ÌâÄ¿ÄÚÈÝ
ÒÑÖª¶ÏÁÑ1 mol C¡ªH¼ü£¬ÒªÎüÊÕÈÈÁ¿414.4 kJ£»¶ÏÁÑ1 mol C¡ªC¼ü£¬ÒªÎüÊÕÈÈÁ¿347.4 kJ£»Éú³É1 mol C===C¼ü£¬»á·Å³öÈÈÁ¿615.3 kJ£»Éú³É1 mol H¡ªH¼ü£¬»á·Å³öÈÈÁ¿435.3 kJ£¬Ä³ÓлúÎï·Ö½âµÄ·´Ó¦¿É±íʾΪ£º
ÈôÔÚ·´Ó¦ÖÐÏûºÄÁË1 molÒÒÍ飬ÔòÓйظ÷´Ó¦µÄ˵·¨ÕýÈ·µÄÊÇ(¡¡¡¡)
A£®¸Ã·´Ó¦·Å³ö251.2 kJµÄÈÈÁ¿ | B£®¸Ã·´Ó¦ÎüÊÕ251.2 kJµÄÈÈÁ¿ |
C£®¸Ã·´Ó¦·Å³ö125.6 kJµÄÈÈÁ¿ | D£®¸Ã·´Ó¦ÎüÊÕ125.6 kJµÄÈÈÁ¿ |
D
½âÎöÊÔÌâ·ÖÎö£º¸ù¾Ý·´Ó¦ÈÈÓë¼üÄܵĹØϵ£¬¸Ã·´Ó¦µÄÈÈЧӦ=·´Ó¦Îï¶Ï¼üʱÎüÊÕµÄÄÜÁ¿-Éú³ÉÎï³É¼üʱ·Å³öµÄÄÜÁ¿="414.4" kJ¡Á6+347.4 kJ-£¨4¡Á414.4 kJ+615.3 kJ+435.3 kJ£©=125.6kJ>0£¬ËµÃ÷¸Ã·´Ó¦ÎüÈÈ£¬ËùÒÔ´ð°¸Ñ¡D¡£
¿¼µã£º¿¼²é»¯Ñ§·´Ó¦ÖÐÈÈЧӦµÄ¼ÆËã
ÅðºÍþÐγɵĻ¯ºÏÎïË¢ÐÂÁ˽ðÊô»¯ºÏÎﳬµ¼Î¶ȵÄ×î¸ß¼Ç¼¡£ÈçÓÒͼÊǸû¯ºÏÎïµÄ¾§Ìå½á¹¹µ¥Ôª£ºÃ¾Ô×Ó¼äÐγÉÕýÁùÀâÖù£¬ÇÒÀâÖùµÄÉÏÏÂÃ滹¸÷ÓÐÒ»¸öþÔ×Ó£»6¸öÅðÔ×ÓλÓÚÀâÖùµÄ²àÀâÉÏ£¬Ôò¸Ã»¯ºÏÎïµÄ»¯Ñ§Ê½¿É±íʾΪ( )
A£®MgB | B£®Mg3B2 |
C£®MgB2 | D£®Mg2B3 |
ÒÑÖªÏÂÁз´Ó¦µÄÈÈ»¯Ñ§·½³Ìʽ£º6C(s)+5H2(g)+3N2(g)+9O2(g)=2C3H5(ONO2)3(l) ¡÷H1
2 H2(g)+O2(g)=2H2O(g) ¡÷H2
C(s)+O2(g)=CO2(g) ¡÷H3
Ôò·´Ó¦4C3H5(ONO2)3(l)=12CO2(g)+10H2O(g)+O2(g)+6N2(g)µÄ¡÷HΪ£¨ £©
A£®12¡÷H3+5¡÷H2£2¡÷H1 | B£®2¡÷H1£5¡÷H2£12¡÷H3 |
C£®12¡÷H3£5¡÷H2£2¡÷H1 | D£®¡÷H1£5¡÷H2£12¡÷H3 |
ÒÑÖª·´Ó¦A+B=C+DµÄÄÜÁ¿±ä»¯ÈçͼËùʾ£¬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ £¨ £©
A£®¸Ã·´Ó¦Îª·ÅÈÈ·´Ó¦ |
B£®¸Ã·´Ó¦ÎªÎüÈÈ·´Ó¦ |
C£®·´Ó¦ÎïµÄ×ÜÄÜÁ¿¸ßÓÚÉú³ÉÎïµÄ×ÜÄÜÁ¿ |
D£®¸Ã·´Ó¦Ö»ÓÐÔÚ¼ÓÈÈÌõ¼þϲÅÄܽøÐÐ |
ÒÑÖª£º2CO(g)+O2(g)=2CO2(g) ¦¤H= £566 kJ?mol£1
Na2O2(s)+CO2(g) = Na2CO3(s)+1/2O2(g) ¦¤H= £226 kJ?mol£1
ÏÂÁбíÊöÕýÈ·µÄÊÇ(NA´ú±í°¢·üÙ¤µÂÂÞ³£ÊýµÄÊýÖµ) ( )
A£®1molCOȼÉÕʱ·Å³öµÄÈÈÁ¿Îª283 kJ?mol£1 |
B£®Na2O2(s)+CO(g) = Na2CO3(s)¦¤H= £509 kJ?mol-1 |
C£®Na2O2(s)ÓëCO2(g)·´Ó¦·Å³ö226 kJÈÈÁ¿Ê±µç×ÓתÒÆÊýΪ2NA |
D£®Na2O2ºÍNa2CO3ÖÐÒõÑôÀë×Ó¸öÊý±È²»Í¬ |
ÒÑÖª¶ÏÁÑ1 mol C¡ªH¼ü£¬ÒªÎüÊÕÈÈÁ¿414.4 kJ£»¶ÏÁÑ1 mol C¡ªC¼ü£¬ÒªÎüÊÕÈÈÁ¿347.4 kJ£»Éú³É1 mol C===C¼ü£¬»á·Å³öÈÈÁ¿615.3 kJ£»Éú³É1 mol H¡ªH¼ü£¬»á·Å³öÈÈÁ¿435.3 kJ£¬Ä³ÓлúÎï·Ö½âµÄ·´Ó¦¿É±íʾΪ£º
ÈôÔÚ·´Ó¦ÖÐÏûºÄÁË1 molÒÒÍé(·´Ó¦Îï)£¬ÔòÓйظ÷´Ó¦µÄ˵·¨ÕýÈ·µÄÊÇ(¡¡¡¡)
A£®¸Ã·´Ó¦·Å³ö251.2 kJµÄÈÈÁ¿ | B£®¸Ã·´Ó¦ÎüÊÕ251.2 kJµÄÈÈÁ¿ |
C£®¸Ã·´Ó¦·Å³ö125.6 kJµÄÈÈÁ¿ | D£®¸Ã·´Ó¦ÎüÊÕ125.6 kJµÄÈÈÁ¿ |
ÒÑÖª25 ¡æ¡¢101 kPaÏ£¬ÏÂÁз´Ó¦
C(ʯī) + O2(g) === CO2(g) £¬È¼ÉÕ1 mol C(ʯī)·ÅÈÈ393.51 kJ¡£
C(½ð¸Õʯ) + O2(g) === CO2(g)£¬È¼ÉÕ1 mol C(½ð¸Õʯ)·ÅÈÈ395.41 kJ¡£
¿ÉÒԵóöµÄ½áÂÛÊÇ
A£®½ð¸Õʯ±ÈʯīÎȶ¨ | B£®1 molʯīËù¾ßÓеÄÄÜÁ¿±È1 mol½ð¸ÕʯµÍ |
C£®½ð¸Õʯת±ä³ÉʯīÊÇÎïÀí±ä»¯ | D£®Ê¯Ä«ºÍ½ð¸Õʯ¶¼ÊÇ̼µÄͬλËØ |
ÔÚ101kPa 25¡æʱ£¬1.0gÒÒÍéÆøÌåÍêȫȼÉÕÉú³ÉҺ̬ˮʱ·Å³öÈÈÁ¿52.0kJ£¬ÔòÒÒÍéȼÉÕµÄÈÈ»¯Ñ§·½³ÌʽΪ
A£®C2H6(g) £« O2(g)£½2CO2(g) £«3H2O(l)¡÷H =£1560kJ¡¤mol£1 |
B£®2C2H6(g) £« 7O2(g)£½4CO2(g) £«6H2O(g)¡÷H =£1560kJ¡¤mol£1 |
C£®2C2H6(g) £« 7O2(g)£½4CO2(g) £«6H2O(l)¡÷H =£«3120 kJ¡¤mol£1 |
D£®C2H6(g) £«O2(g)£½2CO2(g) £«3H2O(l)¡÷H =£52.0kJ¡¤mol£1 |
Çâ·úËáÊÇÒ»ÖÖÈõËᣬ¿ÉÓÃÀ´¿ÌÊ´²£Á§¡£ÒÑÖª25ʱ£º
ÔÚ20Ml0.lmol/LµÄÇâ·úËáÖеμÓ0.lmol/LµÄNaOH V mL£¬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ
A£®Çâ·úËáµÄµçÀë·½³Ìʽ¼°ÈÈЧӦ¿É±íʾΪ£º |
B£®µ±V="20" mLʱ£¬ÈÜÒºÖУº |
C£®µ±V="20" mLʱ£¬ÈÜÒºÖУº |
D£®µ±v>0ʱ£¬ÈÜÒºÖÐÒ»¶¨´æÔÚ |