题目内容
.已知下列热化学方程式:
(1)CH3COOH(l)+2O2(g) ="==" 2CO2(g)+2H2O(l) △H1= -870.3 kJ·mol-1
(2)C(s)+O2(g) ="==" CO2(g) △H2= -393.5 kJ·mol-1
(3)H2(g)+O2(g) === H2O(l) △H3= -285.8 kJ·mol-1
则反应2C(s)+2H2(g)+O2(g)="==CH3COOH(l)" 的焓变△H为( )kJ·mol-1
(1)CH3COOH(l)+2O2(g) ="==" 2CO2(g)+2H2O(l) △H1= -870.3 kJ·mol-1
(2)C(s)+O2(g) ="==" CO2(g) △H2= -393.5 kJ·mol-1
(3)H2(g)+O2(g) === H2O(l) △H3= -285.8 kJ·mol-1
则反应2C(s)+2H2(g)+O2(g)="==CH3COOH(l)" 的焓变△H为( )kJ·mol-1
A.488.3 | B.-244.15 | C.244.15 | D.-488.3 |
D
已知:
①CH3COOH(l)+2O2(g)═2CO2(g)+2H2O(l)△H1=-870.3kJ/mol
②C(s)+O2(g)═CO2(g)△H2=-393.5kJ/mol
③H2(g)+O2(g) === H2O(l)△H3=-285.8kJ/mol
利用盖斯定律将②×2+③×2-①可得:
2C(s)+2H2(g)+O2(g)=CH3COOH(l);△H=2×(-393.5kJ/mol)+2×(-285.8kJ/mol)-(-870.3kJ/mol)=-488.3kJ/mol,
所以热化学方程式为2C(s)+2H2(g)+O2(g)=CH3COOH(l);△H=-488.3kJ/mol,
故答案为:2C(s)+2H2(g)+O2(g)=CH3COOH(l);△H=-488.3kJ/mol.
故选D.
①CH3COOH(l)+2O2(g)═2CO2(g)+2H2O(l)△H1=-870.3kJ/mol
②C(s)+O2(g)═CO2(g)△H2=-393.5kJ/mol
③H2(g)+O2(g) === H2O(l)△H3=-285.8kJ/mol
利用盖斯定律将②×2+③×2-①可得:
2C(s)+2H2(g)+O2(g)=CH3COOH(l);△H=2×(-393.5kJ/mol)+2×(-285.8kJ/mol)-(-870.3kJ/mol)=-488.3kJ/mol,
所以热化学方程式为2C(s)+2H2(g)+O2(g)=CH3COOH(l);△H=-488.3kJ/mol,
故答案为:2C(s)+2H2(g)+O2(g)=CH3COOH(l);△H=-488.3kJ/mol.
故选D.
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