ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿¢ñ.ºãκãÈÝÏÂ2 mol AÆøÌåºÍ2 mol BÆøÌåͨÈëÌå»ýΪ2 LµÄÃܱÕÈÝÆ÷Öз¢ÉúÈçÏ·´Ó¦£º2A(g)£«B(g) xC(g)£«2D(s)¡£2 min ʱ·´Ó¦´ïµ½Æ½ºâ״̬£¬´ËʱʣÓà1.2 mol B£¬²¢²âµÃCµÄŨ¶ÈΪ1.2 mol/L¡£
£¨1£©´Ó¿ªÊ¼·´Ó¦ÖÁ´ïµ½Æ½ºâ״̬£¬AµÄת»¯ÂÊΪ________¡£
£¨2£©x£½________¡£
£¨3£©ÏÂÁи÷Ïî¿É×÷Ϊ¸Ã·´Ó¦´ïµ½Æ½ºâ״̬µÄ±êÖ¾µÄÊÇ________(Ìî¸÷Ïî´úºÅ)
A£®Ñ¹Ç¿²»Ôٱ仯
B£®ÆøÌåƽ¾ùÏà¶Ô·Ö×ÓÖÊÁ¿²»Ôٱ仯
C£®ÆøÌåÃܶȲ»Ôٱ仯
D£®AµÄÏûºÄËÙÂÊÓëBµÄÏûºÄËÙÂÊÖ®±ÈΪ2:1
¢ò.Ò»¶¨Ìõ¼þÏ£¬¿ÉÄæ·´Ó¦A2(g)+B2(g) 2C(g)´ïµ½Æ½ºâʱ£¬¸÷ÎïÖʵÄƽºâŨ¶È·Ö±ðΪc(A2)=0.4mol¡¤L¡ª1£»c(B2)=0.1mol¡¤L¡ª1£»c(C)=1.6mol¡¤L¡ª1¡£
£¨1£©Èô·´Ó¦¿ªÊ¼Ê±£¬·´Ó¦ÈÝÆ÷ÖÐδ¼ÓÈëB£¬10sºó´ïµ½Æ½ºâ£¬Ôò10sÄÚÓÃCµÄŨ¶È±ä»¯±íʾµÄ»¯Ñ§·´Ó¦ËÙÂÊΪ_____________¡£
£¨2£©ÈôA2¡¢B2¡¢CµÄ³õʼŨ¶È·Ö±ðÓÃa¡¢b¡¢c±íʾ(mol¡¤L¡ª1)£¬Ôò£ºa¡¢bÓ¦Âú×ãµÄ¹ØϵÊÇ ¡£aµÄÈ¡Öµ·¶Î§ÊÇ ¡£
¡¾´ð°¸¡¿
¢ñ£¨1£©80%£»
£¨2£©3£»
£¨3£©BC
¢ò£¨1£©0.02 mol/(L¡¤s)
£¨2£©a-b=0.3£» 0.3¨Qa¨Q1.2
¡¾½âÎö¡¿
ÊÔÌâ·ÖÎö£º¢ñ¡¢£¨1£©2A(g)+B(g) xC(g)+2D(s)£¬
¿ªÊ¼ 2 2 0 0
ת»¯ 1.6 0.8
ƽºâ 0.4 1.2
ÔòAµÄת»¯ÂÊΪ¡Á100%=80%£¬¹Ê´ð°¸Îª£º80%£»
£¨2£©2minʱ·´Ó¦´ïµ½Æ½ºâ״̬£¬´ËʱʣÓà1.2mol B£¬ÔòBµÄ·´Ó¦ËÙÂÊΪ=0.2mol/(L£®min)£¬ÓÉ·´Ó¦ËÙÂÊÖ®±ÈµÈÓÚ»¯Ñ§¼ÆÁ¿ÊýÖ®±È¿ÉÖª£¬x=3£¬¹Ê´ð°¸Îª£º3£»
£¨3£©2A(g)+B(g) 3C(g)+2D(s)£¬A£®¸Ã·´Ó¦ÖÐѹǿʼÖÕ²»±ä£¬²»ÄÜÅжÏƽºâ£¬¹ÊA´íÎó£»B£®ÒòÆøÌåµÄÖÊÁ¿Ôڱ仯£¬ÔòÆøÌåÃܶȲ»Ôٱ仯£¬´ïµ½Æ½ºâ£¬¹ÊBÕýÈ·£»C£®ÒòÆøÌåµÄÖÊÁ¿Ôڱ仯£¬ÔòÆøÌåµÄƽ¾ùÏà¶Ô·Ö×ÓÖÊÁ¿²»Ôٱ仯£¬´ïµ½Æ½ºâ£¬¹ÊCÕýÈ·£»D£®AµÄÏûºÄËÙÂÊÓëBµÄÏûºÄËÙÂÊÖ®±ÈΪ2:1£¬¹ØϵʼÖÕ´æÔÚ£¬²»ÄÜÅжÏƽºâ£¬¹ÊD´íÎ󣻹ʴð°¸Îª£ºBC£»
¢ò¡¢£¨1£©10sÄÚ¡÷c(B2)=0.1molL-1£¬v(B2)==0.01molL-1s-1£¬v(C)=2v(B2)=2¡Á0.01molL-1s-1=0.02 molL-1s-1£¬¹Ê´ð°¸Îª£º0.02 molL-1s-1£»
£¨2£©A2(g)+B2(g)2C(g)£¬²Î¼Ó·´Ó¦µÄA2ºÍB2µÄŨ¶ÈÏàͬ£¬¹Ê¶þÕßƽºâŨ¶ÈÖ®²îÓ¦µÈÓÚÆðʼŨ¶ÈÖ®²î£¬¼´a-b=0.4-0.1=0.3£¬Èôƽºâ´ÓÕýÏò½¨Á¢£¬Ôò
A2(g)+B2(g)2C(g)
Æðʼ£º a b 0
ת»¯£ºa-0.4 b-0.1 1.6
ƽºâ£º 0.4 0.1 1.6
=
£¬a=1.2mol/L£¬
Èôƽºâ´ÓÄæÏò½¨Á¢£¬Ôò
A2(g)+B2(g)2C(g)
Æðʼ£º a 0 c
ת»¯£º0.1 0.1
ƽºâ£º0.4 0.1 1.6
a+0.1=0.4£¬a=0.3mol/L£¬¹ÊaµÄÈ¡Öµ·¶Î§Îª£º0.3¡Üa¡Ü1.2£¬¹Ê´ð°¸Îª£ºa-b=0.3£»0.3¡Üa¡Ü1.2
![](http://thumb2018.1010pic.com/images/loading.gif)