ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿¸ßÌúËáÄÆ(Na2FeO4)¾ßÓкÜÇ¿µÄÑõ»¯ÐÔ,ÊÇÒ»ÖÖÐÂÐ͵ÄÂÌÉ«¾»Ë®Ïû¶¾¼Á¡£¹¤ÒµÉÏÒÔÁâÌú¿ó(Ö÷Òª³É·ÖÊÇFeCO3¼°ÉÙÁ¿SiO2)ΪÔÁÏÖƱ¸¸ßÌúËáÄÆÉú²ú¹ý³ÌÈçÏ£º
(1)Na2FeO4ÖÐÌúÔªËصĻ¯ºÏ¼ÛΪ___,¸ßÌúËáÄÆÓÃÓÚɱ¾úÏû¶¾Ê±µÄ»¯Ñ§·´Ó¦ÀàÐÍΪ____(Ìî¡°Ñõ»¯»¹Ô·´Ó¦¡±¡¢¡°¸´·Ö½â·´Ó¦¡±»ò¡°»¯ºÏ·´Ó¦¡±)¡£
(2)°´ÕÕÉÏÊöÁ÷³Ì,²½Öè¢ÙÖмî½þʱÄÜ·ñÓýϱãÒ˵ÄCa(OH)2Ìæ´úNaOH_____(Ìî¡°ÄÜ¡±»ò¡°²»ÄÜ¡±),ÀíÓÉÊÇ___________¡£
(3)²½Öè¢ÚÖÐ28%µÄÏ¡ÁòËáÐèÒªÓÃ98%µÄŨÁòËáÅäÖÆ,ÅäÖÆʱËùÐè²£Á§ÒÇÆ÷³ýÁ¿Í²Íâ,»¹____(Ìî×ÖĸÐòºÅ)¡£²½Öè¢ÛÖмìÑéFe2+È«²¿×ª»¯³ÉFe3+µÄ·½·¨ÊÇ£º__________¡£
A£®ÈÝÁ¿Æ¿ B£®ÉÕ± C£®ÉÕÆ¿ D£®²£Á§°ô E£®ËáʽµÎ¶¨¹Ü;
(4)²½Öè¢ÜÖгýÉú³ÉNa2FeO4Íâ,»¹ÓÐNaClÉú³É,ÆäÀë×Ó·½³ÌʽΪ_________£»¼ºÖª²½Öè¢ÝÊÇÏòNa2FeO4ÈÜÒºÖмÌÐø¼ÓÈëÇâÑõ»¯ÄƹÌÌåµÃµ½Ðü×ÇÒº,Ôò²Ù×÷aµÄÃû³ÆΪ_____¡£
(5)ÀíÂÛÉÏ,ÿ»ñµÃ0.5molµÄFeO42-ÏûºÄ NaClOµÄ×ÜÖÊÁ¿Îª_____¡£
¡¾´ð°¸¡¿+6 Ñõ»¯»¹Ô·´Ó¦ ²»ÄÜ CaSiO3 ÄÑÈÜÓÚË®£¬ÎÞ·¨·ÖÀë³öSiO2£¨ÆäËüºÏÀí´ð°¸Ò²¿É£© BD È¡ÉÙÁ¿¢ÛÖÐÈÜÒºÓÚÊԹܣ¬µÎÈëÉÙÁ¿K3Fe(CN)6ÈÜÒº£¬ÈôÎÞÀ¶É«³Áµí£¬ÔòFe2£« ÒѾȫ²¿×ª»¯³ÉFe3£« 2Fe3£«£«3ClO££«10OH£=2FeO42££«3Cl££«5H2O ¹ýÂË 74.5g
¡¾½âÎö¡¿
¹¤ÒµÉÏÁâÌú¿ó£¬Ö÷Òª³É·ÖÊÇFeCO3¼°ÉÙÁ¿SiO2£¬¢ÙÓÃNaOHÈܽâSiO2³ýÈ¥£¬²½Öè¢ÚÖÐÓÃ28%µÄÏ¡ÁòËáÈܽâÉú³ÉÑÇÌúÀë×Ó£¬¢ÛNaClO½«ÑÇÌúÀë×ÓÑõ»¯³ÉÌúÀë×Ó£¬¢ÜÈ»ºó¼ÓÈëNaOHºÍNaClO·¢Éú·´Ó¦£º2Fe3£«+3ClO£+10OH£=2FeO42£+3Cl£+5H2O£¬µÃµ½¸ßÌúËáÄÆ£¨Na2FeO4£©ÈÜÒº£¬¢Ý×îºó½á¹¹Õô·¢Å¨Ëõ¡¢ÀäÈ´½á¾§µÃµ½²úÆ·¸ßÌúËáÄÆ¡£
£¨1£©Na2FeO4Öл¯ºÏ¼Û´úÊýºÍΪÁ㣻
£¨2£©CaSiO3 ÄÑÈÜÓÚË®£»
£¨3£©¸ù¾ÝÅäÖÆÒ»¶¨Á¿·ÖÊýÈÜÒºµÄ²½Ö裺¼ÆËã¡¢³ÆÁ¿¡¢Èܽ⣬ȷ¶¨ËùÓõÄÒÇÆ÷£»
¿ÉÓÃK3Fe(CN)6ÈÜÒº£¬¼ìÑéFe2+£»
£¨4£©²½Öè¢ÜÖгýÉú³ÉNa2FeO4Í⣬»¹ÓÐNaClÉú³É£¬¸ù¾ÝÖÊÁ¿Êغãд³öÀë×Ó·½³Ìʽ£»
·ÖÀë¹ÌÌåÓëÒºÌåÓ¦ÓùýÂË£»
£¨5£©ÀíÂÛÉÏ£¬Óɵç×ÓÊغ㣬Ìú´Ó+2¼Û±ä³É+6¼Û£¬°´¹ØϵʽFeO42-¡«2NaClO¼ÆËã¡£
£¨1£©Na2FeO4Öл¯ºÏ¼Û´úÊýºÍΪÁ㣬ÔòFeÔªËصĻ¯ºÏ¼ÛΪ+6¼Û£»
¸ßÌúËáÄƾßÓкÜÇ¿µÄÑõ»¯ÐÔ£¬¸ßÌúËáÄÆÓÃÓÚɱ¾úÏû¶¾Ê±µÄ»¯Ñ§·´Ó¦ÀàÐÍΪÑõ»¯»¹Ô·´Ó¦£»
£¨2£©ÓÃNaOHÈܽâSiO2Éú³É¹èËáÄÆÄÜÈܽ⣬´Ó¶øÓëFeCO3·ÖÀë¶ø³ýÈ¥£¬²»ÄÜÓýϱãÒ˵ÄCa(OH)2Ìæ´úNaOH£¬CaSiO3 ÄÑÈÜÓÚË®£¬ÎÞ·¨·ÖÀë³öSiO2¡£
£¨3£©¸ù¾ÝÅäÖÆÒ»¶¨Á¿·ÖÊýÈÜÒºµÄ²½Ö裺¼ÆËã¡¢³ÆÁ¿¡¢Èܽ⣬ȷ¶¨ËùÓõÄÒÇÆ÷£º½ºÍ·µÎ¹Ü¡¢Á¿Í²¡¢²£Á§°ô¡¢ÉÕ±£¬¹ÊÑ¡£ºBD¡£
²½Öè¢ÛÖмìÑéFe2+È«²¿×ª»¯³ÉFe3+µÄ·½·¨ÊÇ£ºÈ¡ÉÙÁ¿¢ÛÖÐÈÜÒºÓÚÊԹܣ¬µÎÈëÉÙÁ¿K3Fe(CN)6ÈÜÒº£¬ÈôÎÞÀ¶É«³Áµí£¬ÔòFe2£« ÒѾȫ²¿×ª»¯³ÉFe3£«£»
£¨4£©²½Öè¢ÜÖгýÉú³ÉNa2FeO4Í⣬»¹ÓÐNaClÉú³É,ÆäÀë×Ó·½³ÌʽΪ2Fe3£«£«3ClO££«10OH£=2FeO42££«3Cl££«5H2O£»
¼ºÖª²½Öè¢ÝÊÇÏòNa2FeO4ÈÜÒºÖмÌÐø¼ÓÈëÇâÑõ»¯ÄƹÌÌåµÃµ½Ðü×ÇÒº£¬·ÖÀë¹ÌÌåÓëÒºÌåÓ¦ÓùýÂË£¬Ôò²Ù×÷aµÄÃû³ÆΪ¹ýÂË¡£
£¨5£©ÀíÂÛÉÏ£¬Óɵç×ÓÊغ㣬Ìú´Ó+2¼Û±ä³É+6¼Û£¬°´¹ØϵʽFeO42-¡«2NaClO¼ÆË㣬ÿ»ñµÃ0.5molµÄFeO42-ÏûºÄ NaClOµÄ×ÜÖÊÁ¿Îª74.5g¡£
¡¾ÌâÄ¿¡¿ÏÂÁÐʵÑéÉè¼ÆÕýÈ·µÄÊÇ£¨ £©
²Ù×÷ | ÏÖÏó | ½áÂÛ | |
A | ½«SO2ͨÈëäåË® | äåË®ÍÊÉ« | SO2¾ßÓÐƯ°×ÐÔ |
B | ½«ÒÒϩͨÈëËáÐÔKMnO4ÈÜÒº | ËáÐÔKMnO4ÈÜÒºÍÊÉ« | ÒÒÏ©¾ßÓл¹ÔÐÔ |
C | ½«³ÎÇåʯ»ÒË®µÎÈëijÈÜÒº | ³öÏÖ°×É«»ë×Ç | ÆäÈÜÒºÖдæÔÚCO32- |
D | ½«ÏõËáÒøÈÜÒºµÎÈëijÈÜÒº | ³öÏÖ°×É«³Áµí | ÆäÈÜÒºÖдæÔÚCl- |
A.AB.BC.CD.D
¡¾ÌâÄ¿¡¿¶ÔÏõ»ù¼×±½ÊÇÒ½Ò©¡¢È¾Áϵȹ¤ÒµµÄÒ»ÖÖÖØÒªÓлúÖмäÌ壬Ëü³£ÒÔŨÏõËáΪÏõ»¯¼Á£¬Å¨ÁòËáΪ´ß»¯¼Á£¬Í¨¹ý¼×±½µÄÏõ»¯·´Ó¦ÖƱ¸¡£
++
Ò»ÖÖеÄÖƱ¸¶ÔÏõ»ù¼×±½µÄʵÑé·½·¨ÊÇ£ºÒÔ·¢ÑÌÏõËáΪÏõ»¯¼Á£¬¹ÌÌåNaHSO4Ϊ´ß»¯¼Á(¿ÉÑ»·Ê¹ÓÃ)£¬ÔÚCCl4ÈÜÒºÖУ¬¼ÓÈëÒÒËáôû(ÓÐÍÑË®×÷ÓÃ)£¬45¡æ·´Ó¦1h ¡£·´Ó¦½áÊøºó£¬¹ýÂË£¬ÂËÒº·Ö±ðÓÃ5% NaHCO3ÈÜÒº¡¢Ë®Ï´ÖÁÖÐÐÔ£¬ÔÙ¾·ÖÀëÌá´¿µÃµ½¶ÔÏõ»ù¼×±½¡£
(1)ÉÏÊöʵÑéÖйýÂ˵ÄÄ¿µÄÊÇ___________¡£
(2)ÂËÒºÔÚ·ÖҺ©¶·ÖÐÏ´µÓ¾²Öúó£¬Óлú²ã´¦ÓÚ________²ã(Ìî¡°ÉÏ¡±»ò'Ï¡±)¡£
(3)5% NaHCO3ÈÜҺϴµÓµÄÄ¿µÄÊÇ__________
(4)ÏÂÁиø³öÁË´ß»¯¼ÁÖÖÀ༰ÓÃÁ¿¶Ô¼×±½Ïõ»¯·´Ó¦Ó°ÏìµÄʵÑé½á¹û¡£
´ß»¯¼Á | n(´ß»¯¼Á)/n(¼×±½) | Ïõ»¯²úÎïÖи÷ÖÖÒì¹¹ÌåÖÊÁ¿·ÖÊý(%) | ×ܲúÂÊ(%) | ||
¶ÔÏõ»ù¼×±½ | ÁÚÏõ»ù¼×±½ | ¼äÏõ»ù¼×±½ | |||
ŨH2SO4 | 1.0 | 35.6 | 60.2 | 4.2 | 98.0 |
1.2 | 36.5 | 59.5 | 4.0 | 99.8 | |
NaHSO4 | 0.15 | 44.6 | 55.1 | 0.3 | 98.9 |
0.25 | 46.3 | 52.8 | 0.9 | 99.9 | |
0.32 | 47.9 | 51.8 | 0.3 | 99.9 | |
0.36 | 45.2 | 54.2 | 0.6 | 99.9 |
¢ÙNaHSO4´ß»¯ÖƱ¸¶ÔÏõ»ù¼×±½Ê±£¬´ß»¯¼ÁÓë¼×±½µÄ×î¼ÑÎïÖʵÄÁ¿Ö®±ÈΪ_______________¡£
¢ÚÓɼױ½Ïõ»¯µÃµ½µÄ¸÷ÖÖ²úÎïµÄº¬Á¿¿ÉÖª£¬¼×±½Ïõ»¯·´Ó¦µÄÌصãÊÇ_________________¡£
¢ÛÓëŨÁòËá´ß»¯¼×±½Ïõ»¯Ïà±È£¬NaHSO4´ß»¯¼×±½Ïõ»¯µÄÓŵãÓÐ_____________¡£