题目内容
如图,A、B是反比例函数y=
(k>0)图象上的点,A、B两点的横坐标分别是a、2a,线段AB的延长线交x轴于点C,若S△AOC=6.则k=_______.


4
解:分别过点A、B作x轴的垂线,垂足分别为D、E.
则AD∥BE,AD=2BE=
,
∴B、E分别是AC、DC的中点.
∴△ADC∽△BEC,
∵BE:AD=1:2,
∴EC:CD=1:2,
∴EC=DE=a,
∴OC=3a,
又∵A(a,
),B(2a,
),
∴S△AOC=
AD×CO=
×3a×
=
=6,
解得:k=4.
则AD∥BE,AD=2BE=

∴B、E分别是AC、DC的中点.
∴△ADC∽△BEC,
∵BE:AD=1:2,
∴EC:CD=1:2,
∴EC=DE=a,
∴OC=3a,
又∵A(a,


∴S△AOC=




解得:k=4.

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