ÌâÄ¿ÄÚÈÝ

ÓÐA¡¢B¡¢C¡¢D¡¢E¡¢FÁùÖÖÎïÖÊ£¬ËüÃÇÖ®¼äÏ໥ת»¯¹ØϵÈçͼËùʾ(Ìõ¼þ¼°²¿·Ö²úÎïδ±ê³ö)¡£

£¨1£©ÈôA¡¢DΪÆøÌ壬¶¼ÄÜʹ³ÎÇåµÄʯ»ÒË®±ä»ë×Ç£»B¡¢F×öÑæÉ«·´Ó¦£¬Í¸¹ýÀ¶É«îܲ£Á§¹Û²ìΪ×ÏÉ«£¬ B¡¢CΪÕýÑΣ¬FµÄÈÜҺΪ×ϺìÉ«¡£ÔòCºÍFÔÚËáÐÔÈÜÒºÖз¢Éú·´Ó¦¢ÚµÄÀë×Ó·½³ÌʽΪ              ¡£              
£¨2£©Èô1 mol A·Ö×ÓÖк¬ÓÐ3 mol¼«ÐÔ¹²¼Û¼ü£¬ B¡¢C¡¢F¶¼ÊǶÌÖÜÆÚÔªËØ×é³ÉµÄ·Ç½ðÊôµ¥ÖÊ£»³£ÎÂÏ£¬Ö»ÓÐDΪ¹ÌÌ壬ÆäËüΪÆøÌå¡£Ôò·´Ó¦¢ÛµÄ»¯Ñ§·½³ÌʽΪ                                    ¡£ 
ijͬѧÉè¼ÆÁËÈçͼËùʾװÖ㨼гÖÒÇÆ÷Ê¡ÂÔ£©½øÐÐÉÏÊö(2)ÖÐÎïÖÊBµÄ»¯Ñ§ÐÔÖÊ̽¾¿¡£

¢ÙÄãÈÏΪ´Ë×°ÖÃÉè¼ÆÊÇ·ñºÏÀí£¿Èô²»ºÏÀíÈçºÎ¸Ä½ø£º                       ¡£(ÈôºÏÀí´ËÎʲ»´ð)
¢Ú¢òÖвúÉúµÄÏÖÏóÊÇ                                                                 ¡£
¢Û·´Ó¦¼¸·ÖÖӺ󣬼ìÑé¢óÖпÉÄܺ¬ÓеĽðÊôÑôÀë×ÓµÄʵÑé²Ù×÷ÊÇ                            ¡£
¢Üͨ¹ýÒÔÉÏ̽¾¿£¬ÆøÌåBµÄÖ÷Òª»¯Ñ§ÐÔÖÊÊÇ                                             ¡£
(12·Ö)£¨1£©5SO32-£«2MnO4-£«6H+£½2Mn2+£«5SO42-£«3H2O    ¡¡¡¡¡¡¡¡¡¡    (2·Ö)
£¨2£©4NH3£«5O24NO + 6 H2O                           ¡¡¡¡¡¡¡¡¡¡¡¡¡¡  (2·Ö)
¢Ù²»ºÏÀí£¬Ó¦ÔÚ¢ñ¡¢¢òÖ®¼ä¼ÓÉϳýÈ¥HClµÄ×°Öᣠ          ¡¡¡¡¡¡¡¡¡¡¡¡¡¡ (2·Ö)
¢ÚʯÈïÈÜÒºÏȱäºìºóÍÊÉ«                                  ¡¡¡¡¡¡¡¡¡¡     (2·Ö)
¢ÛÈ¡ÈÜÒºÉÙÐí·Ö±ð¼ÓÈëÁ½Ö§ÊÔ¹ÜÖУ¬ÏòÆäÖÐÒ»Ö»µÎ¼ÓÁòÇ軯¼ØÈÜÒº£¬ÈôÈÜÒº±äºì£¬Ôòº¬ÓÐFe3+£»
ÏòÁíÒ»Ö»ÊÔ¹ÜÖеμÓÌúÇ軯¼ØÈÜÒº£¬Èô²úÉúÀ¶É«³Áµí£¬Ôòº¬ÓÐFe2+¡£(ÿ¸öÀë×Ó1·Ö£¬¹²2·Ö)
¢ÜÇ¿Ñõ»¯ÐÔ£¬ÄÜÓëË®¡¢Óë¼î·´Ó¦£¬Ë®ÈÜÒº¾ßÓÐËáÐÔºÍÑõ»¯(Ư°×)ÐÔ   £¨2·Ö£¬¶Ô3¸öÈ«·Ö£©

ÊÔÌâ·ÖÎö£º£¨1£©ÈôA¡¢DΪÆøÌ壬¶¼ÄÜʹ³ÎÇåµÄʯ»ÒË®±ä»ë×Ç£¬Õâ˵Ã÷¶þÕßÊÇCO2ºÍSO2£»B¡¢F×öÑæÉ«·´Ó¦£¬Í¸¹ýÀ¶É«îܲ£Á§¹Û²ìΪ×ÏÉ«£¬ËµÃ÷º¬ÓмØÔªËØ¡£ FµÄÈÜҺΪ×ϺìÉ«£¬Õâ˵Ã÷FÊǸßÃÌËá¼Ø¡£ÓÉÓÚFÄܺÍA·´Ó¦£¬ËµÃ÷AÊǾßÓл¹Ô­ÐԵģ¬ËùÒÔAÊÇSO2£¬DÊÇCO2¡£B¡¢CΪÕýÑΣ¬ËùÒÔBÊÇ̼Ëá¼Ø£¬CÊÇÑÇÁòËá¼Ø¡£ÔòCºÍFÔÚËáÐÔÈÜÒºÖз¢Éú·´Ó¦¢ÚµÄÀë×Ó·½³ÌʽΪ5SO32-£«2MnO4-£«6H+£½2Mn2+£«5SO42-£«3H2O¡£
£¨2£©Èô1 mol A·Ö×ÓÖк¬ÓÐ3 mol¼«ÐÔ¹²¼Û¼ü£¬Òò´ËAÊÇ°±Æø¡£B¡¢C¡¢F¶¼ÊǶÌÖÜÆÚÔªËØ×é³ÉµÄ·Ç½ðÊôµ¥ÖÊ£»³£ÎÂÏ£¬Ö»ÓÐDΪ¹ÌÌ壬ÆäËüΪÆøÌ壬Õâ˵Ã÷BÓ¦¸ÃÊÇÂÈÆø£¬CÊǵªÆø£¬DÊÇÂÈ»¯ï§£¬FÊÇÑõÆø£¬EÊÇNO£¬Ôò·´Ó¦¢ÛµÄ»¯Ñ§·½³ÌʽΪ4NH3£«5O24NO + 6 H2O¡£
¢ÙÓÉÓÚÔÚÖƱ¸ÂÈÆøʱ£¬Å¨ÑÎËá¾ßÓлӷ¢ÐÔ£¬ËùÒÔÉú³ÉµÄÂÈÆøÖк¬ÓÐÂÈ»¯Ç⣬»ò¸ÉÈźóÐøµÄʵÑ飬Òò´ËÊDz»ºÏÀí£¬Ó¦ÔÚ¢ñ¡¢¢òÖ®¼ä¼ÓÉϳýÈ¥HClµÄ×°Ö㬿ÉÒÔÓñ¥ºÍµÄʳÑÎË®³ýÈ¥ÂÈ»¯Çâ¡£
¢ÚÂÈÆøÈÜÓÚË®Éú³ÉÑÎËáºÍ´ÎÂÈËᣬ¾ßÓÐËáÐÔºÍÇ¿Ñõ»¯ÐÔ£¬ËùÒÔ¢òÖвúÉúµÄÏÖÏóÊÇʯÈïÈÜÒºÏȱäºìºóÍÊÉ«¡£
¢ÛÂÈÆø¾ßÓÐÇ¿Ñõ»¯ÐÔ£¬ÄÜ°ÑÂÈ»¯ÑÇÌúÑõ»¯Éú³ÉÂÈ»¯Ìú£¬ËùÒÔ·´Ó¦¼¸·ÖÖӺ󣬼ìÑé¢óÖпÉÄܺ¬ÓеĽðÊôÑôÀë×ÓµÄʵÑé²Ù×÷ÊÇÈ¡ÈÜÒºÉÙÐí·Ö±ð¼ÓÈëÁ½Ö§ÊÔ¹ÜÖУ¬ÏòÆäÖÐÒ»Ö»µÎ¼ÓÁòÇ軯¼ØÈÜÒº£¬ÈôÈÜÒº±äºì£¬Ôòº¬ÓÐFe3+£»ÏòÁíÒ»Ö»ÊÔ¹ÜÖеμÓÌúÇ軯¼ØÈÜÒº£¬Èô²úÉúÀ¶É«³Áµí£¬Ôòº¬ÓÐFe2+¡£
¢Ü¸ù¾ÝÒÔÉÏ·ÖÎö¿ÉÖª£¬ÂÈÆøµÄÖ÷ÒªÐÔÖÊÊÇÇ¿Ñõ»¯ÐÔ£¬ÄÜÓëË®¡¢Óë¼î·´Ó¦£¬Ë®ÈÜÒº¾ßÓÐËáÐÔºÍÑõ»¯(Ư°×)ÐÔ¡£
µãÆÀ£º¸ÃÌâÊÇÖеÈÄѶȵÄÊÔÌ⣬ÊÔÌâ×ÛºÏÐÔÇ¿£¬¶ÔѧÉúµÄ˼άÄÜÁ¦ÒªÇó¸ß£¬ÓÐÀûÓÚÅàÑøѧÉúµÄÂß¼­ÍÆÀíÄÜÁ¦ºÍ·¢É¢Ë¼Î¬ÄÜÁ¦£¬Ò²ÓÐÖúÓÚÅàÑøѧÉú¹æ·¶¡¢ÑϽ÷µÄʵÑéÉè¼ÆÄÜÁ¦¡£¸ÃÌâµÄÄѵãÊÇ¿òͼÌâµÄÅжϣ¬ÐèҪעÒâµÄÊÇ»¯Ñ§ÍƶÏÌâÊÇÒ»Àà×ÛºÏÐÔ½ÏÇ¿µÄÊÔÌ⣬ÈçÔªËؼ°»¯ºÏÎïÐÔÖʺÍÉç»áÉú»î£¬»·¾³±£»¤£¬»¯Ñ§¼ÆËãµÈ֪ʶ£¬»¹¿ÉÒýÈëѧ¿Æ¼ä×ۺϡ£Ëü²»½ö¿É¿¼²ìѧÉú¶Ô»¯Ñ§ÖªÊ¶µÄÀí½â³Ì¶È£¬¸üÖØÒªµÄÊÇÅàÑøѧÉúµÄ×ۺϷÖÎöÄÜÁ¦ºÍ˼ά·½·¨¡£½â¿òͼÌâµÄ·½·¨£º×î¹Ø¼üµÄÊÇÑ°ÕÒ¡°Í»ÆÆ¿Ú¡±£¬¡°Í»ÆÆ¿Ú¡±¾ÍÊÇ×¥¡°ÌØ¡±×Ö£¬ÀýÈçÌØÊâÑÕÉ«¡¢ÌØÊâ״̬¡¢ÌØÊâÆøζ¡¢ÌØÊâ·´Ó¦¡¢ÌØÊâÏÖÏó¡¢ÌØÊâÖÆ·¨¡¢ÌØÊâÓÃ;µÈ¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
SO2ÊÇÒ»ÖÖÖØÒªµÄ»¯¹¤Ô­ÁÏ£¬Ò²ÊÇÒýÆðËáÓêÎÛȾµÄÖØÒªÀ´Ô´¡£
(1)ijÐËȤС×é²ÉÓÃÈçͼËùʾװÖÃÖÆÈ¡SO2

¢ÙÏÂÁÐʵÑé·½°¸ÊÊÓÃÈçͼËùʾװÖÃÖÆÈ¡ËùÐèSO2µÄÊÔ¼ÁÊÇ_______(ÌîÐòºÅ£©¡£
A£®Na2SO3ÈÜÒºÓëÏ¡ÏõËá
B£®Na2SO3¹ÌÌåÓëŨÁòËá
C£®¹ÌÌåÁòºÍÑõÆø
D£®Í­ÓëŨÁòËá
¢ÚaµÄÒÇÆ÷Ãû³ÆÊÇ_______¡£
¢ÛβÆøÎüÊÕ×°ÖõÄÁ¬½Ó˳ÐòÊÇb½Ó(   )½Ó (   )½Óe¡£
(2)ΪÁË»ØÊÕÀûÓÃSO2·ÏÆø£¬Ñо¿ÈËÔ±ÑÐÖÆÁËÀûÓõÍƷλÈíÃÌ¿ó½¬(Ö÷Òª³É·ÖÊÇMnO2)ÎüÊÕ¸ßαºÉÕº¬Áò·ÏÔü²úÉúµÄSO2·ÏÆø£¬ÖƱ¸ÁòËáÃ̾§Ìå(Éú²úÁ÷³Ì£¬ÆäÁ÷³ÌʾÒâͼÈçÏ£º

ÒÑÖª£º½þ³öÒºµÄpH<2£¬ÆäÖеĽðÊôÀë×ÓÖ÷ÒªÊÇMn2+£¬»¹º¬ÓÐÉÙÁ¿µÄFe2£«¡¢Al3£«µÈÆäËû½ðÊôÀë×Ó¡£ÓйؽðÊôÀë×ÓÐγÉÇâÑõ»¯Îï³ÁµíʱÈÜÒºµÄpH¼ûÏÂ±í£º

Çë»Ø´ð£º
¢Ùº¬Al3£«µÄÑγ£ÓÃ×÷¾»Ë®¼Á£¬ÓÃÀë×Ó·½³Ìʽ±íʾÆ侻ˮԭÀí________________________¡£
¢Ú½þ³ö¹ý³ÌÖÐÖ÷Òª·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ___________________________________________¡£
¢ÛÑõ»¯¹ý³ÌÖмÓÈëMnO2·ÛµÄÄ¿µÄÊÇ______________________________________________;
·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ_________________________________________________________¡£
¢ÜÓÃʯ»Ò½¬µ÷½ÚpH£¬pHÓ¦µ÷½ÚµÄ·¶Î§ÊÇ___________________________________¡£
¢ÝÂËÔüµÄÖ÷Òª³É·ÖÊÇ____________________________________¡£
ﯲúÒµÊǼ«Óз¢Õ¹Ç±Á¦¼°Ç°¾°µÄÐÂÐ˲úÒµ£¬ï¯£¨Zr£©ÔªËØÊǺ˷´Ó¦¶ÑȼÁÏ°ôµÄ°ü¹ü²ÄÁÏ£¬¶þÑõ»¯ï¯£¨ZrO2£©¿ÉÒÔÖÆÔìÄ͸ßÎÂÄÉÃ×ÌÕ´É¡£ÎÒ¹úÓзḻµÄï¯Ó¢Ê¯£¨ZrSiO4£©£¬º¬Al2O3¡¢SiO2¡¢Fe2O3µÈÔÓÖÊ£¬Éú²úï¯Á÷³ÌÖ®Ò»ÈçÏ£º   

ÊԻشðÏÂÁÐÎÊÌ⣺
£¨1£©Ð´³öÉÏÊöÁ÷³ÌÖиßÎÂÆø»¯µÄ·´Ó¦·½³Ìʽ£¨Ì¼×ª»¯³ÉCO£©£º                    £»
£¨2£©Ð´³öZrOCl2?8H2OÔÚ900¡æÉú³ÉZrO2µÄ·´Ó¦·½³Ìʽ                       £»
£¨3£©¹ØÓÚ¶þÑõ»¯ï¯ÄÉÃ×ÌմɺÍﯺϽðµÄ˵·¨²»ÕýÈ·µÄÊÇ         £¨µ¥Ñ¡£©£»
A£®¶þÑõ»¯ï¯ÄÉÃ×ÌÕ´ÉÊÇÐÂÐÍÎÞ»ú·Ç½ðÊô²ÄÁÏ
B£®1ÄÉÃ×=10£­10Ã×
C£®ï¯ºÏ½ðµÄÓ²¶È±È´¿ï¯Òª¸ß
D£®ÈÕ±¾¸£µººËµçÕ¾µÄ±¬Õ¨¿ÉÄÜÊÇÓÉﯺϽðÔÚ¸ßÎÂÏÂÓëË®ÕôÆø·´Ó¦²úÉúµÄÇâÆø±¬Õ¨ÒýÆð
£¨4£©Ò»ÖÖÐÂÐÍȼÁϵç³Ø£¬Ò»¼«Í¨Èë¿ÕÆø£¬ÁíÒ»¼«Í¨È붡Í飻µç½âÖÊÊDzôÔÓÑõ»¯îÆ£¨Y2O3£©µÄÑõ»¯ï¯£¨ZrO2£©¾§Ì壬ÔÚÈÛÈÚ״̬ÏÂÄÜ´«µ¼O2£­¡£ÔÚÈÛÈÚµç½âÖÊÖУ¬O2£­Ïò     (ÌîÕý¸º)¼«Òƶ¯¡£µç³ØÕý¼«µç¼«·´Ó¦Îª£º                  £¬¸º¼«µç¼«·´Ó¦Îª£º                    ¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø