ÌâÄ¿ÄÚÈÝ

ij¹¤Òµ·ÏË®½öº¬Ï±íÖеÄijЩÀë×Ó£¬ÇÒ¸÷ÖÖÀë×ÓµÄÎïÖʵÄÁ¿Å¨¶ÈÏàµÈ£¬¾ùΪ0.1 mol/L(´ËÊýÖµºöÂÔË®µÄµçÀë¼°Àë×ÓµÄË®½â)¡£
ÑôÀë×Ó
K£«¡¡Ag£«¡¡Mg2£«¡¡Cu2£«¡¡Al3£«¡¡NH4+
ÒõÀë×Ó
Cl£­¡¡CO32¡ª¡¡NO3¡ª¡¡SO42¡ª¡¡I£­
 
¼×ͬѧÓû̽¾¿·ÏË®µÄ×é³É£¬½øÐÐÁËÈçÏÂʵÑ飺
¢ñ.È¡¸ÃÎÞÉ«ÈÜÒº5 mL£¬µÎ¼ÓÒ»µÎ°±Ë®ÓгÁµíÉú³É£¬ÇÒÀë×ÓÖÖÀàÔö¼Ó¡£
¢ò.Óò¬Ë¿ÕºÈ¡ÈÜÒº£¬ÔÚ»ðÑæÉÏ×ÆÉÕ£¬Í¸¹ýÀ¶É«îܲ£Á§¹Û²ì£¬ÎÞ×ÏÉ«»ðÑæ¡£
¢ó.ÁíÈ¡ÈÜÒº¼ÓÈë¹ýÁ¿ÑÎËᣬÓÐÎÞÉ«ÆøÌåÉú³É£¬¸ÃÎÞÉ«ÆøÌåÓö¿ÕÆø±ä³Éºì×ØÉ«¡£
¢ô.Ïò¢óÖÐËùµÃµÄÈÜÒºÖмÓÈëBaCl2ÈÜÒº£¬Óа×É«³ÁµíÉú³É¡£
ÇëÍƶϣº
(1)ÓÉ¢ñ¡¢¢òÅжϣ¬ÈÜÒºÖÐÒ»¶¨²»º¬ÓеÄÑôÀë×ÓÊÇ___________________________________¡£
(2)¢óÖмÓÈëÑÎËáÉú³ÉÎÞÉ«ÆøÌåµÄÀë×Ó·½³ÌʽÊÇ________________________¡£
(3)¼×ͬѧ×îÖÕÈ·¶¨Ô­ÈÜÒºÖÐËùº¬ÑôÀë×ÓÓÐ________£¬ÒõÀë×ÓÓÐ________£»²¢¾Ý´ËÍƲâÔ­ÈÜÒºÓ¦¸Ã³Ê________ÐÔ£¬Ô­ÒòÊÇ____________________________(ÇëÓÃÀë×Ó·½³Ìʽ˵Ã÷)¡£
(4)ÁíÈ¡100 mLÔ­ÈÜÒº£¬¼ÓÈë×ãÁ¿µÄNaOHÈÜÒº£¬´Ë¹ý³ÌÖÐÉæ¼°µÄÀë×Ó·½³ÌʽΪ____________________________¡£³ä·Ö·´Ó¦ºó¹ýÂË£¬Ï´µÓ£¬×ÆÉÕ³ÁµíÖÁºãÖØ£¬µÃµ½µÄ¹ÌÌåÖÊÁ¿Îª________g¡£
(1)K£«¡¢NH4+¡¢Cu2£«
(2)6I£­£«2NO3¡ª£«8H£«=3I2£«2NO¡ü£«4H2O
(3)Mg2£«¡¢Al3£«¡¡Cl£­¡¢NO3¡ª¡¢SO42¡ª¡¢I£­¡¡Ëá¡¡Mg2£«£«2H2O??Mg(OH)2£«2H£«¡¢Al3£«£«3H2OAl(OH)3£«3H£«
(4)Mg2£«£«2OH£­=Mg(OH) 2¡ý¡¢Al3£«£«4OH£­=AlO2¡ª£«2H2O¡¡0.4
(1)¸ù¾Ý¢ñ£¬ÈÜҺΪÎÞÉ«£¬ÔòÈÜÒºÖв»º¬Cu2£«£¬Éú³É³ÁµíºóÀë×ÓÖÖÀàÔö¼Ó£¬ËµÃ÷Ô­ÈÜÒºÖв»º¬NH4+£»¸ù¾Ý¢ò¿ÉÈ·¶¨ÈÜÒºÖв»º¬K£«¡£(2)¸ù¾Ý¢óµÄÃèÊö¿ÉÈ·¶¨Éú³ÉµÄÎÞÉ«ÆøÌåΪNO£¬ÔòÔ­ÈÜÒºÖÐÒ»¶¨º¬ÓÐNO3¡ªºÍI£­£¬¸ù¾ÝתÒƵç×ÓÊýÄ¿ÏàµÈ¡¢µçºÉÊغã¿Éд³öÀë×Ó·½³Ìʽ¡£(3)½áºÏ¢ôºÍÈÜÒºÖи÷Àë×ÓŨ¶ÈÏàµÈ¿ÉÈ·¶¨ÈÜÒºÖк¬ÓеÄÒõÀë×ÓΪSO42¡ª¡¢Cl£­¡¢NO3¡ªºÍÈÜÒºÏÔËáÐÔ£¬ÊÇMg2£«¡¢Al3£«Ë®½âµÄÔµ¹Ê¡£(4)¼ÓÈëNaOHÈÜÒº£¬Mg2£«×ª»¯ÎªMg(OH)2³Áµí£¬Al3£«×îºóת»¯ÎªNaAlO2£¬×îÖյõ½0.01 mol Mg(OH)2³Áµí£¬×ÆÉÕÖÁºãÖصõ½0.4 g MgO¡£
µã²¦£º±¾Ìâ½áºÏ·ÏË®µÄ³É·Ö¿¼²éÀë×Ó¼ìÑéºÍÀë×Ó·½³ÌʽµÄÊéд£¬ÒâÔÚ¿¼²é¿¼Éú×ۺϷÖÎöÎÊÌâµÄÄÜÁ¦ºÍ¼ÆËãÄÜÁ¦¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
ÔÚÔÖºóÖؽ¨ÖУ¬ÒûÓÃË®°²È«Õ¼Óм«ÎªÖØÒªµÄµØλ£¬Ä³Ñо¿Ð¡×éÌáÈ¡Èý´¦±»ÎÛȾµÄˮԴ½øÐзÖÎö£¬²¢¸ø³öÁËÈçÏÂʵÑéÐÅÏ¢£ºÆäÖÐÒ»´¦±»ÎÛȾµÄˮԴº¬ÓÐA¡¢BÁ½ÖÖÎïÖÊ£¬Ò»´¦º¬ÓÐC¡¢DÁ½ÖÖÎïÖÊ£¬Ò»´¦º¬ÓÐEÎïÖÊ£¬A¡¢B¡¢C¡¢D¡¢EÎåÖÖ³£¼û»¯ºÏÎﶼÊÇÓÉϱíÖеÄÀë×ÓÐγɵģº
ÑôÀë×Ó
K£«¡¢Na£«¡¢Cu2£«¡¢Al3£«
ÒõÀë×Ó
SO42¡ª¡¢HCO3¡ª¡¢NO3¡ª¡¢OH£­
 
ΪÁ˼ø±ðÉÏÊö»¯ºÏÎ·Ö±ðÍê³ÉÒÔÏÂʵÑ飬Æä½á¹ûÊÇ£º
¢Ù½«ËüÃÇÈÜÓÚË®ºó£¬DΪÀ¶É«ÈÜÒº£¬ÆäËû¾ùΪÎÞÉ«ÈÜÒº¡£
¢Ú½«EÈÜÒºµÎÈëµ½CÈÜÒºÖУ¬³öÏÖ°×É«³Áµí£¬¼ÌÐøµÎ¼Ó³ÁµíÈܽ⡣
¢Û½øÐÐÑæÉ«·´Ó¦ÊµÑ飬ֻÓÐB¡¢Cº¬ÓмØÀë×Ó¡£
¢ÜÔÚ¸÷ÈÜÒºÖмÓÈëBa(NO3)2ÈÜÒº£¬ÔÙ¼ÓÈë¹ýÁ¿Ï¡ÏõËᣬAÖзųöÎÞÉ«ÆøÌ壬C¡¢DÖвúÉú°×É«³Áµí¡£
¢Ý½«B¡¢DÁ½ÈÜÒº»ìºÏ£¬Î´¼û³Áµí»òÆøÌåÉú³É¡£
¸ù¾ÝÉÏÊöʵÑéÏÖÏóÌîдÏÂÁпհףº
(1)д³öB¡¢C¡¢DµÄ»¯Ñ§Ê½£ºB________¡¢C________¡¢D________¡£
(2)½«º¬1 mol AµÄÈÜÒºÓ뺬1 mol EµÄÈÜÒº·´Ó¦ºóÕô¸É£¬½öµÃµ½Ò»ÖÖ»¯ºÏÎ¸Ã»¯ºÏÎïΪ________¡£
(3)д³öʵÑé¢Ú·¢Éú·´Ó¦µÄÀë×Ó·½³Ìʽ________________________________________
(4)C³£ÓÃ×÷¾»Ë®¼Á£¬ÓÃÀë×Ó·½³Ìʽ±íʾÆ侻ˮԭÀí_______________________________

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø