ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿¶þÑõ»¯ÂÈÊÇÒ»ÖÖ¸ßЧÏû¶¾¼Á£¬Í¨³£×´¿ö϶þÑõ»¯ÂÈÒ×ÈÜÓÚË®£¬·ÐµãΪ11.0¡æ£¬¼«Ò×±¬Õ¨£¬ÖÆÈ¡ºÍʹÓöþÑõ»¯ÂÈʱҪÓÃÐÔÖÊÎȶ¨µÄÆøÌå°´Ò»¶¨±ÈÀýÏ¡ÊÍ£¬ÒÔ·À±¬Õ¨¡£Ä³ÊµÑéС×éÔÚ¸ÉÔï¿ÕÆøÏ¡ÊÍÌõ¼þÏ£¬ÓøÉÔïµÄÂÈÆøÓë¹ÌÌåÑÇÂÈËáÄÆÖƱ¸¶þÑõ»¯ÂÈ£¬ÊµÑé×°ÖÃÈçͼËùʾ£º
(1)ÒÇÆ÷aµÄÃû³ÆΪ___________£¬×°ÖÃAÖз´Ó¦µÄ»¯Ñ§·½³ÌʽΪ___________¡£
(2)ÊÔ¼ÁXÊÇ___________¡£
(3)×°ÖÃDÄÚ·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ___________¡£
(4)¹¤ÒµÉÏÒ²³£ÓÃÑÎËá»òË«ÑõË®»¹ÔNaClO3ÖƱ¸ClO2£¬Ïà±ÈÖ®ÏÂÓÃË«ÑõË®ÖƱ¸ClO2·½·¨¸üÓÅ£¬¿ÉÄܵÄÔÒòÊÇ_____________________________¡£
(5)×°ÖÃEÖÐÖ÷Òª·´Ó¦µÄÀë×Ó·½³ÌʽΪ____________________¡£
(6)ÒÑÖªNaClO2±¥ºÍÈÜÒºÔÚζȵÍÓÚ38¡æʱÎö³öµÄ¾§ÌåÊÇNaClO2¡¤3H2O£¬¸ßÓÚ38¡æʱÎö³ö¾§ÌåÊÇNaClO2£¬¸ßÓÚ60¡æʱNaClO2·Ö½â³ÉNaClO3ºÍNaCl¡£
¢ÙÇëÍê³ÉʵÑéÊÒÀûÓÃNaClO2ÈÜÒºÖƵÃNaClO2¾§ÌåµÄ²Ù×÷²½Ö裺A£®¼õѹ£¬55¡æÕô·¢½á¾§£»B£®³ÃÈȹýÂË£»C£®ÓÃ38¡«60¡æµÄÎÂˮϴµÓ£»D£®µÍÓÚ60¡æ¸ÉÔµÃµ½²úÆ·¡£
¢ÚÈ¡ÉÏÊöËùµÃ²úÆ·2.50gÈÜÓÚË®Åä³É250mLÈÜÒº£¬È¡³ö25.00mLÈÜÒºÓÚ׶ÐÎÆ¿ÖУ¬ÔÙ¼ÓÈë×ãÁ¿ËữµÄKIÈÜÒº£¬³ä·Ö·´Ó¦ºó(NaClO2±»»¹ÔΪCl-£¬ÔÓÖʲ»²Î¼Ó·´Ó¦)£¬¼ÓÈë2¡«3µÎµí·ÛÈÜÒº£¬ÓÃ0.500mol¡¤L-1Na2S2O3±ê×¼ÒºµÎ¶¨ÖÁÖյ㡣½øÐÐ3´ÎʵÑéºó£¬Æ½¾ùÓÃÈ¥±ê×¼Òº18.80mL£¬ÊÔ¼ÆËãNaClO2²úÆ·µÄ´¿¶È__________(ÒÑÖª£º2Na2S2O3+I2=Na2S4O6+2NaI)¡£
¡¾´ð°¸¡¿·ÖҺ©¶· ±¥ºÍʳÑÎË® 2NaClO2+Cl2=2NaCl+2ClO2 H2O2µÄÑõ»¯²úÎïΪO2²»»áÎÛȾ»·¾³(»òHClµÄÑõ»¯²úÎïΪCl2»áÎÛȾ»·¾³) )Cl2+2OH-=Cl-+ClO-+H2O 85.07%(»ò¡°0.8507¡±µÈ)
¡¾½âÎö¡¿
±¾ÌâÖ÷ÒªÒÔʵÑéÊÒÖƱ¸ÂÈÆø¡¢³ýÔÓ¡¢¸ÉÔï½ø¶ø½øÐÐÂÈÆøµÄÐÔÖÊʵÑ飬²¢¸ù¾Ý·´Ó¦¹ý³ÌÖÐÀûÓÃÑõ»¯»¹Ô·´Ó¦µÄÔÀíÊéд·´Ó¦·½³Ìʽ£¬Í¬Ê±½øÐж¨Á¿ÊµÑéÀ´²âÁ¿ËùÓÃNaClO2²úÆ·µÄ´¿¶È£¬Ö»Òª»ù´¡ÖªÊ¶Ôúʵ£¬´ËÀàÌâÐÍÄѶȲ¢²»´ó¡£
(1)´ÓͼÖпÉÒÔÖ±½Ó¿´³öÒÇÆ÷aµÄÃû³ÆΪ·ÖҺ©¶·£¬×°ÖÃAÖоÍÊÇ·¢ÉúµÄʵÑéÊÒÖƱ¸ÂÈÆøµÄ»¯Ñ§·½³ÌʽΪ£¬¹Ê´ð°¸Îª£º·ÖҺ©¶· £»
(2)¸ù¾ÝʵÑéÐèÒª£¬×°ÖÃBÊǽøÐгýÔÓ£¬¼´³öÈ¥ÂÈÆøÖеÄÂÈ»¯ÇâÆøÌ壬¹ÊÊÔ¼ÁXÊDZ¥ºÍʳÑÎË®£¬¹Ê´ð°¸Îª£º±¥ºÍʳÑÎË®£»
(3)¸ù¾ÝÒÑÖª·´Ó¦ÎïΪNaClO2ºÍCl2£¬²¿·ÖÉú³ÉΪClO2£¬´Ë¹ý³ÌÖÐÂȵĻ¯ºÏ¼ÛÉý¸ß£¬±ØȻҪÓÐÔªËØ»¯ºÏ¼Û½µµÍ£¬¹ÊÍƳöÁíÒ»ÖÖÉú³ÉÎïΪNaCl£¬È»ºóÔÙ½øÐÐÑõ»¯»¹Ô·´Ó¦Åäƽ£¬¹Ê×°ÖÃDÄÚ·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ2NaClO2+Cl2=2NaCl+2ClO2£¬¹Ê´ð°¸Îª£º2NaClO2+Cl2=2NaCl+2ClO2£»
(4)ÓÉÓÚÑÎËáÄÜÓëNaClO3ÔÚÒ»¶¨Ìõ¼þÏ·´Ó¦Éú³ÉÂÈÆø£¬ÎÛȾ»·¾³£¬¶øH2O2µÄÑõ»¯²úÎïΪO2²»»áÎÛȾ»·¾³£¬¹Ê¹¤ÒµÉÏÒ²³£ÓÃÑÎËá»òË«ÑõË®»¹ÔNaClO3ÖƱ¸ClO2£¬Ïà±ÈÖ®ÏÂÓÃË«ÑõË®ÖƱ¸ClO2·½·¨¸üÓÅ£¬¿ÉÄܵÄÔÒòÊÇH2O2µÄÑõ»¯²úÎïΪO2²»»áÎÛȾ»·¾³(»òHClµÄÑõ»¯²úÎïΪCl2»áÎÛȾ»·¾³)£¬¹Ê´ð°¸Îª£ºH2O2µÄÑõ»¯²úÎïΪO2²»»áÎÛȾ»·¾³(»òHClµÄÑõ»¯²úÎïΪCl2»áÎÛȾ»·¾³)£»
(5)×°ÖÃEÊǽøÐÐβÆø´¦Àí£¬ÓÃNaOHÈÜÒºÎüÊÕÂÈÆø£¬¹ÊÆäÖ÷Òª·´Ó¦µÄÀë×Ó·½³ÌʽΪCl2+2OH-=Cl-+ClO-+H2O£¬¹Ê´ð°¸Îª£ºCl2+2OH-=Cl-+ClO-+H2O£»
(6) ¼ÓÈë×ãÁ¿ËữµÄKIÈÜÒº£¬³ä·Ö·´Ó¦ºó(NaClO2±»»¹ÔΪCl-£¬ÔÓÖʲ»²Î¼Ó·´Ó¦£¬¸ù¾ÝµÃʧµç×Ó×ÜÊýÏàµÈ£¬¿ÉÖªµÄI2µÄÎïÖʵÄÁ¿Ö®±ÈΪ1£º2£¬½ø¶ø¿ÉÒÔÕÒ³öÈçϹØϵʽ£º--2I2--4 £¬¹Ê
¼ÆËãµÃµ½ÑùÆ·ÖÐNaClO2µÄÖÊÁ¿·ÖÊý=£¬¹Ê´ð°¸Îª£º85.07%(»ò¡°0.8507¡±µÈ)¡£