ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿µÍŨ¶ÈSO2·ÏÆøµÄ´¦ÀíÊǹ¤ÒµÄÑÌ⣬¹¤ÒµÉϳ£ÀûÓ÷ϼîÔü£¨Ö÷Òª³É·ÖNa2CO3£©ÎüÊÕÁòË᳧βÆøÖеÄSO2ÖƱ¸ÎÞË®Na2SO3µÄ³É±¾µÍ£¬ÓÅÊÆÃ÷ÏÔ£¬ÆäÁ÷³ÌÈçÏ¡£
£¨1£©ÎªÁËʹSO2¾¡¿ÉÄÜÎüÊÕÍêÈ«£¬ÔÚ²»¸Ä±äÎüÊÕËþÌå»ýµÄÌõ¼þÏ£¬¿ÉÒÔ²ÉÈ¡µÄºÏ
Àí´ëÊ©______________¡¢_______________¡££¨Ð´³öÁ½Ìõ£©
£¨2£©ÖкÍÆ÷Öз¢ÉúµÄÖ÷Òª·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ_____________________¡£
£¨3£©ÏÂͼΪÎüÊÕËþÖÐNa2CO3ÈÜÒºÓëSO2·´Ó¦¹ý³ÌÖÐÈÜÒº×é³É±ä»¯¡£
¢ÙÔò³õÆÚ·´Ó¦£¨Í¼ÖÐAµãÒÔÇ°£©µÄ»¯Ñ§·½³ÌʽÊÇ__________________¡£
¢Úͨ¹ýµç½â·¨¿É·ÖÀëͼÖÐBµãNaHSO3ÓëNa2SO3»ìºÏÎʵÏÖNa2SO3µÄÑ»·ÀûÓã¬Ê¾ÒâͼÈçÏ£º
¼òÊö·ÖÀëNaHSO3ÓëNa2SO3»ìºÏÎïµÄÔÀí___________________¡£
£¨4£©ÏÂͼÊÇÑÇÁòËáÄƵÄÈܽâ¶ÈÇúÏߣ¨Î¶ÈÔÚ33¡æÇ°ºó¶ÔÓ¦²»Í¬ÎïÖÊ£©£¬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ______
A£®aµãʱÈÜҺΪ²»±¥ºÍÈÜÒº
B£®bµãʱNa2SO3¡¤7H2OºÍÎÞË®Na2SO3¹²´æ
C£®ÖƱ¸ÎÞË®Na2SO3£¬Ó¦¸ÃÔÚ95~100¡æ¼ÓÈÈŨËõ£¬ÀäÈ´ÖÁÊÒνᾧ
£¨5£©Èç¹ûÓú¬µÈÎïÖʵÄÁ¿ÈÜÖʵÄÏÂÁи÷ÈÜÒº·Ö±ðÎüÊÕSO2£¬ÔòÀíÂÛÎüÊÕÁ¿×î¶àµÄÊÇ__________
A£®Na2SO3 B£®Na2S C£®Ba(NO3)2 D£®ËáÐÔKMnO4
¡¾´ð°¸¡¿¿ØÖÆSO2Á÷ËÙÔö´óNa2CO3ÈÜÒºµÄŨ¶È£¨Êʵ±ÉýΡ¢²ÉÓÃÆøÒºÄæÁ÷·¨¡¢ÅçÁÜ·¨»ò½«Na2CO3ÈÜÒºÎí»¯µÈºÏÀí¼´¿É£©HSO3- + OH- = SO32- + H2O 2Na2CO3 + SO2 + H2O =2 NaHCO3 + Na2SO3Ñô¼«4OH£-4e£=2H2O+O2¡ü£¬c(H+)Ôö´ó£¬H£«ÓÉaÊÒ¾ÑôÀë×Ó½»»»Ä¤½øÈëbÊÒ£¬H£«ÓëSO32£ ½áºÏÉú³ÉHSO3££¬Na2SO3ת»¯ÎªNaHSO3£¬Òõ¼«2H£«-2e£=H2¡ü£¬µ¼ÖÂHSO3£ H£«+ SO32£ÕýÏòÒƶ¯£¬Na£«´ÓbÊÒ½øÈëcÊÒ£¬NaHSO3ת»¯ÎªNa2SO3¡£BC
¡¾½âÎö¡¿£¨1£©Óô¿¼îÈÜÒºÎüÊÕº¬ÓÐSO2µÄβÆø£¬¿ÉÒÔͨ¹ý¿ØÖÆSO2Á÷ËÙ¡¢Ôö´óNa2CO3ÈÜÒºµÄŨ¶È¡¢²ÉÓÃÆøÒºÄæÁ÷·¨¡¢ÅçÁÜ·¨»ò½«Na2CO3ÈÜÒºÎí»¯µÈ´ëʩʹSO2¾¡¿ÉÄÜÎüÊÕÍêÈ«£»
£¨2£©Ëæ×ŶþÑõ»¯ÁòͨÈëÁ¿Ôö´ó£¬ºóÆÚÉú³ÉÖ÷ÒªÊǵõ½ÑÇÁòËáÇâÄÆ£¬ÖкÍÆ÷ÖÐÖ÷ÒªÊǽ«ÑÇÁòËáÇâÄÆת»¯ÎªÁòËáÄÆ£¬Í¬Ê±Ì¼ËáÇâÄÆ·´Ó¦µÃµ½Ì¼ËáÄÆ£¬Ö÷Òª·´Ó¦»¯Ñ§·½³ÌʽΪ£ºNaHSO3+NaOH=Na2SO3+H2O£¬¶ÔÓ¦µÄÀë×Ó·½³ÌʽΪHSO3- + OH- = SO32- + H2O£»
£¨3£©¢ÙÓÉͼ¿ÉÖª£¬³õÆÚ·´Ó¦£¨Í¼ÖÐAµãÒÔÇ°£©Ì¼ËáÄÆÓë¶þÑõ»¯Áò·´Ó¦Éú³É̼ËáÇâÄÆÓëÑÇÁòËáÄÆ£¬·´Ó¦·½³ÌʽΪ2Na2CO3 + SO2 + H2O =2 NaHCO3 + Na2SO3 -£»
¢Úͨ¹ýµç½â·¨¿É·ÖÀëNaHSO3ÓëNa2SO3»ìºÏÎÑô¼«2H2O-4e-=4H++O2¡ü£¬c£¨H+£©Ôö´ó£¬H+ÓÉaÊÒ¾ÑôÀë×Ó½»»»Ä¤½øÈëbÊÒ£¬H+ÓëSO32-½áºÏÉú³ÉHSO3-£¬Na2SO3ת»¯ÎªNaHSO3£®Òõ¼«2H+-2e-=H2¡ü£¬µ¼ÖÂHSO3-H++SO32-ÕýÏòÒƶ¯£¬Na+´ÓbÊÒ½øÈëcÊÒ£¬NaHSO3ת»¯ÎªNa2SO3£¬ÊµÏÖNa2SO3µÄÑ»·ÀûÓã»
£¨4£©A£®aµãÔÚÈܽâ¶ÈÇúÏßÉÏ·½£¬´ËʱÈÜҺΪ¹ý±¥ºÍÈÜÒº£¬ÔÚ¶ÔӦζÈÏ»áÓо§ÌåÎö³ö£¬¹ÊA´íÎó£»B£®ÔÚbµãÎö³öµÄ¾§Ìå¿ÉÄÜÊÇNa2SO3¡¤7H2OºÍÎÞË®Na2SO3µÄ»ìºÏÎ¶þÕß¹²´æ£¬¹ÊBÕýÈ·£» C£®ÓûÖƱ¸ÎÞË®Na2SO3£¬Ó¦¸ÃÔÚ95~100¡æ¼ÓÈÈŨËõ¡¢½á¾§¡¢²¢³ÃÈȹýÂË£¬²»ÄÜÀäÈ´½á¾§£¬¹ÊC´íÎó£»´ð°¸ÎªB¡£
£¨5£©Èç¹ûÓú¬µÈÎïÖʵÄÁ¿ÈÜÖʵÄÏÂÁи÷ÈÜÒº·Ö±ðÀ´ÎüÊÕSO2£¬
A£®Na2SO3 ÎüÊÕ¶þÑõ»¯Áò·¢ÉúµÄ·´Ó¦Îª£ºNa2SO3+SO2+H2O=2NaHSO3£¬1molNa2SO3 ×î¶àÎüÊÕ¶þÑõ»¯Áò1mol£»B£®Na2SÎüÊÕ¶þÑõ»¯Áò·¢ÉúµÄ·´Ó¦Îª£º2Na2S+5SO2+2H2O=4NaHSO3+3S¡ý£¬1mol2Na2S×î¶à·´Ó¦¶þÑõ»¯Áò2.5mol£»C£®Ba£¨NO3£©2ÎüÊÕ¶þÑõ»¯Áò·´Ó¦»¯Ñ§·½³ÌʽΪBa£¨NO3£©2+3SO2+2H2O=BaSO4¡ý+2H2SO4+2NO¡ü£º1molBa£¨NO3£©2×î¶àÎüÊÕ¶þÑõ»¯Áò3mol£»D£®ËáÐÔKMnO4ÈÜÒºÎüÊÕ¶þÑõ»¯ÁòµÄ·´Ó¦2MnO4-+5SO2+2H2O=2Mn2++5SO42-+4H+£¬1molKMnO4×î¶à·´Ó¦¶þÑõ»¯Áò2.5mol£»´ð°¸ÎªC¡£
¡¾ÌâÄ¿¡¿Ä³ÈÜÒºÖУ¬ÈôºöÂÔË®µÄµçÀ룬ֻº¬ÓÐϱíÖÐËùʾµÄËÄÖÖÀë×Ó£¬.Ôò±íÖÐXÀë×ÓÖÖÀ༰Æä¸öÊýbΪ
Àë×ÓÖÖÀà | Na+ | Al3+ | Cl- | X |
¸öÊý | 2a | a | a | b |
A. NH4+¡¢4a B. SO42-¡¢2a C. OH-¡¢4a D. CO32-¡¢2a
¡¾ÌâÄ¿¡¿ÊµÑéÊÒÖÐijЩÆøÌåµÄÖÆÈ¡¡¢ÊÕ¼¯¼°Î²Æø´¦Àí×°ÖÃÈçͼËùʾ(Ê¡ÂԼгֺ;»»¯×°ÖÃ)¡£½öÓôË×°ÖúͱíÖÐÌṩµÄÎïÖÊÍê³ÉÏà¹ØʵÑ飬×îºÏÀíµÄÑ¡ÏîÊÇ
Ñ¡Ïî | aÖеÄÎïÖÊ | bÖеÄÎïÖÊ | cÖÐÊÕ¼¯µÄÆøÌå | dÖеÄÎïÖÊ |
A | Ũ°±Ë® | CaO | NH3 | H2O |
B | ŨÁòËá | Na2SO3 | SO2 | NaOHÈÜÒº |
C | Ï¡ÏõËá | Cu | NO2 | H2O |
D | ŨÑÎËá | MnO2 | Cl2 | NaOHÈÜÒº |
A. A B. B C. C D. D
¡¾ÌâÄ¿¡¿Ï±íÖеÄÊý¾ÝÊÇÆÆ»µ1molÎïÖÊÖеĻ¯Ñ§¼üËùÏûºÄµÄÄÜÁ¿£¨kJ£©£º
ÎïÖÊ | Cl2 | Br2 | I2 | HCl | HBr | HI | H2 |
ÄÜÁ¿£¨kJ£© | 243 | 193 | 151 | 432 | 366 | 298 | 436 |
¸ù¾ÝÉÏÊöÊý¾Ý»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÏÂÁÐÎïÖʱ¾Éí¾ßÓеÄÄÜÁ¿×îµÍµÄÊÇ ¡£
A£®H2 B£®Cl2C£®Br2D£®I2
£¨2£©X2+H22HX (X´ú±íCl¡¢Br¡¢I)µÄ·´Ó¦ÊÇ·ÅÈÈ·´Ó¦»¹ÊÇÎüÈÈ·´Ó¦£¿
£¨3£©ÏàͬÌõ¼þÏ£¬X2(X´ú±íCl¡¢Br¡¢I)·Ö±ðÓëÇâÆø·´Ó¦£¬µ±ÏûºÄµÈÎïÖʵÄÁ¿µÄÇâÆøʱ£¬·Å³ö»òÎüÊÕµÄÈÈÁ¿×î¶àµÄÊÇ ¡£
£¨4£©ÈôÎÞÉϱíÖеÄÊý¾Ý£¬ÄãÄܻشðÎÊÌ⣨3£©Â𣿠£¨»Ø´ð¡°ÄÜ¡±»ò¡°²»ÄÜ¡±£©¡£ÄãµÄÒÀ¾ÝÊÇ ¡£