ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿îѼ°Æ仯ºÏÎïÔÚ»¯¹¤¡¢Ò½Ò©¡¢²ÄÁϵÈÁìÓòÓÐ׏㷺µÄÓ¦Óá£
£¨1£©»ù̬îÑÔ×ӵļ۵ç×ÓÅŲ¼Ê½Îª_____________£¬ÓëîÑͬÖÜÆÚµÄÔªËØÖУ¬»ù̬Ô×ÓµÄδ³É¶Ôµç×ÓÊýÓëîÑÏàͬµÄÓÐ____________ÖÖ¡£
£¨2£©îѱȸÖÇá¡¢±ÈÂÁÓ²£¬ÊÇÒ»ÖÖÐÂÐ˵Ľṹ²ÄÁÏ£¬îѵÄÓ²¶È±ÈÂÁ´óµÄÔÒòÊÇ_________¡£
£¨3£©ÔÚŨµÄTiCl3µÄÑÎËáÈÜÒºÖмÓÈëÒÒÃÑ£¬²¢Í¨ÈëHClÖÁ±¥ºÍ£¬¿ÉµÃµ½ÅäλÊýΪ6¡¢×é³ÉΪTiCl3¡¤6H2OµÄÂÌÉ«¾§Ì壬¸Ã¾§ÌåÖÐÁ½ÖÖÅäÌåµÄÎïÖʵÄÁ¿Ö®±ÈΪ1£º5£¬Ôò¸ÃÅäºÏÀë×ӵĻ¯Ñ§Ê½Îª___________¡£
£¨4£©°ë¼ÐÐĽṹ´ß»¯¼ÁMÄÜ´ß»¯ÒÒÏ©¡¢±ûÏ©¡¢±½ÒÒÏ©µÄ¾ÛºÏ£¬Æä½á¹¹ÈçͼËùʾ¡£
¢Ù×é³ÉMµÄÔªËØÖУ¬µç¸ºÐÔ×î´óµÄÊÇ_________(ÌîÃû³Æ)¡£
¢ÚMÖÐ̼Ô×ÓµÄÔÓ»¯·½Ê½Îª____________¡£
¢ÛMÖв»º¬________(Ìî´úºÅ)¡£
a£®¦Ð¼ü b£®¦Ò¼ü c£®Àë×Ó¼ü d£®Åäλ¼ü
£¨5£©½ðºìʯ(TiO2)ÊǺ¬îѵÄÖ÷Òª¿óÎïÖ®Ò»¡£Æ侧°û½á¹¹(¾§°ûÖÐÏàͬλÖõÄÔ×ÓÏàͬ)ÈçͼËùʾ¡£
¢ÙA¡¢B¡¢C¡¢D4ÖÖ΢Á££¬ÆäÖÐÑõÔ×ÓÊÇ________(Ìî´úºÅ)¡£
¢ÚÈôA¡¢B¡¢CµÄÔ×Ó×ø±ê·Ö±ðΪA(0£¬0£¬0)¡¢B(0.69a£¬0.69a£¬c)¡¢C(a£¬a£¬c)£¬ÔòDµÄÔ×Ó×ø±êΪD(0.19a£¬____£¬___)£»îÑÑõ¼üµÄ¼ü³¤d=______(ÓôúÊýʽ±íʾ)¡£
¢ÛÈô¾§°ûµ×±ß³¤Îªa cm£¬¸ßΪc cm£¬ÔòTiO2¾§ÌåµÄÃܶÈΪ______g/cm3¡£
¡¾´ð°¸¡¿3d24s2 3 TiÔ×ӵļ۵ç×ÓÊý±ÈAl¶à£¬½ðÊô¼ü¸üÇ¿ [TiCl(H2O)5]2+ Ñõ sp2¡¢sp3 c BD 0.81a 0.5c 0.31¡Áa
¡¾½âÎö¡¿
(5)¸ù¾Ý¾§°û½á¹¹·ÖÎö£¬ËÄ·½¾§°ûÖУ¬¶¥µãÁ£×ÓÕ¼£¬ÃæÉÏÁ£×ÓÕ¼
£¬ÄÚ²¿Á£×ÓΪÕû¸ö¾§°ûËùÓУ¬¾§Ì廯ѧʽΪTiO2£¬OµÄÊýÄ¿ÊÇTiµÄÁ½±¶£¬Ôò±ØÓÐ2¸öÑõÔ×ÓλÓÚ¾§°ûÄÚ£¬¾§°ûµÄÉÏ¡¢Ïµ×ÃæÉϸ÷ÓÐ2¸öÑõÔ×Ó¡£
(1)îÑΪ22ºÅÔªËØ£¬Î»ÓÚµÚËÄÖÜÆÚ£¬»ù̬îÑÔ×ӵļ۵ç×ÓÅŲ¼Ê½Îª3d24s2£¬»ù̬îÑÔ×Óδ³É¶Ôµç×ÓΪ3d¹ìµÀµÄ2¸öµç×Ó£¬µÚËÄÖÜÆÚÖлù̬Ô×Óδ³É¶Ôµç×ÓÊýΪ2µÄ»¹Óм۵ç×ÓÅŲ¼Îª3d84s2µÄNi¡¢3d104s24p2µÄGe¡¢3d104s24p4µÄSe¹²3ÖÖ£¬¹Ê´ð°¸Îª£º3d24s2£»3£»
(2)TiÔ×ӵļ۵ç×ÓÊý±ÈAl¶à£¬½ðÊô¼ü¸üÇ¿£¬µ¼ÖÂîѵÄÓ²¶È±ÈÂÁ´ó£¬¹Ê´ð°¸Îª£ºTiÔ×ӵļ۵ç×ÓÊý±ÈAl¶à£¬½ðÊô¼ü¸üÇ¿£»
(3)ÅäλÊýΪ6¡¢×é³ÉΪTiCl36H2OµÄÂÌÉ«¾§Ì壬¸Ã¾§ÌåÖÐÁ½ÖÖÅäÌåµÄÎïÖʵÄÁ¿Ö®±ÈΪ1:5£¬¶ø¾§ÌåÖÐÖ»º¬ÓÐ3¸öCl£¬ËùÒÔÅäÌåÊýÄ¿¶àµÄÊÇH2O£¬H2OºÍCl±ÈֵΪ5:1£¬ËùÒÔ¸ÃÅäÀë×ӵĻ¯Ñ§Ê½Îª[TiCl(H2O)5]2+£¬¹Ê´ð°¸Îª£º[TiCl(H2O)5]2+£»
(4)¢ÙMÖк¬ÓеÄÔªËØÓУºTi¡¢Cl¡¢O¡¢C¡¢H£¬ÆäÖе縺ÐÔ×î´óµÄÊÇO£¬Ãû³ÆΪÑõÔªËØ£¬¹Ê´ð°¸Îª£ºÑõ£»
¢ÚMÖÐC´æÔÚµ¥¼üºÍË«¼ü£¬Ç°ÕßΪsp3ÔÓ»¯£¬ºóÕßΪsp2ÔÓ»¯£¬¹Ê´ð°¸Îª£ºsp2¡¢sp3£»
¢ÛMÖк¬Óй²¼Û¼ü£¬Åäλ¼ü£¬¹²¼Ûµ¥¼üΪ¦Ò¼ü£¬¹²¼ÛË«¼üÖÐÒ»¸ùΪ¦Ò¼ü£¬Ò»¸ùΪ¦Ð¼ü£¬ËùÒÔMÖв»º¬Àë×Ó¼ü£¬¹Ê´ð°¸Îª£ºc£»
(5)¢Ù¸ù¾Ý¾§°û½á¹¹·ÖÎö£¬ËÄ·½¾§°ûÖУ¬¶¥µãÁ£×ÓÕ¼£¬ÃæÉÏÁ£×ÓÕ¼
£¬ÄÚ²¿Á£×ÓΪÕû¸ö¾§°ûËùÓУ¬¾§Ì廯ѧʽΪTiO2£¬OµÄÊýÄ¿ÊÇTiµÄÁ½±¶£¬ÔòÓÐ2¸öÑõÔ×ÓλÓÚ¾§°ûÄÚ£¬¾§°ûµÄÉÏ¡¢Ïµ×ÃæÉϸ÷ÓÐ2¸öÑõÔ×Ó£¬¸öÊýΪ2+4¡Á
=4 £¬TiλÓÚÌåÐĺͶ¥µã£¬¸öÊýΪ1+8¡Á
=2£¬ÔòA¡¢B¡¢C¡¢DËÄÖÖ΢Á££¬ÆäÖÐÑõÔ×ÓÊÇB¡¢D£¬¹Ê´ð°¸Îª£ºBD£»
¢ÚA¡¢B¡¢CµÄÔ×Ó×ø±ê·Ö±ðΪA(0£¬0£¬0)¡¢B(0.69a£¬0.69a£¬c)¡¢C(a£¬a£¬c)£¬½ðºìʯ¾§°ûÖУ¬Ti´¦ÓÚÌåÐÄ£¬ÌåÐÄTiÖÜΧÓÐ8¸öOÐγɰËÃæÌå½á¹¹£¬Éϵ×Ãæ½á¹¹Îª£º£¬Öмä°ë²ãµÄ½á¹¹Îª
£¬l¼´ÎªîÑÑõ¼üµÄ¼ü³¤d£¬¸ù¾ÝÉϵ×Ãæ½á¹¹£¬d=(a0.69a)¡Á
=0.31¡Á
a£¬D´¦Óڸߵİ봦ËùÔÚµÄƽÃ棬¸ù¾ÝÖмä°ë²ãµÄ½á¹¹·ÖÎö£¬l=d=0.31¡Á
a£¬ÒÑÖªDµÄx×ø±êΪ0.19a£¬Ôòy=a0.19a=0.81a£¬ËùÒÔDµÄ×ø±êΪ(0.19a£¬0.81a£¬0.5c)£¬¹Ê´ð°¸Îª£º0.81a£»0.5c£»0.31¡Á
a£»
¢ÛÓÉ¢Ù¿ÉÖª£¬1¸ö¾§°ûÖк¬2¸öTiÔ×Ó¡¢4¸öOÔ×Ó£¬¹Ê1¸ö¾§°ûµÄÖÊÁ¿=g=
g£¬1¸ö¾§°ûµÄÌå»ý=acm¡Áacm¡Áccm=a2ccm3£¬ËùÒÔÃܶȦÑ=
=
g¡¤cm-3£¬¹Ê´ð°¸Îª£º
¡£
![](http://thumb2018.1010pic.com/images/loading.gif)
¡¾ÌâÄ¿¡¿ÀûÓÃË®îÜ¿ó(Ö÷Òª³É·ÖΪCo2O3£¬º¬ÉÙÁ¿Fe2O3¡¢Al2O3¡¢MnO¡¢MgO¡¢CaO¡¢SiO2µÈ)¿ÉÒÔÖÆÈ¡¶àÖÖ»¯¹¤ÊÔ¼Á¡£ÏÂͼÊDzÝËáîܾ§ÌåºÍÂÈ»¯îܾ§ÌåµÄÖƱ¸Á÷³Ì£¬»Ø´ðÏÂÁÐÎÊÌ⣺
ÒÑÖª£º¢Ù½þ³öÒºÖк¬ÓеÄÑôÀë×ÓÖ÷ÒªÓÐH+¡¢Co2+¡¢Fe2+¡¢Mn2+¡¢Al3+¡¢Mg2+¡¢Ca2+µÈ¡£
¢ÚÁ÷³ÌÖв¿·ÖÑôÀë×ÓÒÔÇâÑõ»¯ÎïÐÎʽ³ÁµíʱÈÜÒºµÄpH¼û±í£º
³ÁµíÎï | Fe(OH)3 | Fe(OH)2 | Co(OH)2 | Al(OH)3 | Mn(OH)2 |
¿ªÊ¼³Áµí | 2.7 | 7.6 | 7.6 | 4.0 | 7.7 |
ÍêÈ«³Áµí | 3.7 | 9.6 | 9.2 | 5.2 | 9.8 |
£¨1£©½þ³ö¹ý³ÌÖÐCo2O3·¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽΪ______________¡£
£¨2£©1molNaClO3ÔÚ½þ³öÒºÖз¢Éú·´Ó¦Ê±£¬×ªÒƵĵç×ÓÊýΪ_________¡£
£¨3£©¼ÓÈëNa2CO3µ÷pHÖÁ5.2Ö»µÃµ½Á½ÖÖ³Áµí£¬Ôò³ÁµíIµÄ³É·ÖΪ______________£¨Ìѧʽ£¬ÏÂͬ£©£»ÝÍÈ¡¼Á²ãº¬ÃÌÔªËØ£¬Ôò³Áµí¢òµÄÖ÷Òª³É·ÖΪ______________¡£
£¨4£©²Ù×÷¢ñ°üÀ¨£º½«Ë®²ã¼ÓÈëŨÑÎËáµ÷ÕûpHΪ2¡«3¡¢________¡¢________¡¢¹ýÂË¡¢Ï´µÓ¡¢¼õѹºæ¸ÉµÈ¹ý³Ì¡£
£¨5£©½«5.49g²ÝËáîܾ§Ìå(CoC2O4¡¤2H2O)ÖÃÓÚ¿ÕÆøÖмÓÈÈ£¬ÊÜÈȹý³ÌÖУ¬²»Í¬Î¶ȷ¶Î§Äڵõ½Ò»ÖÖ²»Í¬µÄ¹ÌÌåÎïÖÊ£¬ÆäÖÊÁ¿Èç±í¡£
ζȷ¶Î§/¡æ | ¹ÌÌåÖÊÁ¿/g |
150¡«210 | 4.41 |
290¡«320 | 2.41 |
¾²â¶¨£¬Õû¸öÊÜÈȹý³Ì²úÉúµÄÆøÌåÖ»ÓÐË®ÕôÆøºÍCO2£¬Ôò290¡«320¡æ·¶Î§ÄÚ£¬Ê£Óà¹ÌÌåÎïÖʵĻ¯Ñ§Ê½Îª______________¡£