ÌâÄ¿ÄÚÈÝ

ÏÂÁÐÐðÊöÕýÈ·µÄÊÇ
¢ÙÒ»ÊøƽÐйâÏßÕÕÉäµ°°×ÖÊÈÜҺʱ£¬´Ó²àÃæ¿É¿´µ½¹âÁÁµÄͨ·
¢ÚÒ»¶¨Î¶ȺÍѹǿÏ£¬ÆøÌåÌå»ýÖ÷ÒªÓÉÆä·Ö×ÓµÄÎïÖʵÄÁ¿¾ö¶¨
¢ÛÆøÌåĦ¶ûÌå»ýÊÇÖ¸µ¥Î»ÎïÖʵÄÁ¿ÆøÌåËùÕ¼µÄÌå»ý£¬Æ䵥λÊÇL
¢ÜÔÚͬÎÂͬÌå»ýʱ£¬ÆøÌåµÄÎïÖʵÄÁ¿Ô½´ó£¬ÔòѹǿԽ´ó
¢ÝÕô·¢²Ù×÷ʱ£¬Ó¦Ê¹»ìºÏÎïÖеÄË®·ÖÍêÈ«Õô¸Éºó£¬²ÅÄÜÍ£Ö¹¼ÓÈÈ
¢Þ±ê×¼×´¿öÏ£¬½«lgÂÁƬͶÈë20mL 18mol/LµÄÁòËáÖУ¬ÂÁƬÍêÈ«Èܽâ

A£®¢Ù¢Ú¢Ü B£®¢Ù¢Û¢Ý C£®¢Ú¢Û¢Þ D£®¢Ú¢Ü¢Ý

A

½âÎöÊÔÌâ·ÖÎö£ºµ°°×ÖÊÈÜÓÚË®¿ÉÒÔÐγɽºÌ壬ËùÒÔÒ»ÊøƽÐйâÏßÕÕÉäµ°°×ÖÊÈÜҺʱ£¬´Ó²àÃæ¿É¿´µ½¹âÁÁµÄͨ·£¬¢ÙÕýÈ·£»ÓÉÓÚÆøÌå·Ö×Ó¼äµÄ¾àÀëÔ¶´óÓÚÆøÌå·Ö×ÓÖ±¾¶£¬¶øÔÚÒ»¶¨Î¶ȺÍѹǿÏ£¬²»Í¬ÆøÌå·Ö×Ó¼äµÄ¾àÀ뼸ºõ¶¼ÊÇÏàͬµÄ£¬ËùÒÔÆøÌåÌå»ýÖ÷ÒªÓÉÆä·Ö×ÓµÄÎïÖʵÄÁ¿¾ö¶¨£¬¢ÚÕýÈ·£»ÆøÌåĦ¶ûÌå»ýÊÇÖ¸µ¥Î»ÎïÖʵÄÁ¿ÆøÌåËùÕ¼µÄÌå»ý£¬Æ䵥λÊÇL/mol£¬¢Û²»ÕýÈ·£»¸ù¾ÝPV£½nRT¿ÉÖª£¬ÔÚͬÎÂͬÌå»ýʱ£¬ÆøÌåµÄÎïÖʵÄÁ¿Ô½´ó£¬ÔòѹǿԽ´ó£¬¢ÜÕýÈ·£»Õô·¢²Ù×÷ʱ£¬µ±Õô·¢ÃóÖгöÏÖ´óÁ¿¾§Ìåʱ£¬¼´¿ÉÍ£Ö¹¼ÓÈÈ£¬ÀûÓÃÓàÈȽ«Ê£ÓàË®·ÖÕô¸É£¬¢Ý²»ÕýÈ·£»ÔÚ±ê×¼×´¿öϽðÊôÂÁÔÚŨÁòËáÖжۻ¯£¬ÂÁ²»¿ÉÄÜÈܽ⣬¢Þ²»ÕýÈ·£¬´ð°¸Ñ¡A¡£
¿¼µã£º¿¼²é½ºÌåÐÔÖÊ¡¢Ó°ÏìÆøÌåÌå»ýÒòËØ¡¢°¢·ü¼ÓµÂÂÞ¶¨ÂɵÄÓ¦Óá¢ÆøÌåĦ¶ûÌå»ý¡¢Õô·¢²Ù×÷ÒÔ¼°¶Û»¯µÈ

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø