题目内容
先化简,再求值:1 |
2a |
a2-1 |
a2-2a+1 |
a2+a |
a2-2a+1 |
1 |
2 |
分析:先算除法,再通分,然后进行四则运算,最后将a=-
代入.
1 |
2 |
解答:解:原式=
-
•
=
-
=
=
.
∵a=-
,∴原式=
=
=-4.
1 |
2a |
(a+1)(a-1) |
(a-1)2 |
(a-1)2 |
a(a+1) |
=
1 |
2a |
a-1 |
a |
=
1-2a+2 |
2a |
=
3-2a |
2a |
∵a=-
1 |
2 |
3-2a |
2a |
3-2×(-
| ||
2×(-
|
点评:本题考查了分式的化简求值,解答此题的关键是把分式化到最简,然后代值计算.
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