ÌâÄ¿ÄÚÈÝ

£¨14·Ö£©¹¤ÒµÉú²ú´¿¼îµÄ¹¤ÒÕÁ÷³ÌʾÒâͼÈçÏ£º

Íê³ÉÏÂÁÐÌî¿Õ£º
£¨1£©´ÖÑÎË®¼ÓÈë³Áµí¼ÁA¡¢B³ýÔÓÖÊ£¨³Áµí¼ÁAÀ´Ô´ÓÚʯ»ÒÒ¤³§£©£¬ÊµÑéÊÒÌá´¿´ÖÑεÄʵÑé²Ù×÷ÒÀ´ÎΪ£ºÈ¡Ñù¡¢Èܽ⡢³Áµí¡¢¡¡¡¡¡¡¡¡¡¢Õô·¢¡¢ÀäÈ´½á¾§¡¢¡¡¡¡¡¡¡¡¡¢ºæ¸É¡£
£¨2£©¹¤ÒµÉú²ú´¿¼î¹¤ÒÕÁ÷³ÌÖУ¬Ì¼Ëữʱ²úÉúµÄÏÖÏóÊÇ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£
̼ËữʱûÓÐÎö³ö̼ËáÄƾ§Ì壬ÆäÔ­ÒòÊÇ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£
£¨3£©Ì¼Ëữºó¹ýÂË£¬ÂËÒºD×îÖ÷ÒªµÄ³É·ÖÊÇ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£¨Ìîд»¯Ñ§Ê½£©£¬¼ìÑéÕâÒ»³É·ÖµÄÒõÀë×ӵľßÌå·½·¨ÊÇ£º¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£
£¨4£©°±¼î·¨Á÷³ÌÖа±ÊÇÑ­»·Ê¹Óõģ¬Îª´Ë£¬ÂËÒºD¼ÓÈëʯ»ÒÈé²úÉú°±¡£¼Óʯ»ÒË®ºóËù·¢ÉúµÄ·´Ó¦µÄÀë×Ó·½³ÌʽΪ£º¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£
£¨5£©²úÆ·´¿¼îÖк¬ÓÐ̼ËáÇâÄÆ¡£È¡a¿Ë²úÆ·ÓüÓÈÈ·Ö½âµÄ·½·¨²â¶¨´¿¼îÖÐ̼ËáÇâÄƵÄÖÊÁ¿·ÖÊý£¬³ä·Ö¼ÓÈȲ¢ÔÚ¸ÉÔïÆ÷ÖÐÀäÈ´µÃb¿Ë¹ÌÌå¡£ ´¿¼îÖÐ̼ËáÇâÄƵÄÖÊÁ¿·ÖÊý¿É±íʾΪ£º              ¡£
£¨14·Ö£©
£¨1£© ¹ýÂË       ¹ýÂË         (ÿ¿Õ1·Ö)
£¨2£©Óо§ÌåÎö³ö£¨»ò³öÏÖ»ë×Ç£©  £¨2·Ö£©Ì¼ËáÄÆÈܽâ¶È½Ï´ó£¨2·Ö£©
£¨3£©NH4Cl£¨1·Ö£©È¡Ñù£¬¼ÓÏõËáËữ£¬¼ÓÏõËáÒø£¬ÈôÓа×É«³Áµí¡£ÔòÊÇÂÈÀë×Ó¡££¨2·Ö£©
£¨4£©NH4++ OH-= NH3¡ü+ H2O£¨»ò2NH4++ Ca(OH£©2= 2NH3¡ü+ H2O+Ca2+Ò²¸ø·Ö)£¨2·Ö£©
£¨5£© [168£¨a-b£©/62a] 100©‡(Ò²¿ÉÒÔÊÇ»¯¼òºóµÄʽ×Ó)£¨3·Ö£©
£¨1£©ÊµÑéÊÒÌá´¿´ÖÑεÄʵÑé²Ù×÷ÒÀ´ÎΪ£ºÈ¡Ñù¡¢Èܽ⡢³Áµí¡¢¹ýÂË¡¢Õô·¢¡¢ÀäÈ´½á¾§¡¢¹ýÂË¡¢ºæ¸É¡£
£¨2£©¹¤ÒµÉú²ú´¿¼î¹¤ÒÕÁ÷³ÌÖУ¬Ì¼Ëữʱ²úÉúµÄÏÖÏóÊÇ£ºÓо§ÌåÎö³ö£¬Ì¼ËữʱûÓÐÎö³ö̼ËáÄƾ§Ì壬ÆäÔ­ÒòÊÇ̼ËáÄƵÄÈܽâ¶È½Ï´ó£»
£¨3£©Ì¼Ëữºó¹ýÂË£¬ÂËÒºD×îÖ÷ÒªµÄ³É·ÖÊÇ£ºNH4Cl£»¼ìÑéÕâÒ»³É·ÖµÄÒõÀë×ӵľßÌå·½·¨ÊÇ£ºÈ¡Ñù£¬¼ÓÏõËáËữ£¬¼ÓÏõËáÒø£¬ÈôÓа×É«³Áµí¡£ÔòÊÇÂÈÀë×Ó¡£
£¨4£©¼Óʯ»ÒË®ºóËù·¢ÉúµÄ·´Ó¦µÄÀë×Ó·½³ÌʽΪ£ºNH4++ OH-= NH3¡ü+ H2O£¨»ò2NH4++ Ca(OH£©2= 2NH3¡ü+ H2O+Ca2+£»
£¨5£©´¿¼îÖÐ̼ËáÇâÄƵÄÖÊÁ¿·ÖÊý¿É±íʾΪ£º[168£¨a-b£©/62a] ¡Á100©‡
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø