ÌâÄ¿ÄÚÈÝ

1£®ÏÖÓÐŨ¶È¾ùΪ0.1mol/LµÄÏÂÁÐÈÜÒº£º¢ÙÁòËá¡¡¢Ú´×Ëá¡¡¢ÛÇâÑõ»¯ÄÆ¡¡¢ÜÂÈ»¯ï§
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©¢Ù¢Ú¢Û¢ÜËÄÖÖÈÜÒºÖÐÓÉË®µçÀë³öµÄH+Ũ¶ÈÓÉ´óµ½Ð¡µÄ˳ÐòÊÇ£¨ÌîÐòºÅ£©¢Ü¢Ú¢Û¢Ù£®
£¨2£©½«¢ÛºÍ¢ÜµÈÌå»ý»ìºÏºó£¬»ìºÏÒºÖи÷Àë×ÓŨ¶ÈÓÉ´óµ½Ð¡µÄ˳ÐòÊÇc£¨Na+£©=c£¨Cl-£©£¾c£¨OH-£©£¾c£¨NH4+£©£¾c£¨H+£©
£¨3£©ÒÑÖªt¡ãC£¬KW=1¡Á10-13£¬Ôòt¡ãC£¾£¨Ìî¡°£¾¡±¡¢¡°£¼¡±»ò¡°=¡±£©25¡ãC£®
£¨4£©25¡ãCʱ£¬ÓÐpH=xµÄÑÎËáºÍpH=yµÄÇâÑõ»¯ÄÆÈÜÒº£¨x¡Ü6£¬y¡Ý8£©£¬È¡a L¸ÃÑÎËáÓëb L¸ÃÇâÑõ»¯ÄÆÈÜÒº·´Ó¦£¬Ç¡ºÃÍêÈ«Öкͣ®Á½ÈÜÒºµÄpH£¨x¡¢y£©µÄ¹ØϵʽΪ$\frac{a}{b}$=10x+y-14£¨Ìî±í´ïʽ£©£®

·ÖÎö £¨1£©¸ù¾ÝËá»ò¼î¾ùÄÜÒÖÖÆH2OµÄµçÀ룬ÇÒÈÜÒºÖÐH+»òOH-Ũ¶ÈÔ½´ó¡¢ÑεÄË®½âÄÜ´Ù½øË®µÄµçÀë·ÖÎö£»
£¨2£©¸ù¾Ý¶þÕßÍêÈ«·´Ó¦Éú³ÉNaClºÍNH3•H2OÈÜÒº·ÖÎö£»
£¨3£©Ë®µÄµçÀëÊÇÎüÈÈ·´Ó¦£¬Éý¸ßζȴٽøË®µçÀ룻
£¨4£©ÑÎËáÊÇһԪǿËᣬÇâÑõ»¯ÄÆÊÇһԪǿ¼î£¬ÆäÇ¡ºÃÍêÈ«Öкͣ¬ÈÜÒºÏÔÖÐÐÔ£¬¾ÝÇâÀë×ÓÓëÇâÑõ¸ùÀë×ÓÎïÖʵÄÁ¿Ïàͬ¼ÆË㣮

½â´ð ½â£º£¨1£©ÏòÈÜÒºÖмÓÈëËá»ò¼î¾ùÄÜÒÖÖÆH2OµÄµçÀ룬ÇÒÈÜÒºÖÐH+»òOH-Ũ¶ÈÔ½´ó£¬ÓÉË®µçÀë³öµÄH+Ũ¶ÈԽС£»ÑεÄË®½âÄÜ´Ù½øË®µÄµçÀ룬ËùÒÔÓÉË®µçÀë³öc£¨H+£©ÓÉ´óµ½Ð¡µÄ˳ÐòΪ£º¢Ü¢Ú¢Û¢Ù£¬
¹Ê´ð°¸Îª£º¢Ü¢Ú¢Û¢Ù£»
£¨2£©¶þÕßÍêÈ«·´Ó¦Éú³ÉNaClºÍNH3•H2O£¬ÓÉÓÚNH3•H2OµçÀë³öÇâÑõ¸ùÀë×Ó£¬ËùÒÔÈÜÒº³Ê¼îÐÔ£¬ÈÜÒºÖÐÀë×ÓŨ¶È´óС¹ØϵΪ£ºc£¨Na+£©=c£¨Cl-£©£¾c£¨OH-£©£¾c£¨NH4+£©£¾c£¨H+£©£¬
¹Ê´ð°¸Îª£ºc£¨Na+£©=c£¨Cl-£©£¾c£¨OH-£©£¾c£¨NH4+£©£¾c£¨H+£©£»
£¨3£©Ë®µÄµçÀëÊÇÎüÈÈ·´Ó¦£¬Éý¸ßζȴٽøË®µçÀ룬ÔòË®µÄÀë×Ó»ý³£ÊýÔö´ó£¬t¡æʱ£¬Kw=1¡Á10-13£¾10-14£¬ËùÒÔt¡æ£¾25¡æ£¬¹Ê´ð°¸Îª£º£¾£»
£¨4£©ÑÎËáÊÇһԪǿËᣬÇâÑõ»¯ÄÆÊÇһԪǿ¼î£¬ÆäÇ¡ºÃÍêÈ«Öкͣ¬ÈÜÒºÏÔÖÐÐÔ£¬¾ÝÇâÀë×ÓÓëÇâÑõ¸ùÀë×ÓÎïÖʵÄÁ¿Ïàͬ¿ÉÖª£¬aL¡Á10-xmol/L=bL¡Á10-14+ymol/L£¬
$\frac{a}{b}$=10x+y-14£¬¹Ê´ð°¸Îª£º$\frac{a}{b}$=10x+y-14£®

µãÆÀ ±¾Ì⿼²éÁËË®µÄµçÀë¼°ÈÜÒºÖÐÀë×ÓŨ¶È´óСµÄ±È½Ï£¬ÌâÄ¿ÄѶÈÖеȣ¬×¢ÒâζÈÓ°ÏìË®µÄÀë×Ó»ý£¬Î¶Ȳ»Í¬£¬Ë®µÄÀë×Ó»ý²»Í¬£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
10£®Ñо¿PM2.5¡¢SO2¡¢NO2µÈ´óÆøÎÛȾÎï¾ßÓÐÖØÒªÒâÒ壬Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©PM2.5³£Îü¸½º¬ÓÐÉéµÄ»¯ºÏÎïµÈÓж¾Ö°©ÎïÖÊ£¬ÉéµÄÔªËØ·ûºÅΪAs£¬Î»ÓÚÔªËØÖÜÆÚ±íµÚËÄÖÜÆÚµÚ¢õA×壮
£¨2£©½«PM2.5Ñù±¾ÓÃÕôÁóË®´¦Àí³É´ý²âÒº£¬²âµÃËùº¬Ë®ÈÜÐÔÎÞ»úÀë×ӵĻ¯Ñ§×é·Ö¼°Æäƽ¾ùŨ¶ÈÈçÏÂ±í£º
Àë×ÓK+Na+NH4+SO42-NO3-Cl-
Ũ¶È/mol•L-14¡Á10-66¡Á10-62¡Á10-54¡Á10-53¡Á10-52¡Á10-5
¸ù¾Ý±íÖÐÊý¾ÝÅжϴý×ÇÈÜÒºµÄpH=4£®
£¨3£©ÊÒÎÂÏ£¬ÓÃNa2SO3ÈÜÒºÎüÊÕSO2µÄ¹ý³ÌÖУ¬pHËæn£¨SO32-£©£ºn£¨HSO3-£©±ä»¯ÈçÏÂ±í£º
N£¨SO32-£©£ºn£¨HSO3-£©91£º91£º19£º91
pH8.27.26.2
ÓÉÉϱíÅжÏNaHSO3ÈÜÒºÏÔËáÐÔ£¬Óû¯Ñ§Æ½ºâÔ­Àí½âÊÍ£ºHSO3-´æÔÚ£ºHSO3-?SO32-+H+ºÍHSO3-+H2O?H2SO3+OH-£¬HSO3-µÄµçÀë³Ì¶È´óÓÚË®½â³Ì¶È£®
£¨4£©ÒÑÖª£º2NO£¨g£©+O2£¨g£©?2NO2£¨g£©¡÷H=-113.0kJ•mol-1
2SO2£¨g£©+O2£¨g£©?2SO3£¨g£©¡÷H=-196.6kJ•mol-1
Ôò·´Ó¦NO2£¨g£©+SO2£¨g£©?SO3£¨g£©+NO£¨g£©µÄ¡÷H=-41.8kJ•mol-1£®
Ò»¶¨Ìõ¼þÏ£¬½«NOºÍSO2ÒÔÌå»ý±È1£º2ÖÃÓÚÃܱÕÈÝÆ÷Öз¢ÉúÉÏÊö·´Ó¦£¬ÏÂÁÐÄÜ˵Ã÷·´Ó¦´ïµ½Æ½ºâ״̬µÄÊÇb£®
a£®Ìåϵѹǿ±£³Ö²»±ä  b£®»ìºÏÆøÌåÑÕÉ«±£³Ö²»±ä  c£®SO3ºÍNOµÄÌå»ý±£³Ö²»±ä d£®Ã¿ÏûºÄ1molSO3µÄͬʱÉú³É1molNO2£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø