ÌâÄ¿ÄÚÈÝ

ÏÖÓÐA¡¢B¡¢C¡¢D¡¢E¡¢FÁùÖÖ³£¼û»¯ºÏÎÒÑÖªËüÃÇ°üº¬µÄÑôÀë×ÓÓÐK£«¡¢Ag£«¡¢Na£«¡¢
Ba2£«¡¢Fe2£«¡¢Al3£«£¬ÒõÀë×ÓÓÐCl£­¡¢OH£­¡¢AlO2-¡¢NO3-¡¢SO42-¡¢CO32-¡£½«ËüÃÇ·Ö±ðÅä³É0.1 mol/LµÄÈÜÒº½øÐÐÈçÏÂʵÑ飺
¢Ù²âµÃÈÜÒºA¡¢C¡¢E¾ù³Ê¼îÐÔ£¬ÇÒ¼îÐÔA£¾E£¾C£¬EµÄÑæÉ«³Êdz×ÏÉ«£¨Í¸¹ýÀ¶É«îܲ£Á§¹Û²ì£©£»¢ÚÏòBÈÜÒºÖеμÓÏ¡°±Ë®ÖÁ¹ýÁ¿£¬ÏÈÉú³É³Áµí£¬ºó³ÁµíÈ«²¿Èܽ⣻¢ÛÏòFÈÜÒºÖеμÓÏ¡ÏõËᣬÈÜÒº±ä³É×Ø»ÆÉ«£¬ÇÒÓÐÎÞÉ«ÆøÌåÉú³É£»¢ÜÏòDÈÜÒºÖеμÓBa£¨NO3£©2ÈÜÒºÎÞÃ÷ÏÔÏÖÏó¡£
£¨1£©Ð´³öA¡¢D¡¢E¡¢FµÄ»¯Ñ§Ê½£º
A________£»D________£»E________£»F________¡£
£¨2£©ÓÃÀë×Ó·½³Ìʽ½âÊÍCÈÜÒº³Ê¼îÐÔµÄÔ­Òò£º__________________________________¡£
£¨3£©Ð´³öʵÑé¢ÛÖз´Ó¦µÄÀë×Ó·½³Ìʽ£º________________________________¡£

£¨1£©Ba£¨OH£©2 AlCl3 KAlO2 FeSO4
£¨2£©CO32-£«H2OHCO3-£«OH£­
£¨3£©3Fe2£«£«NO3-£«4H£«=3Fe3£«£«NO¡ü£«2H2O

½âÎö

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

(17·Ö)Ìú¼°Æ仯ºÏÎïÔÚÈÕ³£Éú»î¡¢Éú²úÖÐÓ¦Óù㷺¡£ÂÈ»¯ÌúºÍ¸ßÌúËá¼Ø¶¼Êdz£¼ûµÄË®´¦Àí¼Á¡£ÏÂͼΪÖƱ¸ÂÈ»¯Ìú¼°½øÒ»²½Ñõ»¯ÖƱ¸¸ßÌúËá¼ØµÄ¹¤ÒÕÁ÷³Ì¡£

Çë»Ø´ðÏÂÁÐÎÊÌâ
£¨1£©ÒÑÖª£º¢ÙFe2O3£¨s£©+3C(ʯī)2Fe(s)+3CO£¨g£©¡÷H=+489.0KJ¡¤mol£»
¢ÚC(ʯī)+CO2£¨g£©2CO(g)¡÷H=+172.5KJ¡¤mol£»ÓóàÌú¿óΪԭÁÏÔڸ߯Á¶Ìú¹ý³ÌÖз¢ÉúµÄÖ÷Òª·´Ó¦ÎªFe2O3£¨s£©+3CO(g)2Fe(s)+3CO2£¨g£©¡÷H=  KJ¡¤mol¡£
£¨2£©ÎüÊÕ¼ÁxµÄÈÜÖÊΪ____________(д»¯Ñ§Ê½)¡£
£¨3£©Ñõ»¯¼ÁYΪ¡°84Ïû¶¾Òº¡±µÄÓÐЧ³É·Ö£¬ÔòÔÚ¼îÐÔÌõ¼þÏ·´Ó¦¢ÙµÄÀë×Ó·½³ÌʽΪ
__________________________________________________________________
£¨4£©¹ý³Ì¢ÚÊÇÔÚijµÍÎÂϽøÐеģ¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ=£¬ËµÃ÷´ËζÈÏÂ__________ (Ìî¡°>¡±»ò¡°<¡±)¡£
¼Ù¶¨´Ë¹ý³ÌÖÐÍêȫת»¯Îª£¬Èô×îÖÕÖƵôֲúÆ·206.25t£¬²úÆ·´¿¶ÈΪ96£¥£¬ÔòÀíÂÛÉÏÖÁÉÙÐèÒªÑõ»¯¼ÁYµÄÖÊÁ¿ÊÇ___________t¡£
£¨5£©¸ßÌúµç³ØÊÇÒ»ÖÖÐÂÐͶþ´Îµç³Ø£¬µç½âҺΪǿ¼îÈÜÒº£¬Æäµç³Ø·´Ó¦Îª£º3Zn+2K2FeO4+8H2O3Zn£¨OH£©2+2Fe£¨OH£©3+4KOH£¬·Åµçʱµç³ØµÄ¸º¼«·´Ó¦Ê½Îª______________________________________¡£

A¡¢B¡¢C¡¢D¡¢E¡¢F¡¢GÆßÖÖÎïÖʼä´æÔÚÈçͼËùʾµÄת»¯¹Øϵ£¬ÆäÖÐA¡¢B¡¢D¡¢Gº¬ÓÐͬÖÖÔªËØ¡£

ÒÑÖª£º
AΪ½ðÊôµ¥ÖÊ£¬BΪºìºÖÉ«¹ÌÌ壬EΪÃܶÈ×îСµÄÆøÌ壬GΪdzÂÌÉ«µÄÈÜÒº¡£
DµÄË®ÈÜҺΪ»ÆÉ«ÈÜÒº£¬ÄÜÓëÏõËáÒøÈÜÒº·´Ó¦Éú³É²»ÈÜÓÚÏ¡ÏõËáµÄ°×É«³Áµí¡£
ÔÚË®ÈÜÒºÖÐDÄܽ«Ä³Ñõ»¯ÎïÑõ»¯ÎªF£¬FÊǺ¬ÓÐÈýÖÖÔªËصĻ¯ºÏÎï¡£
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©¹¹³ÉCÎïÖʵÄÔªËØÔÚÖÜÆÚ±íÖеÄλÖÃÊÇ     £¬ÔÚ¶ÌÖÜÆÚÖ÷×åÔªËØÖУ¬¸ÃÔªËØÓëÆäÏàÁÚÔªËصÄÔ­×Ӱ뾶´Ó´óµ½Ð¡µÄ˳ÐòÊÇ         (ÓÃÔªËØ·ûºÅ±íʾ)¡£
£¨2£©DµÄË®ÈÜÒº³Ê   ÐÔ£¬ÇëÓÃÀë×Ó·½³Ìʽ½âÊÍÔ­Òò£º             ¡£
£¨3£©ÉÏÊö·´Ó¦ÖÐÊôÓÚÖû»·´Ó¦µÄÊÇ     (ÌîÐòºÅ)¡£
£¨4£©·´Ó¦¢Û(¼´D½«Ä³ÖÖÑõ»¯ÎïÑõ»¯ÎªF)µÄÀë×Ó·½³Ìʽ£º               ¡£
£¨5£©¶ÔÆøÌåC½øÐÐÈçÏÂʵÑé¡£ÒÑÖªÕû¸ö·´Ó¦¹ý³ÌÖУ¬Ã¿ÏûºÄ0.1mol KI£¬×ªÒƵĵç×ÓÊýԼΪ3.612¡Á1023¸ö¡£Çë°´ÕÕÒªÇóÌî¿Õ£º

ʵÑé²½Öè
ʵÑéÏÖÏó
дÀë×Ó·½³Ìʽ
½«ÉÙÁ¿ÆøÌåͨÈëµí·ÛKIÈÜÒº
ÈÜÒº×î³õ±ä³É     É«
 
¼ÌÐøͨÈëÆøÌå
ÈÜÒºÖð½¥±ä³ÉÎÞÉ«
 
 

ij¹¤Òµ·ÏË®½öº¬Ï±íÖеÄijЩÀë×Ó£¬ÇÒ¸÷ÖÖÀë×ÓµÄÎïÖʵÄÁ¿Å¨¶ÈÏàµÈ£¬¾ùΪ0.1 mol/L(´ËÊýÖµºöÂÔË®µÄµçÀë¼°Àë×ÓµÄË®½â)¡£

ÑôÀë×Ó
K£«¡¡Ag£«¡¡Mg2£«¡¡Cu2£«¡¡Al3£«¡¡NH4+
ÒõÀë×Ó
Cl£­¡¡CO32¡ª¡¡NO3¡ª¡¡SO42¡ª¡¡I£­
 
¼×ͬѧÓû̽¾¿·ÏË®µÄ×é³É£¬½øÐÐÁËÈçÏÂʵÑ飺
¢ñ.È¡¸ÃÎÞÉ«ÈÜÒº5 mL£¬µÎ¼ÓÒ»µÎ°±Ë®ÓгÁµíÉú³É£¬ÇÒÀë×ÓÖÖÀàÔö¼Ó¡£
¢ò.Óò¬Ë¿ÕºÈ¡ÈÜÒº£¬ÔÚ»ðÑæÉÏ×ÆÉÕ£¬Í¸¹ýÀ¶É«îܲ£Á§¹Û²ì£¬ÎÞ×ÏÉ«»ðÑæ¡£
¢ó.ÁíÈ¡ÈÜÒº¼ÓÈë¹ýÁ¿ÑÎËᣬÓÐÎÞÉ«ÆøÌåÉú³É£¬¸ÃÎÞÉ«ÆøÌåÓö¿ÕÆø±ä³Éºì×ØÉ«¡£
¢ô.Ïò¢óÖÐËùµÃµÄÈÜÒºÖмÓÈëBaCl2ÈÜÒº£¬Óа×É«³ÁµíÉú³É¡£
ÇëÍƶϣº
(1)ÓÉ¢ñ¡¢¢òÅжϣ¬ÈÜÒºÖÐÒ»¶¨²»º¬ÓеÄÑôÀë×ÓÊÇ___________________________________¡£
(2)¢óÖмÓÈëÑÎËáÉú³ÉÎÞÉ«ÆøÌåµÄÀë×Ó·½³ÌʽÊÇ________________________¡£
(3)¼×ͬѧ×îÖÕÈ·¶¨Ô­ÈÜÒºÖÐËùº¬ÑôÀë×ÓÓÐ________£¬ÒõÀë×ÓÓÐ________£»²¢¾Ý´ËÍƲâÔ­ÈÜÒºÓ¦¸Ã³Ê________ÐÔ£¬Ô­ÒòÊÇ____________________________(ÇëÓÃÀë×Ó·½³Ìʽ˵Ã÷)¡£
(4)ÁíÈ¡100 mLÔ­ÈÜÒº£¬¼ÓÈë×ãÁ¿µÄNaOHÈÜÒº£¬´Ë¹ý³ÌÖÐÉæ¼°µÄÀë×Ó·½³ÌʽΪ____________________________¡£³ä·Ö·´Ó¦ºó¹ýÂË£¬Ï´µÓ£¬×ÆÉÕ³ÁµíÖÁºãÖØ£¬µÃµ½µÄ¹ÌÌåÖÊÁ¿Îª________g¡£

¢ñ.Í­Ìú¼°Æ仯ºÏÎïÔÚÈÕ³£Éú»îÖÐÓ¦Óù㷺£¬Ä³Ñо¿ÐÔѧϰС×éÓôÖÍ­£¨º¬ÔÓÖÊFe£©Óë¹ýÁ¿ÂÈÆø·´Ó¦µÃ¹ÌÌåA£¬ÓÃÏ¡ÑÎËáÈܽâA£¬È»ºó¼ÓÊÔ¼Áµ÷½ÚÈÜÒºµÄpHºóµÃÈÜÒºB£¬ÈÜÒºB¾­ÏµÁвÙ×÷¿ÉµÃÂÈ»¯Í­¾§Ì壬Çë»Ø´ð£º
£¨1£©¹ÌÌåAÓÃÏ¡ÑÎËáÈܽâµÄÔ­ÒòÊÇ           __¡£
£¨2£©¼ìÑéÈÜÒºBÖÐÊÇ·ñ´æÔÚFe3£«µÄ·½·¨ÊÇ   __¡£
£¨3£©ÒÑÖªÔªËØÔڸ߼Û̬ʱ³£±íÏÖÑõ»¯ÐÔ£¬ÈôÔÚËáÐÔCuSO4ÈÜÒºÖмÓÈëÒ»¶¨Á¿µÄNa2SO3ºÍNaClÈÜÒº£¬¼ÓÈÈ£¬Éú³ÉCuCl³Áµí£¬ÔòÉú³ÉCuClµÄÀë×Ó·½³ÌʽÊÇ           ¡£
¢ò.³£ÎÂÏ£¬Ä³Í¬Ñ§½«Ï¡ÑÎËáºÍ°±Ë®µÈÌå»ý»ìºÏ£¬Á½ÖÖÈÜÒºµÄŨ¶ÈºÍ»ìºÏºóËùµÃÈÜÒºµÄpHÈçÏÂ±í£º

ʵÑé±àºÅ
°±Ë®ÎïÖʵÄÁ¿Å¨¶È/£¨mol¡¤L£­1£©
ÑÎËáÎïÖʵÄÁ¿Å¨¶È/£¨mol¡¤L£­1£©
»ìºÏÈÜÒºpH
¢Ù
0.1
0.1
pH£½5
¢Ú
c
0.2
pH£½7
¢Û
0.2
0.1
pH>7
 
Çë»Ø´ð£º
£¨4£©´ÓµÚ¢Ù×éÇé¿ö·ÖÎö£¬¸Ã×éËùµÃ»ìºÏÈÜÒºÖÐÓÉË®µçÀë³öµÄc£¨H£«£©£½   __mol¡¤L£­1£»´ÓµÚ¢Ú×éÇé¿ö±íÃ÷£¬c   __£¨Ìî¡°>¡±¡°<¡±»ò¡°£½¡±£©0.2 mol¡¤L£­1£»´ÓµÚ¢Û×éÇé¿ö·ÖÎö¿ÉÖª£¬»ìºÏÈÜÒºÖÐc£¨NH4+£©   __£¨Ìî¡°>¡±¡°<¡±»ò¡°£½¡±£©c£¨NH3¡¤H2O£©¡£
£¨5£©Ð´³öÒÔÏÂËÄ×éÈÜÒºNH4+Ũ¶ÈÓÉ´óµ½Ð¡µÄ˳Ðò   __>   __>   __>   __£¨ÌîÑ¡Ïî±àºÅ£©¡£
A£®0.1 mol¡¤L£­1 NH4Cl
B£®0.1 mol¡¤L£­1 NH4ClºÍ0.1 mol¡¤L£­1 NH3¡¤H2O
C£®0.1 mol¡¤L£­1 NH3¡¤H2O
D£®0.1 mol¡¤L£­1 NH4ClºÍ0.1 mol¡¤L£­1 HCl

ÂÈÆø¼°Æ仯ºÏÎïÔÚ¹¤Å©ÒµÉú²úºÍÈËÀàÉú»îÖж¼ÓÐ×ÅÖØÒªµÄÓ¦Óá£
(1)Ca(ClO)2¡¢NaClO¡¢NaClO2µÈº¬ÂÈ»¯ºÏÎﶼÊdz£ÓõÄÏû¶¾¼ÁºÍƯ°×¼Á,ÊÇÒòΪËüÃǶ¼¾ßÓС¡¡¡¡¡¡¡¡¡ÐÔ,Çëд³ö¹¤ÒµÉÏÓÃÂÈÆøÓëNaOHÈÜÒº·´Ó¦Éú²úÏû¶¾¼ÁNaClOµÄÀë×Ó·½³Ìʽ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£ 
(2)×Ø»ÆÉ«Ç¿´Ì¼¤ÐÔÆøÌåCl2OΪ¹ú¼Ê¹«ÈϸßЧ°²È«Ãð¾úÏû¶¾¼ÁÖ®Ò»,ʵÑéÊÒ¿ÉÓó±ÊªµÄCl2ÓëNa2CO3·´Ó¦ÖÆÈ¡ÉÙÁ¿Cl2OºÍNaHCO3µÄÀë×Ó·½³Ìʽ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£ 
(3)»ÆÉ«ÆøÌåClO2¿ÉÓÃÓÚÎÛˮɱ¾úºÍÒûÓÃË®¾»»¯¡£
¢ÙKClO3ÓëSO2ÔÚÇ¿ËáÐÔÈÜÒºÖз´Ó¦¿ÉÖƵÃClO2,´Ë·´Ó¦µÄÀë×Ó·½³ÌʽΪ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£ 
¢ÚClO2ÓöŨÑÎËá»áÉú³ÉCl2,ÿÉú³É1 mol Cl2תÒƵç×ÓµÄÎïÖʵÄÁ¿Îª¡¡¡¡¡¡¡¡¡£ 
¢ÛClO2¿É½«·ÏË®ÖеÄMn2+ת»¯ÎªMnO2¶ø³ýÈ¥,±¾Éí»¹Ô­ÎªCl-,¸Ã·´Ó¦¹ý³ÌÖÐÑõ»¯¼ÁÓ뻹ԭ¼ÁµÄÎïÖʵÄÁ¿Ö®±ÈΪ¡¡¡¡¡¡¡¡¡£ 
(4)ÓÃCl2Éú²úijЩº¬ÂÈÓлúÎïʱ»á²úÉú¸±²úÎïHCl¡£ÀûÓ÷´Ó¦4HCl+O22Cl2+2H2O,¿ÉʵÏÖÂȵÄÑ­»·ÀûÓá£
ÒÑÖª:¢ÙÉÏÊö·´Ó¦ÖÐ,4 mol HCl±»Ñõ»¯·Å³ö115.6 kJµÄÈÈÁ¿¡£

Ôò¶Ï¿ª1 mol H¡ªO¼üÓë¶Ï¿ª1 mol H¡ªCl¼üËùÐèÄÜÁ¿Ïà²îԼΪ¡¡¡¡¡¡¡¡ kJ,H2OÖÐH¡ªO¼ü±ÈHClÖÐH¡ªCl¼ü(Ìî¡°Ç¿¡±»ò¡°Èõ¡±)¡¡¡¡¡¡¡¡¡£ 

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø