ÌâÄ¿ÄÚÈÝ
¹¤ÒµÉϽ«ÖÆÈ¡ÖظõËá¼Ø(K2Cr2O7)ºÍ¸õËáôû(CrO3)µÄÊ£Óà·ÏÔü³ÆΪ¸õÔü£¬Æä³É·ÖΪSiO2¡¢Al2O3¡¢MgO¡¢Fe2O3¡¢CrO3¡¢K2Cr2O7µÈ¡£
ÒÑÖª£º
¢ÙÖظõËá¼ØºÍ¸õËáôû¶¼Ò×ÈÜÓÚË®£¬ÕâÊÇÔì³É¸õÎÛȾµÄÖ÷ÒªÔÒò£¬ËüÃǶ¼ÊÇÇ¿Ñõ»¯¼Á£¬¸õËáôûÈÜÓÚË®³ÊËáÐÔ£»
¢Ú£«6¼Û¸õÒ×±»ÈËÌåÎüÊÕ£¬¿ÉÖ°©£»£«3¼Û¸õ²»Ò×±»ÈËÌåÎüÊÕ£¬¶¾ÐÔС¡£
¢ÛϱíΪһЩ½ðÊôÇâÑõ»¯Îï³ÁµíµÄpH²ÎÕÕÊý¾Ý¡£
ÎïÖÊ | ¿ªÊ¼³Áµí | ÍêÈ«³Áµí |
Fe(OH)3 | 2.7 | 3.7 |
Al(OH)3 | 3.7 | 4.7 |
Cr(OH)3 | 4.7 | a |
Fe(OH)2 | 7.6 | 9.6 |
Mg(OH)2 | 9.6 | 11.1 |
»Ø´ðÏÂÁд¦Àí¸õÔü¡¢Ïû³ý¸õÎÛȾµÄÓйØÎÊÌ⣺
(1)½«¸õÔüÓÃÏ¡ÁòËá½þÈ¡¡¢¹ýÂË£¬ÔÚ½þ³öÒºÖмÓÈëÊÊÁ¿µÄÂÌ·¯(FeSO4¡¤7H2O)£¬¼ÓÈëÂÌ·¯µÄÄ¿µÄÊÇ_____________________________________________
(2)ÔÙÏò½þ³öÒºÖлºÂý¼ÓÈëÉռÖÁpH¸ÕºÃ´ïµ½4.7£¬¹ýÂË£¬ËùµÃ³ÁµíµÄ»¯Ñ§Ê½ÊÇ____________________________________________________________£»
³£ÎÂÏ£¬Cr(OH)3µÄÈܶȻýKsp£½10£32£¬ÒªÊ¹Cr3£«ÍêÈ«³Áµí[c(Cr3£«)½µÖÁ10£5 mol¡¤L£1ÊÓΪ³ÁµíÍêÈ«]£¬ÈÜÒºµÄpHÓ¦µ÷ÓÚa£½________¡£
(3)Ïò(2)Öеõ½µÄÂËÒºÖмÓÈëÁòËᣬµ÷½ÚÖÁ³ÊÇ¿ËáÐÔ£¬ËùµÃµÄÈÜÒºÊǺ¬____________________ÈÜÖʵÄÈÜÒº¡£
(1)½«¸ß¼ÛÓж¾µÄ£«6¼ÛCr»¹Ô³ÉÎÞ¶¾µÄ£«3¼ÛCr
(2)Fe(OH)3¡¢Al(OH)3¡¡5
(3)MgSO4ºÍK2SO4
½âÎö
ÀûÓ÷ϾɶÆпÌúƤ¿ÉÖƱ¸´ÅÐÔFe3O4½ºÌåÁ£×Ó¼°¸±²úÎïZnO¡£ÖƱ¸Á÷³ÌͼÈçÏ£º
ÒÑÖª£ºZn¼°Æ仯ºÏÎïµÄÐÔÖÊÓëAl¼°Æ仯ºÏÎïµÄÐÔÖÊÏàËÆ£¬Çë»Ø´ðÏÂÁÐÎÊÌ⣺
(1)ÓÃNaOHÈÜÒº´¦Àí·Ï¾É¶ÆпÌúƤµÄ×÷ÓÃÓÐ________¡£
A£®È¥³ýÓÍÎÛ | B£®Èܽâ¶Æп²ã | C£®È¥³ýÌúÐâ | D£®¶Û»¯ |
(3)ÓÉÈÜÒºBÖÆÈ¡Fe3O4½ºÌåÁ£×ӵĹý³ÌÖУ¬Ðë³ÖÐøͨÈëN2£¬ÆäÔÒòÊÇ
_______________________________________________________________
(4)Fe3O4½ºÌåÁ£×ÓÄÜ·ñÓüõѹ¹ýÂË·¨ÊµÏÖ¹ÌÒº·ÖÀ룿__________(Ìî¡°ÄÜ¡±»ò¡°²»ÄÜ¡±)£¬ÀíÓÉÊÇ________________________________¡£
(5)ÓÃÖظõËá¼Ø·¨(Ò»ÖÖÑõ»¯»¹ÔµÎ¶¨·¨)¿É²â¶¨²úÎïFe3O4ÖеĶþ¼ÛÌúº¬Á¿¡£ÈôÐèÅäÖÆŨ¶ÈΪ0.010 00 mol¡¤L£1µÄK2Cr2O7±ê×¼ÈÜÒº250 mL£¬Ó¦×¼È·³ÆÈ¡________ g K2Cr2O7(±£Áô4λÓÐЧÊý×Ö£¬ÒÑÖªMK2Cr2O7£½294.0 g¡¤mol£1)¡£ÅäÖƸñê×¼ÈÜҺʱ£¬ÏÂÁÐÒÇÆ÷Öв»±ØÒªÓõ½µÄÓÐ________(ÓñàºÅ±íʾ)¡£
¢Ùµç×ÓÌìƽ¡¡¢ÚÉÕ±¡¡¢ÛÁ¿Í²¡¡¢Ü²£Á§°ô
¢ÝÈÝÁ¿Æ¿ ¢Þ½ºÍ·µÎ¹Ü¡¡¢ßÒÆÒº¹Ü
(6) µÎ¶¨²Ù×÷ÖУ¬Èç¹ûµÎ¶¨Ç°×°ÓÐK2Cr2O7±ê×¼ÈÜÒºµÄµÎ¶¨¹Ü¼â×첿·ÖÓÐÆøÅÝ£¬¶øµÎ¶¨½áÊøºóÆøÅÝÏûʧ£¬Ôò²â¶¨½á¹û½«________(Ìî¡°Æ«´ó¡±¡¢¡°Æ«Ð¡¡±»ò¡°²»±ä¡±)¡£
ÒÑÖª25 ¡æʱ²¿·ÖÈõµç½âÖʵĵçÀëƽºâ³£ÊýÊý¾ÝÈç±íËùʾ£º
»Ø´ðÏÂÁÐÎÊÌ⣺
(1)ÎïÖʵÄÁ¿Å¨¶È¾ùΪ0.1 mol¡¤L-1µÄËÄÖÖÈÜÒº£º
a.CH3COONa b.Na2CO3 c.NaClO d.NaHCO3
pHÓÉСµ½´óÅÅÁÐ˳ÐòÊÇ (ÓñàºÅÌîд)¡£
(2)³£ÎÂÏ£¬0.1 mol/LµÄCH3COOHÈÜÒº¼ÓˮϡÊ͹ý³ÌÖУ¬ÏÂÁбí´ïʽµÄÊý¾Ý±ä´óµÄÊÇ ¡£
A£®c(H+) |
B£®c(H+)/c(CH3COOH) |
C£®c(H+)¡¤c(OH-) |
D£®c(OH-)/c(H+) |
(3)Ìå»ý¾ùΪ100 mL pH£½2µÄCH3COOHÓëÒ»ÔªËáHX£¬¼ÓˮϡÊ͹ý³ÌÖÐpHÓëÈÜÒºÌå»ýµÄ¹ØϵÈçͼËùʾ£¬ÔòHXµÄµçÀëƽºâ³£Êý (Ìî¡°´óÓÚ¡±¡¢¡°Ð¡ÓÚ¡±»ò¡°µÈÓÚ¡±)CH3COOHµÄµçÀëƽºâ³£Êý£¬ÀíÓÉÊÇ ¡£
ÏÖÓÐŨ¶È¾ùΪ0.1 mol¡¤L£1µÄÏÂÁÐÈÜÒº£º
¢ÙÁòËá¡¢¢Ú´×ËáÈÜÒº¡¢¢ÛÇâÑõ»¯ÄÆÈÜÒº¡¢¢ÜÂÈ»¯ï§ÈÜÒº¡¢¢Ý´×Ëáï§ÈÜÒº¡¢¢ÞÁòËáï§ÈÜÒº¡¢¢ßÁòËáÇâï§ÈÜÒº¡¢¢à°±Ë®£¬Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©¢Ù¡¢¢Ú¡¢¢Û¡¢¢ÜËÄÖÖÈÜÒºÖÐÓÉË®µçÀë³öµÄH£«Å¨¶ÈÓÉ´óµ½Ð¡µÄ˳ÐòÊÇ£¨ÌîÐòºÅ£©________¡£
£¨2£©¢Ü¡¢¢Ý¡¢¢ß¡¢¢àËÄÖÖÈÜÒºÖÐNH4+Ũ¶ÈÓÉ´óµ½Ð¡µÄ˳ÐòÊÇ£¨ÌîÐòºÅ£©________¡£
£¨3£©½«¢ÛºÍ¢ÜµÈÌå»ý»ìºÏºó£¬»ìºÏÒºÖи÷Àë×ÓŨ¶È¹ØϵÕýÈ·µÄÊÇ________¡£
A£®c£¨Na£«£©£½c£¨Cl££©£¾c£¨OH££©£¾c£¨NH4+£© |
B£®c£¨Na£«£©£½0.1 mol¡¤L£1 |
C£®c£¨Na£«£©£«c£¨NH4+£©£½c£¨Cl££©£«c£¨OH££© |
D£®c£¨H£«£©£¾c£¨OH££© |
25 ¡æʱ£¬µçÀëƽºâ³£Êý£º
»¯Ñ§Ê½ | CH3COOH | H2CO3 | HClO |
µçÀëƽºâ³£Êý | 1.8¡Á10£5 | K1 4.3¡Á10£7 K2 5.6¡Á10£11 | 3.0¡Á10£8 |
»Ø´ðÏÂÁÐÎÊÌ⣺
(1)ÎïÖʵÄÁ¿Å¨¶ÈΪ0.1 mol¡¤L£1µÄÏÂÁÐËÄÖÖÎïÖÊ£ºa.Na2CO3£¬b.NaClO£¬c.CH3COONa£¬d.NaHCO3£»pHÓÉ´óµ½Ð¡µÄ˳ÐòÊÇ______________(Ìî±àºÅ)£»
(2)³£ÎÂÏÂ0.1 mol¡¤L£1µÄCH3COOHÈÜÒº¼ÓˮϡÊ͹ý³Ì£¬ÏÂÁбí´ïʽµÄÊý¾ÝÒ»¶¨±äСµÄÊÇ________£»¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡
A£®c(H£«) B. C£®c(H£«)¡¤c(OH£) D.
(3)Ìå»ýΪ10 mL pH£½2µÄ´×ËáÈÜÒºÓëÒ»ÔªËáHXÈÜÒº·Ö±ð¼ÓˮϡÊÍÖÁ1 000 mL£¬Ï¡Ê͹ý³ÌpH±ä»¯Èçͼ£ºÔòHXµÄµçÀëƽºâ³£Êý________(Ìî¡°´óÓÚ¡±¡¢¡°µÈÓÚ¡±»ò¡°Ð¡ÓÚ¡±)´×ËáµÄƽºâ³£Êý£»ÀíÓÉÊÇ__________________________________________£¬Ï¡Êͺó£¬HXÈÜÒºÖÐË®µçÀë³öÀ´µÄc(H£«)________´×ËáÈÜҺˮµçÀë³öÀ´c(H£«)(Ìî¡°´óÓÚ¡±¡¢¡°µÈÓÚ¡±»ò¡°Ð¡ÓÚ¡±)ÀíÓÉÊÇ£º____________________________________£»
(4)25 ¡æʱ£¬CH3COOHÓëCH3COONaµÄ»ìºÏÈÜÒº£¬Èô²âµÃ»ìºÏÒºpH£½6£¬ÔòÈÜÒºÖÐc(CH3COO£)£c(Na£«)£½________(Ìî׼ȷÊýÖµ)¡£