ÌâÄ¿ÄÚÈÝ

£¨9·Ö£©ÇâÆø×÷ΪһÖÖÇå½àÄÜÔ´£¬±ØÐë½â¾öËüµÄ´¢´æÎÊÌ⣬  C60¿ÉÓÃ×÷´¢Çâ²ÄÁÏ¡£
£¨1£©ÒÑÖª½ð¸ÕʯÖÐC¡ªC¼üµÄ¼ü³¤Îª154.45 pm£¬C60ÖÐC¡ªC¼üµÄ¼ü³¤Îª145 pmºÍ140 pm£¬ÓÐͬѧ¾Ý´ËÈÏΪC60µÄÈÛµã¸ßÓÚ½ð¸Õʯ£¬ÄãÈÏΪÊÇ·ñÕýÈ·²¢²ûÊöÀíÓÉ____________________________                              ______¡£
£¨2£©¿Æѧ¼Ò°ÑC60ºÍK²ôÔÓÔÚÒ»ÆðÖÆÔìÁËÒ»ÖÖ¸»ÀÕÏ©»¯ºÏÎÆ侧°ûÈçͼËùʾ£¬¸ÃÎïÖÊÔÚµÍÎÂʱÊÇÒ»ÖÖ³¬µ¼Ìå¡£¸ÃÎïÖÊÖÐKÔ­×ÓºÍC60·Ö×ӵĸöÊý±ÈΪ______________________¡£

£¨3£©¼ÌC60ºó£¬¿Æѧ¼ÒÓֺϳÉSi60¡¢N60£¬C¡¢Si¡¢NÔ­×ӵ縺ÐÔÓÉ´óµ½Ð¡µÄ˳ÐòÊÇ________  __¡£Si60·Ö×ÓÖÐÿ¸ö¹èÔ­×ÓÖ»¸úÏàÁÚµÄ3¸ö¹èÔ­×ÓÐγɹ²¼Û¼ü£¬ÇÒÿ¸ö¹èÔ­×Ó×îÍâ²ã¶¼Âú×ã8µç×ÓÎȶ¨½á¹¹£¬ÔòSi60·Ö×ÓÖЦмüµÄÊýĿΪ__________¡£
£¨1£©²»ÕýÈ·£¬C60ÊÇ·Ö×Ó¾§Ì壬ÈÛ»¯Ê±²»ÐèÆÆ»µ»¯Ñ§¼ü  £¨3·Ö£©
£¨2£©3¡Ã1¡¡  £¨2·Ö£© £¨3£©N£¾C£¾Si¡¡30 £¨¸÷2·Ö£©
£¨1£©½ð¸ÕʯÊÇÔ­×Ó¾§Ì壬¶øC60ÊÇ·Ö×Ó¾§Ì壬ÈÛ»¯Ê±²»ÐèÆÆ»µ»¯Ñ§¼ü£¬ËùÒÔÈÛµãµÍÓÚ½ð¸ÕʯµÄ¡£
£¨2£©¸ù¾Ý¾§°û¿ÉÖªC60ÓÐ8¸öλÓÚ¶¥µã£¬1¸öÔÚÖÐÐÄ£¬ËùÒÔ¸öÊýÊÇ8¡Á1/8£«1£½2¡£¶ø12¸ö¼ØÔ­×ÓÈ«²¿Î»ÓÚÃæÉÏ£¬ËùÒÔ¸öÊýÊÇ12¡Á1/2£½6£¬ÔòKÔ­×ÓºÍC60·Ö×ӵĸöÊý±ÈΪ3¡Ã1¡£
£¨3£©·Ç½ðÊôÐÔԽǿ£¬µç¸ºÐÔÔ½´ó£¬ËùÒԵ縺ÐÔÓÉ´óµ½Ð¡µÄ˳ÐòÊÇN£¾C£¾Si¡£ÒªÂú×ãÿ¸ö¹èÔ­×Ó×îÍâ²ã¶¼Âú×ã8µç×ÓÎȶ¨½á¹¹£¬Ôò¹èÔ­×ÓÐγɵÄ3¸ö¹²¼Û¼üÖÐÓÐ2¸öÊǵ¥¼ü£¬1¸öË«¼ü¡£¹èÔ­×ӵļ۵ç×ÓÊÇ4£¬ËùÒÔÐγɵÄË«¼üÊýÊÇ£¬ËùÒԦмüµÄÊýÄ¿30¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
£¨13·Ö£©Ï±íΪÖÜÆÚ±íµÄÒ»²¿·Ö£¬±íÖÐËùÁеÄ×Öĸ·Ö±ð´ú±íÒ»ÖÖ»¯Ñ§ÔªËØ¡£
a
 
 
 
 
 
 
 
 
b
c
d
 
 
 
 
 
 
 
e
f
 
 
 
 
 
 
 
g
 
h
 
 
 
 
 
 
 
 
 
 
Óû¯Ñ§ÓÃÓï»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©Ð´³öÔªËØgµÄ»ù̬ԭ×ÓºËÍâµç×ÓÅŲ¼Ê½___________________________£¬
h2+ÖÐδ³É¶Ôµç×ÓÊýΪ                ¡£
£¨2£©ÔÚb2a2·Ö×ÓÖУ¬ÔªËØbΪ    ÔÓ»¯£¬¸Ã·Ö×ÓÊÇ       ·Ö×Ó£¨Ìî¡°¼«ÐÔ¡±»ò¡°·Ç¼«ÐÔ¡±£©£¬¸Ã·Ö×ÓÖЦҼüºÍ¦Ð¼üµÄÊýÄ¿±ÈΪ          ¡£
£¨3£© bd2Óëbf2±È½Ï£¬·Ðµã½Ï¸ßµÄÊÇ_______£¨Ìî·Ö×Óʽ£©£¬Ô­ÒòÊÇ                    ¡£
£¨4£©ÏÂÁйØÓÚÔªËØÔÚÔªËØÖÜÆÚ±íÖеÄλÖÃÒÔ¼°ÔªËØÔ­×ÓµÄÍâΧµç×ÓÅŲ¼ÌصãµÄÓйØÐðÕýÈ·ÊÇ             ¡£
A£®hλÓÚÔªËØÖÜÆÚ±íÖеÚËÄÖÜÆÚµÚVIII×壬ÊôÓÚdÇøÔªËØ
B£®eµÄ»ù̬ԭ×ÓÖУ¬3pÄܼ¶Îª°ë³äÂú£¬ÊôÓÚpÇøÔªËØ
C£®×îÍâ²ãµç×ÓÅŲ¼Ê½Îª4s2£¬Ò»¶¨ÊôÓÚIIA×å
D£®×îÍâ²ãµç×ÓÅŲ¼Ê½Îªns2np1£¬¸ÃÔªËØ¿ÉÄÜÊÇ¢óA×å»ò¢óB×å
£¨5£©¿ÆѧÑо¿±íÃ÷£¬ÔªËØbÓëÔªËØc¿ÉÒÔÐγÉÒ»ÖÖ³¬Ó²¡¢ÄÍÄ¥¡¢Ä͸ßεÄÐÂÐÍÎÞ»ú·Ç½ðÊô²ÄÁÏ£¬Æ仯ѧʽΪ          £¬ÆäÈÛµã±È½ð¸Õʯ           £¨Ìî¡°¸ß¡±»ò¡°µÍ¡±£©¡£
£¨14·Ö£©µªÔªËØ¿ÉÒÔÐγɶàÖÖ»¯ºÏÎï¡£»Ø´ðÒÔÏÂÎÊÌ⣺
£¨1£©»ù̬µªÔ­×ӵļ۵ç×ÓÅŲ¼Ê½ÊÇ_________________¡£
£¨2£©C¡¢N¡¢OÈýÖÖÔªËصÚÒ»µçÀëÄÜ´Ó´óµ½Ð¡µÄ˳ÐòÊÇ____________¡£
£¨3£©ëÂ(N2H4)·Ö×Ó¿ÉÊÓΪNH3·Ö×ÓÖеÄÒ»¸öÇâÔ­×Ó±»£­NH2£¨°±»ù£©È¡´úÐγɵÄÁíÒ»ÖÖµªµÄÇ⻯Îï¡£
¢ÙNH3·Ö×ӵĿռ乹ÐÍÊÇ_______________£»N2H4·Ö×ÓÖеªÔ­×Ó¹ìµÀµÄÔÓ»¯ÀàÐÍÊÇ___________¡£
¢Úë¿ÉÓÃ×÷»ð¼ýȼÁÏ£¬È¼ÉÕʱ·¢ÉúµÄ·´Ó¦ÊÇ£º
N2O4(l)£«2N2H4(l)===3N2(g)£«4H2O(g)   ¡÷H=£­1038.7kJ¡¤mol£­1
Èô¸Ã·´Ó¦ÖÐÓÐ4mol N£­H¼ü¶ÏÁÑ£¬ÔòÐγɵĦмüÓÐ________mol¡£
¢ÛëÂÄÜÓëÁòËá·´Ó¦Éú³ÉN2H6SO4¡£N2H6SO4¾§ÌåÀàÐÍÓëÁòËáï§Ïàͬ£¬ÔòN2H6SO4µÄ¾§ÌåÄÚ²»´æÔÚ__________(Ìî±êºÅ)
a. Àë×Ó¼ü     b. ¹²¼Û¼ü     c. Åäλ¼ü    d. ·¶µÂ»ªÁ¦
£¨4£©Í¼1±íʾijÖÖº¬µªÓлú»¯ºÏÎïµÄ½á¹¹£¬Æä·Ö×ÓÄÚ4¸öµªÔ­×Ó·Ö±ðλÓÚÕýËÄÃæÌåµÄ4¸ö¶¥µã£¨¼ûͼ2£©£¬·Ö×ÓÄÚ´æÔÚ¿ÕÇ»£¬ÄÜǶÈëijÀë×Ó»ò·Ö×Ó²¢ÐγÉ4¸öÇâ¼üÓèÒÔʶ±ð¡£

ÏÂÁзÖ×Ó»òÀë×ÓÖУ¬Äܱ»¸ÃÓлú»¯ºÏÎïʶ±ðµÄÊÇ_________£¨Ìî±êºÅ£©¡£
a. CF4      b. CH4      c. NH4£«     d. H2O
£¨12·Ö£©
¢ñ£®Ë³²¬ÊÇÃÀ¹ú½ÌÊÚB RosenbergµÈÈËÓÚ1969Äê·¢ÏֵĵÚÒ»ÖÖ¾ßÓп¹°©»îÐԵĽðÊôÅäºÏÎËüµÄ»¯Ñ§Ê½ÎªPt(NH3)2Cl2¡£
(1)ÓëNH3»¥ÎªµÈµç×ÓÌåµÄ·Ö×Ó¡¢Àë×ÓÓР        ¡¢         £¨¸÷¾ÙÒ»Àý£©¡£
(2)̼²¬ÊÇ1£¬1-»·¶¡¶þôÈËá¶þ°±ºÏ²¬(¢ò)µÄ¼ò³Æ£¬Êǵڶþ´ú²¬×忹°©Ò©ÎÆäËû¶¾¸±×÷ÓõÍÓÚ˳²¬¡£Ì¼²¬µÄ½á¹¹ÈçÏÂͼ£º

̼²¬Öк¬ÓеÄ×÷ÓÃÁ¦ÓР         £¨Ìî×Öĸ£©¡£
A£®¼«ÐÔ¹²¼Û¼üB£®·Ç¼«ÐÔ¹²¼Û¼üC£®Åäλ¼üD£®Àë×Ó¼ü
E£®½ðÊô¼ü        F£®¦Ò¼ü             G£®¦Ð¼ü
(3)̼²¬ÖÐCÔ­×ÓµÄÔÓ»¯·½Ê½ÓР    ¡£
(4)²¬£¨Pt£©µ¥Öʾ§ÌåÖÐÔ­×ӵĶѻý·½Ê½ÈçÏÂͼ¼×Ëùʾ£¬Æ侧°ûÌØÕ÷ÈçÏÂͼÒÒËùʾ£¬Ô­×ÓÖ®¼äÏ໥λÖùØϵµÄƽÃæͼÈçÏÂͼ±ûËùʾ¡£

¾§°ûÖв¬£¨Pt£©Ô­×ÓµÄÅäλÊýΪ     ¡£
¢ò£®Ô­×ÓÐòÊýСÓÚ36µÄÔªËØAºÍB£¬ÔÚÖÜÆÚ±íÖмȴ¦ÓÚͬһÖÜÆÚÓÖλÓÚͬһ×壬ÇÒÔ­×ÓÐòÊýB±ÈA¶à1£¬»ù̬BÔ­×ÓÖк¬ÓÐÈý¸öδ³É¶Ôµç×Ó¡£Çëд³öA2£«ÔÚ»ù̬ʱÍâΧµç×Ó£¨¼Ûµç×Ó£©ÅŲ¼Ê½Îª     £¬ BÔªËØÔÚÖÜÆÚ±íÖеÄλÖÃΪ     ¡£
(12·Ö)ÏÖÓÐA¡¢B¡¢C¡¢D¡¢EÎåÖÖ¶ÌÖÜÆÚÔªËØ£¬ÆäÔ­×ÓÐòÊýÒÀ´ÎÔö´ó¡£A¡¢CµÄ»ù̬ԭ×Óµç×ÓÅŲ¼ÖÐδ³É¶Ôµç×ÓÊýÓëÆäÖÜÆÚÊýÏàµÈ£¬ÇÒAµÄ×îÍâ²ãµç×ÓÊýÊÇ´ÎÍâ²ãµç×ÓÊýµÄ2±¶¡£DµÄÑôÀë×Ó¡¢CµÄÒõÀë×Ó¾ùÓëÄÊÔ­×ӵĵç×Ó²ã½á¹¹Ïàͬ£¬ÇÒDµÄµ¥ÖÊÓëCµÄµ¥ÖÊ·´Ó¦ÄÜÉú³ÉD2CºÍD2C2Á½ÖÖ»¯ºÏÎï¡£EËùÔÚÖÜÆÚÐòÊý±ÈËùÔÚÖ÷×åÐòÊý´ól¡£
(1)2011ÄêÊǹú¼Ê»¯Ñ§Ä꣬ÆäÖÐÒ»ÏîÖØÒª»î¶¯ÊǼÍÄî¾ÓÀï·òÈË»ñŵ±´¶û»¯Ñ§½±100ÖÜÄê¡£¾ÓÀï·ò¸¾·¢ÏÖÁË·ÅÉäIÉúÀØ(Ra)ºÍîÇ(Po)ÔªËØ£¬ÆäÖÐEÓëÀØͬÖ÷×壬ÀØλÓÚ           ×å¡£
(2)EµÄ»ù̬ԭ×ӵĺËÍâµç×ÓÅŲ¼Ê½ÊÇ         £¬A¡¢B¡¢CÈýÖÖÔªËØÖеÚÒ»µçÀëÄÜ×î´óµÄÊÇ            £¬B¡¢c¡¢DµÄÔ­×Ӱ뾶ÓÉСµ½´óµÄ˳ÐòΪ             (¾ùÓÃÔªËØ·ûºÅ ±íʾ)¡£
(3)D2C2ÓëAC2·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ             £¬Çëд³ö¸Ã·´Ó¦µÄÒ»ÖÖÓà       ¡£
(4)BÓëÇâÔªËØÐγÉ×î¼òµ¥µÄÆø̬Ç⻯ÎïµÄ¿Õ¼ä¹¹ÐÍΪ            £¬ÆäÖй²¼Û¼üÀàÐÍΪ              (ÌÐÔ¼ü»ò·Ç¼«ÐÔ¼ü)¡£ÒÑÖªB¡ÔB¼üÄÜΪ946 kJ¡¤mol-1£¬H-H¼üÄÜΪ
436 kJ¡¤mol-1£¬B¡ªH¼üÄÜΪ391 kJ¡¤mol-1£¬ÔòB2ºÍH2·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽΪ         ¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø