ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿ÎåÖÖ¶ÌÖÜÆÚÔªËØA¡¢B¡¢C¡¢D¡¢EµÄÔ×ÓÐòÊýÒÀ´ÎÔö´ó£¬AºÍCͬÖ÷×壬BºÍ DͬÖ÷×壬CÀë×ÓºÍBÀë×Ó¾ßÓÐÏàͬµÄµç×Ó²ã½á¹¹¡£AºÍB¡¢D¡¢E¾ùÄÜÐγɹ²¼ÛÐÍ»¯ºÏÎï¡£AºÍBÐγɵĻ¯ºÏÎïÔÚË®ÖгʼîÐÔ£¬CºÍEÐγɵĻ¯ºÏÎïÔÚË®ÖгÊÖÐÐÔ¡£»Ø´ðÏÂÁÐÎÊÌ⣺
(1)ÎåÖÖÔªËØÖУ¬Ô×Ӱ뾶×î´óµÄÊÇ_____(ÌîÔªËØ·ûºÅ£©¡£
(2)д³öÓëDͬÖ÷×åÔªËصÄÇ⻯ÎïÖзеã×îó{µÄÎïÖʵç×Óʽ_______¡£
(3)µ¥ÖÊEÓëË®·´Ó¦µÄ²úÎïÖоßÓÐÇ¿Ñõ»¯ÐÔÎïÖʵĽṹʽ_______¡£
(4)AºÍEÐγɵĻ¯ºÏÎïÓëAºÍBÐγɵĻ¯ºÏÎï·´Ó¦£¬²úÎïÖдæÔڵĻ¯Ñ§¼üÀàÐÍΪ_______¡£
(5)CÓëÑõÆøȼÉյIJúÎïͶÈ뵽ˮÖз¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽΪ_______¡£
(6)ÓÉAºÍB¡¢D¡¢EËùÐγɵĹ²¼ÛÐÍ»¯ºÏÎïÖУ¬ÈÈÎȶ¨ÐÔ×î²îµÄÎïÖÊÔÚ×ãÁ¿ÑõÆøÖÐȼÉÕ£¬Ð´³öȼÉյĻ¯Ñ§·½³Ìʽ________ ¡£
¡¾´ð°¸¡¿ Na H£O£Cl Àë×Ó¼üºÍ¹²¼Û¼ü 2Na2O2£«2H2O=4Na£«£«4OH££«O2¡ü 2PH3£«4O2=P2O5£«3H2O
¡¾½âÎö¡¿ÎåÖÖ¶ÌÖÜÆÚÔªËØA¡¢B¡¢C¡¢D¡¢EµÄÔ×ÓÐòÊýÒÀ´ÎÔö´ó£®AºÍBÐγɵĹ²¼Û»¯ºÏÎïÔÚË®ÖгʼîÐÔ£¬¸Ã»¯ºÏÎïΪNH3£¬ÔòAΪÇâÔªËØ¡¢BΪµªÔªËØ£»AºÍCͬ×壬CµÄÔ×ÓÐòÊý´óÓÚµªÔªËØ£¬¹ÊCΪNaÔªËØ£»BºÍDͬ×壬ÔòDΪÁ×ÔªËØ£»CºÍEÐγɵĻ¯ºÏÎïÔÚË®ÖгÊÖÐÐÔ£¬ÔòEΪClÔªËØ£¬
(1)ͬÖÜÆÚ×Ô×ó¶øÓÒÔ×Ӱ뾶¼õС£¬Í¬Ö÷×å×ÔÉ϶øÏÂÔ×Ӱ뾶Ôö´ó£¬¹ÊNaÔªËصÄÔ×Ӱ뾶×î´ó£»
(2)ÓëPͬÖ÷×åµÄNÔªËصÄÇ⻯ÎïNH3£¬Òò·Ö×Ó¼äÓÐÇâ¼ü£¬·Ðµã×îó{£¬¸ÃÎïÖʵç×ÓʽΪ£»
(3)Cl2ÓëË®·´Ó¦Éú³ÉHClºÍHClO£¬ÆäÖÐHClO¾ßÓÐÇ¿Ñõ»¯ÐÔ£¬HClOµÄ½á¹¹Ê½ÎªH£O£Cl£»
(4)AºÍEÐγɵĻ¯ºÏÎïHCl£¬AºÍBÐγɵĻ¯ºÏÎïNH3£¬¶þÕß·´Ó¦Éú³ÉNH4Cl£¬NH4Cl¾§ÌåÖк¬ÓУºÀë×Ó¼ü¡¢¹²¼Û¼ü£»
(5)NaÓëÑõÆøȼÉÕÉú³ÉµÄNa2O2ÓëË®·¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽΪ2Na2O2£«2H2O=4Na£«£«4OH££«O2¡ü £»
(6)·Ç½ðÊôÐÔÔ½Èõ£¬Ç⻯ÎïÔ½²»Îȶ¨£¬N¡¢P¡¢ClÖÐPÔªËطǽðÊôÐÔ×îÈõ£¬PH3×î²»Îȶ¨£¬ÆäÔÚ×ãÁ¿ÑõÆøÖÐȼÉյĻ¯Ñ§·½³ÌʽΪ2PH3£«4O2=P2O5£«3H2O¡£
¡¾ÌâÄ¿¡¿µçÀëƽºâÊÇÈÜÒº»¯Ñ§ÖеÄÖØÒªÄÚÈÝ£¬Ä³»¯Ñ§ÐËȤС×éÄâÒÔÒÒËáΪÀý̽¾¿ÈõËáµÄÐÔÖÊ¡£
£¨1£©ÊµÑéÒ»£ºÇâÑõ»¯ÄƱê×¼ÈÜÒºµÄÅäÖÆ¡£
ÏÖÒªÅäÖÆ0.1000mol/LNaOH±ê×¼ÈÜÒº250mL£¬ÐèÒªÓõ½µÄ²£Á§ÒÇÆ÷Óв£Á§°ô¡¢ÉÕ±¡¢½ºÍ·µÎ¹ÜºÍ______£¬²Ù×÷¹ý³ÌÖÐÈç¹ûûÓн«ÉÕ±µÈµÄÏ´µÓÒºÒ»²¢×ªÈëÈÝÁ¿Æ¿£¬ÔÚÆäËü²Ù×÷¶¼ÕýÈ·µÄÇé¿öÏ£¬½«¸Ã±ê×¼ÈÜÒºÓÃÀ´µÎ¶¨ÏÂÁУ¨2£©ÖеÄδ֪Ũ¶ÈµÄÒÒËáÈÜÒº£¬½«»áʹ²à¶¨µÄ½á¹ûÆ«£ß£¨Ìî¡°¸ß¡±¡¢¡°µÍ¡±¡¢¡°²»Ó°Ï족£©
£¨2£©ÊµÑé¶þ£ºÏÖÓÐһƿÒÒËáÈÜÒº£¬³£ÎÂϲⶨÆäÖÐÒÒËáµÄµçÀëƽºâ³£Êý¡£Éè¼ÆʵÑé·½°¸£¬½«´ý²âÎïÀíÁ¿ºÍ¶ÔÓ¦µÄ²â¶¨·½·¨ÌîдÔÚϱíÖС£
´ý²âÎïÀíÁ¿ | ²â¶¨·½·¨ |
¢Ù_______ | Á¿È¡25.00mLÒÒËáÈÜÒºÓÚ׶ÐÎÆ¿ÖУ¬µÎ¼Óָʾ¼Á£¬½«0.1000mol/LNaOH±ê×¼ÈÜҺװÈë¼îʽµÎ¶¨¹Ü£¬µÎ¶¨ÖÁÖյ㣬¼Ç¼Êý¾Ý¡£Öظ´µÎ¶¨2´Î¡£ |
¢ÚH+µÄÎïÖʵÄÁ¿Å¨¶È | È¡ÊÊ×îÒÒËáÈÜÒºÓÚÉÕ±ÖУ¬ÓÃ______²â¶¨ÈÜÒºpH¡£ |
¢Û ÉÏÊöʵÑéÖУ¬Èç¹ûÔÚijζÈʱ²âµÃÒÒËáÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶ÈΪ0.1000mol/L£¬pH=3£¬ÔòÔÚ¸ÃζÈʱÒÒËáµÄµçÀëƽºâ³£ÊýΪ____________¡£
£¨3£©ÊµÑéÈý£ºÌ½¾¿ËáµÄÇ¿Èõ¶ÔËáÓëþÌõ·´Ó¦ËÙÂʵÄÓ°Ïì¡£
¢Ù Éè¼ÆʵÑé·½°¸ÈçÏÂ±í£¬±íÖÐc=_______g¡£
±àºÅ | ËáµÄÖÖÀà | ËáµÄŨ¶È£¨mol/L£© | ËáµÄÌå»ý£¯mL | þÌõÖÊÁ¿/g |
l | ÒÒËá | 0.5 | 17.0 | 2.0 |
2 | ÑÎËá | 0.5 | 17.0 | c |
¢Ú ʵÑé²½Ö裺
a£©ÏÂͼµÄ×°ÖÃÖУ¬ÔÚÌí¼ÓҩƷ֮ǰ±ØÐë________£»
b£©·´Ó¦¿ªÊ¼ºó£¬__________£»
c£©½«Ëù¼Ç¼µÄÓû¾Ý»æÖƳÉÇúÏßͼ£¨ÏÂͼ£©¡£
¢Û д³öþÓëÒÒËáÈÜÒº·´Ó¦µÄÀë×Ó·½³Ìʽ£º_______________¡£
¢Ü ÃèÊöO¡«5minÑÎËáÓëþÌõ·´Ó¦µÄ·´Ó¦ËÙÂʱ仯¹æÂÉ£º_____________¡£