL£¬ÐèÒªÓõ½µÄ²£Á§ÒÇÆ÷Óв£Á§°ô¡¢ÉÕ±­¡¢½ºÍ·µÎ¹ÜºÍ250mLÈÝÁ¿Æ¿£¬²Ù×÷¹ý³ÌÖÐÈç¹ûûÓн«ÉÕ±­µÈµÄÏ´µÓÒºÒ»²¢×ªÈëÈÝÁ¿Æ¿£¬ÔòÅäÖƵÄNaOHŨ¶ÈÆ«µÍ£¬ÔÚÆäËü²Ù×÷¶¼ÕýÈ·µÄÇé¿öÏ£¬½«¸Ã±ê×¼ÈÜÒºÓÃÀ´µÎ¶¨Î´ÖªÅ¨¶ÈµÄÒÒËáÈÜÒº£¬ÏûºÄ±ê×¼ÒºµÄÌå»ýÆ«´ó£¬½«»áʹ²à¶¨µÄ½á¹ûÆ«¸ß£»

£¨2£©´×ËáµÄµçÀë³Ì¶ÈÊÇÒѵçÀëµÄµç½âÖÊ·Ö×ÓÊýÕ¼Ô­À´×Ü·Ö×ÓÊýµÄ°Ù·Ö±È£¬¹ÊÒªÇó´×ËáµÄµçÀë³Ì¶È£¬¹ÊÓ¦²â³ö´×ËáÈÜÒºµÄŨ¶ÈºÍÈÜÒºÖÐH+µÄŨ¶È£»
¢Ù¸ù¾Ý²â¶¨·½·¨¿ÉÖª£¬´ËΪËá¼îÖк͵樣¬Ëù¸øµÄNaOHÈÜÒºÊDZê×¼Òº£¬¼´´×ËáÊÇ´ý²âÒº£¬Í¨¹ýµÎ¶¨£¬¿É²â³ö´×ËáÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶È£¬ÆäÖмîҺӦʢ·ÅÔÚ¼îʽµÎ¶¨¹ÜÖУ»
¢ÚÓÉÓÚ¢ÙÄܲâ³ö´×ËáÈÜÒºµÄŨ¶È£¬¹Ê´Ë²½ÊµÑéµÄÄ¿µÄÊDzâÁ¿ÈÜÒºÖÐH+µÄŨ¶È£¬¶øÈô½Ï¾«È·µÄ²âÁ¿ÈÜÒºµÄpH£¬Ó¦¸ÃÓÃpH¼Æ»ò¾«ÃÜpHÊÔÖ½£¬·½·¨ÊÇÈ¡ÊÊÁ¿´×ËáÈÜÒºÓÚÉÕ±­ÖУ¬ÓÃpH¼Æ»ò¾«ÃÜpHÊÔÖ½²â¶¨ÈÜÒºpH£»

¢Û´×ËáµÄµçÀëƽºâ³£Êý===1¡Á10-5£»

£¨3£©¢Ù Ҫ̽¾¿ËáµÄÇ¿Èõ¶ÔËáÓëþÌõ·´Ó¦ËÙÂʵÄÓ°Ï죬Ôò±ØÐë±£³ÖÆäËûÓ°Ïì·´Ó¦ËÙÂʵÄÒòËر£³ÖÒ»Ö£¬¹Ê´×ËáºÍÑÎËáµÄŨ¶ÈÓ¦Ïàͬ£¬Ã¾ÌõÖÊÁ¿Ò²Ïàͬ£¬¼´c=2g£»

¢Ú a£©×°ÖÃÁ¬½Óºó£¬ÔÚÌí¼ÓҩƷ֮ǰ±ØÐë¼ìÑé×°ÖÃÆøÃÜÐÔ£»

b£©¾Ýͼ¿ÉÖª£¬ÊÇҪͨ¹ý²âÁ¿ÔÚÏàͬµÄʱ¼ä¶ÎÄÚÊÕ¼¯µ½µÄÇâÆøÌå»ýµÄ´óСÀ´²âÁ¿·´Ó¦ËÙÂÊ£¬¹ÊÔÚ·´Ó¦¿ªÊ¼ºó£¬Ó¦Ã¿¸ô1min¼Ç¼һ´ÎÉú³ÉH2µÄÌå»ý£¬£»

c£©¢Û þÓëÒÒËáÈÜÒº·´Ó¦µÄÀë×Ó·½³ÌʽΪMg+2CH3COOH=Mg2++2CH3COO- +H2¡ü£»

¢Ü ÃèÊöO¡«5minÑÎËáÓëþÌõ·´Ó¦µÄ·´Ó¦ËÙÂʱ仯¹æÂÉ£º´×ËáÓëþÌõ·´Ó¦µÄËÙÂÊËæʱ¼ä±ä»¯²»Ã÷ÏÔ£¬ÑÎËáÓëþÌõ·´Ó¦¿ªÊ¼½×¶Î·´Ó¦ËÙÂʺܿ죬һ¶Îʱ¼äºó·´Ó¦ËÙÂÊÃ÷ÏÔ¼õС¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

¡¾ÌâÄ¿¡¿£¨1£©ÒÒ»ùÏã²ÝÈ©()ÊÇʳƷÌí¼Ó¼ÁµÄÔöÏãÔ­ÁÏ£¬ÆäÏãζ±ÈÏã²ÝÈ©¸üŨÓô¡£Ð´³öÒÒ»ùÏã²ÝÈ©·Ö×ÓÖк¬Ñõ¹ÙÄÜÍŵÄÃû³Æ£º_____¡¢_______¡¢______£¬ºË´Å¹²ÕñÇâÆ×ÏÔʾ¸Ã·Ö×ÓÖÐÓÐ_____ÖÖ²»Í¬ÀàÀïµÄÇâÔ­×Ó¡£

£¨2£©ÒÒ»ùÏã²ÝÈ©µÄͬ·ÖÒì¹¹ÌåAÊÇÒ»ÖÖÓлúËᣬA¿É·¢ÉúÒÔϱ仯£º

ÒÑÖª£ºRCH2OHRCHO

b.Óë±½»·Ö±½ÓÏàÁ¬µÄÆÆÔ­×ÓÉÏÓÐÇâʱ£¬´Ë̼ԭ×Ӳſɱ»ËáÐÔKMnO4ÈÜÒºÑõ»¯ÎªôÈËá¡£¸ù¾ÝÒÔÉÏÐÅÏ¢£¬»Ø´ðÏÂÁÐÎÊÌ⣺

¢ÙÓÉA¡úCµÄ·´Ó¦·½³Ìʽ_____£¬ÊôÓÚ_____(Ìî·´Ó¦ÀàÐÍ)¡£

¢ÚBµÄ½á¹¹¼òʽΪ_____________¡£

¢Ûд³öÔÚ¼ÓÈÈÌõ¼þÏÂCÓëNaOH´¼ÈÜÒº·¢Éú·´Ó¦µÄ»¯Ñ§·½³Ìʽ____________¡£

£¨3£©ÒÒ»ùÏã²ÝÈ©µÄÁíÒ»ÖÖͬ·ÖÒì¹¹ÌåD()ÊÇÒ»ÖÖÒ½Ò©ÖмäÌ壬ÇëÉè¼ÆºÏÀí·½°¸£¬ÓÃÜîÏãÈ©()ºÏ³ÉD¡£(ÆäËûÔ­ÁÏ×ÔÑ¡£¬Ó÷´Ó¦Á÷³Ìͼ±íʾ²¢×¢Ã÷±ØÒªµÄ·´Ó¦Ìõ¼þ)¡£

ÀýÈ磺_________¡£

£¨4£©ÒÒ»ùÏã²ÝÈ©µÄͬ·ÖÒì¹¹ÌåÓкܶàÖÖ£¬Âú×ãÏÂÁÐÌõ¼þµÄͬ·ÖÒì¹¹ÌåÓÐ_____ÖÖ£¬ÆäÖÐÓÐÒ»ÖÖͬ·ÖÒì¹¹ÌåµÄºË´Å¹²ÕñÇâÆ×ÖгöÏÖ4×é·ä£¬ÎüÊÕ·åµÄÃæȨ֮±ÈΪ1:1:2:6£¬¸Ãͬ·ÖÒì¹¹ÌåµÄ¸ø¹¹¼òʽΪ___________¡£

¢ÙÄÜÓëNaHCO3ÈÜÒº·´Ó¦ ¢ÚÓöFeCl3ÈÜÒºÏÔ×ÏÉ«£¬ÇÒÄÜÓëŨäåË®·´Ó¦

¢Û±½»·ÉϵĹÙÄÜÍÅ´¦ÓÚ¶Ôλ ¢Ü±½»·ÉÏÓÐÁ½¸ö¼×»ù

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø