ÌâÄ¿ÄÚÈÝ

ÔÚÀë×ÓŨ¶È¶¼Îª0.1 mol/LµÄÏÂÁÐÈÜÒºÖУ¬¼ÓÈ루»òͨÈ룩ijÎïÖʺ󣬷¢Éú·´Ó¦ÏȺó˳ÐòÕýÈ·µÄÊÇ
A£®ÔÚº¬Fe3£«¡¢Cu2£«¡¢H£«µÄÈÜÒºÖмÓÈëп·Û£ºCu2£«¡¢Fe3£«¡¢H£«
B£®ÔÚº¬I£­¡¢SO32-¡¢Br£­µÄÈÜÒºÖ⻶ÏͨÈëÂÈÆø£ºI£­¡¢Br£­¡¢SO32-
C£®ÔÚº¬AlO2-¡¢SO32-¡¢OH£­µÄÈÜÒºÖÐÖðµÎ¼ÓÈëÁòËáÇâÄÆÈÜÒº£ºOH£­¡¢AlO2-¡¢SO32-
D£®ÔÚº¬Fe3£«¡¢H£«¡¢NH4+µÄÈÜÒºÖÐÖð½¥¼ÓÈëÉÕ¼îÈÜÒº£ºH£«¡¢NH4+¡¢Fe3£«
C

ÊÔÌâ·ÖÎö£ºA¡¢ZnÊ×ÏÈÓëFe3+·´Ó¦£¬´íÎó£»B¡¢ÂÈÆøÊ×ÏÈÓëSO32?·´Ó¦£¬´íÎó£»C¡¢ÓëH+·´Ó¦µÄÄÜÁ¦OH£­>AlO2->SO32-£¬ÕýÈ·£»D¡¢ÔÚº¬Fe3£«¡¢H£«¡¢NH4+µÄÈÜÒºÖÐÖð½¥¼ÓÈëÉÕ¼îÈÜÒº£ºH£«¡¢Fe3£«¡¢NH4+£¬´íÎó¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
¢ñ.£¨4·Ö£©ÊµÑéÊÒÓÐһƿ³ÎÇåµÄÈÜÒº£¬ÊµÑéÈËԱȷ¶¨ÆäÖпÉÄܺ¬ÓÐNH4+¡¢K+¡¢Na+¡¢Mg2+¡¢Ba2+¡¢Al3+¡¢Fe3+¡¢Cl-¡¢I-¡¢NO3-¡¢CO32-¡¢SO42-£¬È¡¸ÃÈÜÒº½øÐÐÏÂÁÐʵÑ飺
¢ÙÈ¡pHÊÔÖ½¼ìÑ飬±íÃ÷ÈÜÒº³ÊÇ¿ËáÐÔ¡£
¢ÚÈ¡³ö²¿·ÖÈÜÒº£¬¼ÓÈëÉÙÁ¿CCl4¼°ÊýµÎÐÂÖÆÂÈË®£¬¾­Õñµ´ºóCCl4²ã³Ê×ϺìÉ«¡£
¢ÛÁíÈ¡²¿·ÖÈÜÒºÖð½¥¼ÓÈëNaOHÈÜÒº£¬Ê¹ÈÜÒº´ÓËáÐÔÖð½¥±äΪ¼îÐÔ£¬Ôڵμӹý³ÌÖк͵μÓÍê±Ïºó£¬ÈÜÒº¾ùÎÞ³Áµí²úÉú¡£
¢ÜÈ¡²¿·ÖÉÏÊö¼îÐÔÈÜÒº¼ÓNa2CO3ÈÜÒº£¬Óа×É«³ÁµíÉú³É¡£
¢Ý½«¢ÛµÃµ½µÄ¼îÐÔÈÜÒº¼ÓÈÈ£¬ÓÐÆøÌå·Å³ö£¬¸ÃÆøÌåÄÜʹʪÈóµÄºìɫʯÈïÊÔÖ½±äÀ¶¡£
¢ÞÏò¢ÚµÄË®²ãÖмÓÈëHNO3ËữµÄAgNO3ÈÜÒºÓа×É«³Áµí¡£
¸ù¾ÝÉÏÊöʵÑéÊÂʵȷ¶¨£¬ÇëÄãÅжϸÃÈÜÒºÖÐ
£¨1£©¿Ï¶¨´æÔÚµÄÀë×ÓÊÇ                                         £»
£¨2£©²»ÄÜÈ·¶¨ÊÇ·ñ´æÔÚµÄÀë×ÓÊÇ                                   ¡£
¢ò. £¨6·Ö£©¶þÑõ»¯Îø(SeO2)ÊÇÒ»ÖÖÑõ»¯¼Á£¬Æä±»»¹Ô­ºóµÄµ¥ÖÊÎø¿ÉÄܳÉΪ»·¾³ÎÛȾÎͨ¹ýÓëŨHNO3»òŨH2SO4·´Ó¦Éú³ÉSeO2ÒÔ»ØÊÕSe¡£Íê³ÉÏÂÁÐÌî¿Õ£º
£¨1£©SeºÍŨHNO3·´Ó¦µÄ»¹Ô­²úÎïΪNOºÍNO2£¬ÇÒNOºÍNO2µÄÎïÖʵÄÁ¿Ö®±ÈΪ1£º1£¬Ð´³öSeºÍŨHNO3µÄ·´Ó¦·½³Ìʽ                                  ¡£
£¨2£©ÒÑÖª£ºSe+2H2SO4(Ũ)¡ú2SO2¡ü+SeO2+2H2O£»2SO2+SeO2+2H2O¡úSe+2SO42-+4H+
SeO2¡¢H2SO4(Ũ)¡¢SO2µÄÑõ»¯ÐÔÓÉÇ¿µ½ÈõµÄ˳ÐòÊÇ                     ¡£
£¨3£©»ØÊյõ½µÄSeO2µÄº¬Á¿£¬¿ÉÒÔͨ¹ýÏÂÃæµÄ·½·¨²â¶¨£º
¢ÙSeO2+ 4KI+ 4HNO3¡úSe+2I2+ 4KNO3+2H2O ¢ÚI2+2Na2S2O3¡úNa2S4O6+2NaI
ʵÑéÖУ¬×¼È·³ÆÁ¿SeO2ÑùÆ·0.1500g£¬ÏûºÄÁË0.2000 mol/LµÄNa2S2O3ÈÜÒº25.00 mL£¬Ëù²â¶¨µÄÑùÆ·ÖÐSeO2µÄÖÊÁ¿·ÖÊýΪ                   ¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø