ÌâÄ¿ÄÚÈÝ
ij¹¤Òµ·ÏË®½öº¬Ï±íÖеÄijЩÀë×Ó£¬ÇÒ¸÷ÖÖÀë×ÓµÄÎïÖʵÄÁ¿Å¨¶ÈÏàµÈ£¬¾ùΪ0.1 mol/L(´ËÊýÖµºöÂÔË®µÄµçÀë¼°Àë×ÓµÄË®½â)¡£
ÑôÀë×Ó | K£«¡¡Ag£«¡¡Mg2£«¡¡Cu2£«¡¡Al3£«¡¡NH4+ |
ÒõÀë×Ó | Cl£¡¡CO32¡ª¡¡NO3¡ª¡¡SO42¡ª¡¡I£ |
¼×ͬѧÓû̽¾¿·ÏË®µÄ×é³É£¬½øÐÐÁËÈçÏÂʵÑ飺
¢ñ.È¡¸ÃÎÞÉ«ÈÜÒº5 mL£¬µÎ¼ÓÒ»µÎ°±Ë®ÓгÁµíÉú³É£¬ÇÒÀë×ÓÖÖÀàÔö¼Ó¡£
¢ò.Óò¬Ë¿ÕºÈ¡ÈÜÒº£¬ÔÚ»ðÑæÉÏ×ÆÉÕ£¬Í¸¹ýÀ¶É«îܲ£Á§¹Û²ì£¬ÎÞ×ÏÉ«»ðÑæ¡£
¢ó.ÁíÈ¡ÈÜÒº¼ÓÈë¹ýÁ¿ÑÎËᣬÓÐÎÞÉ«ÆøÌåÉú³É£¬¸ÃÎÞÉ«ÆøÌåÓö¿ÕÆø±ä³Éºì×ØÉ«¡£
¢ô.Ïò¢óÖÐËùµÃµÄÈÜÒºÖмÓÈëBaCl2ÈÜÒº£¬Óа×É«³ÁµíÉú³É¡£
ÇëÍƶϣº
(1)ÓÉ¢ñ¡¢¢òÅжϣ¬ÈÜÒºÖÐÒ»¶¨²»º¬ÓеÄÑôÀë×ÓÊÇ___________________________________¡£
(2)¢óÖмÓÈëÑÎËáÉú³ÉÎÞÉ«ÆøÌåµÄÀë×Ó·½³ÌʽÊÇ________________________¡£
(3)¼×ͬѧ×îÖÕÈ·¶¨ÔÈÜÒºÖÐËùº¬ÑôÀë×ÓÓÐ________£¬ÒõÀë×ÓÓÐ________£»²¢¾Ý´ËÍƲâÔÈÜÒºÓ¦¸Ã³Ê________ÐÔ£¬ÔÒòÊÇ____________________________(ÇëÓÃÀë×Ó·½³Ìʽ˵Ã÷)¡£
(4)ÁíÈ¡100 mLÔÈÜÒº£¬¼ÓÈë×ãÁ¿µÄNaOHÈÜÒº£¬´Ë¹ý³ÌÖÐÉæ¼°µÄÀë×Ó·½³ÌʽΪ____________________________¡£³ä·Ö·´Ó¦ºó¹ýÂË£¬Ï´µÓ£¬×ÆÉÕ³ÁµíÖÁºãÖØ£¬µÃµ½µÄ¹ÌÌåÖÊÁ¿Îª________g¡£
(1)K£«¡¢NH4+¡¢Cu2£«
(2)6I££«2NO3¡ª£«8H£«=3I2£«2NO¡ü£«4H2O
(3)Mg2£«¡¢Al3£«¡¡Cl£¡¢NO3¡ª¡¢SO42¡ª¡¢I£¡¡Ëá¡¡Mg2£«£«2H2O??Mg(OH)2£«2H£«¡¢Al3£«£«3H2OAl(OH)3£«3H£«
(4)Mg2£«£«2OH£=Mg(OH) 2¡ý¡¢Al3£«£«4OH£=AlO2¡ª£«2H2O¡¡0.4
½âÎö
äå¼°Æ仯ºÏÎï¹ã·ºÓ¦ÓÃÔÚÓлúºÏ³É¡¢»¯Ñ§·ÖÎöµÈÁìÓò¡£
£¨1£©º£Ë®Ìáäå¹ý³ÌÖÐäåÔªËصı仯ÈçÏ£º
¢Ù¹ý³Ì¢ñ£¬º£Ë®ÏÔ¼îÐÔ£¬µ÷ÆäpH£¼3.5ºó£¬ÔÙͨÈëÂÈÆø¡£
¢¡.ͨÈëÂÈÆøºó£¬·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ______¡£
¢¢.µ÷º£Ë®pH¿ÉÌá¸ßCl2µÄÀûÓÃÂÊ£¬ÓÃƽºâÔÀí½âÊÍÆäÔÒòÊÇ______¡£
¢Ú¹ý³Ì¢ò£¬ÓÃÈÈ¿ÕÆø½«äå¸Ï³ö£¬ÔÙÓÃŨ̼ËáÄÆÈÜÒºÎüÊÕ¡£Íê³É²¢ÅäƽÏÂÁз½³Ìʽ¡£
Br2£«Na2CO3£½NaBrO3£«CO2£«______
¢Û¹ý³Ì¢ó£¬ÓÃÁòËáËữ¿ÉµÃBr2ºÍNa2SO4µÄ»ìºÏÈÜÒº¡£
ÏàͬÌõ¼þÏ£¬ÈôÓÃÑÎËáËữ£¬ÔòËùµÃäåµÄÖÊÁ¿¼õÉÙ£¬ÔÒòÊÇ______¡£
£¨2£©NaBrO3ÊÇÒ»ÖÖ·ÖÎöÊÔ¼Á¡£ÏòÁòËáËữµÄNaIÈÜÒºÖÐÖðµÎ¼ÓÈëNaBrO3ÈÜÒº£¬µ±¼ÓÈë2.6 mol NaBrO3ʱ£¬²âµÃ·´Ó¦ºóÈÜÒºÖÐäåºÍµâµÄ´æÔÚÐÎʽ¼°ÎïÖʵÄÁ¿·Ö±ðΪ£º
Á£×Ó | I2 | Br2 | IO3- |
ÎïÖʵÄÁ¿/mol | 0.5 | 1.3 | |
ijNa2CO3¡¢NaAlO2µÄ»ìºÏÈÜÒºÖÐÖðµÎ¼ÓÈë1 mol¡¤L-1µÄÑÎËá,²âµÃÈÜÒºÖеÄC¡¢HC¡¢Al¡¢Al3+µÄÎïÖʵÄÁ¿Óë¼ÓÈëÑÎËáµÄÌå»ý±ä»¯¹ØϵÈçͼËùʾ,ÔòÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨ £©
A£®Ô»ìºÏÈÜÒºÖеÄCÓëAlµÄÎïÖʵÄÁ¿Ö®±ÈΪ1¡Ã2 |
B£®V1¡ÃV2=1¡Ã5 |
C£®MµãʱÉú³ÉµÄCO2Ϊ0.05 mol |
D£®aÏß±íʾµÄÀë×Ó·½³ÌʽΪ:Al+H++H2OAl(OH)3¡ý |